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Gaseous States Test - 8

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Gaseous States Test - 8
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which one of the following statements is wrong for gases?

    Solution

    Mass of gas can be determined by weighing a container in which it is enclosed as follows:
    Mass of the gas = mass of the cylinder including gas - mass of empty cylinder
    So, it is a wrong statement.

     

  • Question 2
    1 / -0

    Gas equation PV = nRT is obeyed by

    Solution

    General gas equation PV = nRT is obeyed both for isothermal and adiabatic processes.

     

  • Question 3
    1 / -0

    At STP, 0.50 mole H2​ gas and 1.0 mole He gas

    Solution

    Average kinetic energy of a gaseous molecule is given by

    Ek​= 3/2 ​nRT

    The kinetic energy of gas molecule depends on temperature and number of moles.

    Rate of effusion ∝ 1/√M​​

    So, rate of effusion are equal.

     

  • Question 4
    1 / -0

    Which of the following exhibits the weakest intermolecular forces? 

    Solution

    Helium is a noble gas. Weak van der Waal's forces operate between the gaseous molecules of helium. In NH3, H2O and HCl, there is strong hydrogen bonding between the molecules.

     

  • Question 5
    1 / -0

    Mass of 112ml of oxygen at NTP on liquefaction would be:

    Solution

     

  • Question 6
    1 / -0

    The molecular weight of O2​ and SO2​ are 32 and 64, respectively. If one litre of O2​ at 150C and 750mm pressure contain 'N' molecule, the number of molecules in two litres of SO2​ under the same conditions of temperature and pressure will be:

    Solution

     

  • Question 7
    1 / -0

    A pre-weighed vessel was filled with oxygen at NTP and weighed. It was then evacuated, filled with SO2​ at the same temperature and pressure and again weighed. The weight of oxygen is ______________.

    Solution

    At constant temperature and pressure, an equal volume of gas contains an equal number of moles.

    ∴ Moles of O​ = Moles of SO2

    1 mole O​= 32 g

    1 mole SO​= 64 g

    ∴ wt of O2​ = 1/2​ that of SO2​

     

  • Question 8
    1 / -0

    Ratio of Cp​ and Cv​ of a gas 'X' is 1.4. The number of atoms of the gas 'X' present in 11.2L of it at NTP will be

    Solution

     

  • Question 9
    1 / -0

    In the ideal gas equation, the gas constant R has the dimensions of:

    Solution

     

  • Question 10
    1 / -0

    Volume occupied by an ideal gas at one atmospheric pressure and 0C is V ml. Its volume at 273 K will be

    Solution

    0C is equivalent to 273K i.e., conditions are same so volume will be V ml.

     

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