Surface Chemistry Test

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Surface Chemistry Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

The following question has four choices out of which ONLY ONE is correct.

Glycerine decreases the decomposition of

A
KClO₃

B
H₂O₂

C
Na₂SO₃

D
KMnO₄

Solution

Glycerine is an inhibitor to the decomposition of hydrogen peroxide. So, it can be used to decrease the decomposition of hydrogen peroxide.
Question 2
1 / -0

Coagulation of lyophobic colloids can be carried out by

A
boiling

B
persistent dialysis

C
electrophoresis

D
All of the above

Solution

The phenomenon of precipitation of a colloidal solution by the addition of excess of an electrolyte is called coagulation or flocculation. The coagulation of lyophobic colloidscan be carried out by the following methods:

(1) By electrophoresis: In electrophoresis, the colloidal particles move towards oppositely charged electrode. When these come in contact with the electrode for long, these are discharged and precipitated.

(2) By mixing two oppositely charged sols: When oppositely charged sols are mixed in almost equal proportions, their charges are neutralised. Both sols may be partially or completely precipitated as the mixing of ferric hydroxide (+ve sol) and arsenious sulphide (–ve sol) brings them in precipitated form. This type of coagulation is called mutual coagulation or meteral coagulation.

(3) By boiling: When a sol is boiled, the adsorbed layer is disturbed due to increased collisions with the molecules of dispersion medium. This reduces the charge on the particles and ultimately they settle down to form a precipitate.

(4) By persistent dialysis: On prolonged dialysis, the traces of electrolyte present in the sol are removed almost completely and the colloids become unstable.
Question 3
1 / -0

On adding a few drops of dilute HCl to a freshly precipitated ferric hydroxide, a red-coloured colloidal solution is obtained. This phenomenon is called

A
peptisation

B
dialysis

C
protective action

D
dissolution

Solution

Peptisation may be defined as the process of converting a precipitate into colloidal solution by shaking it with dispersion medium, in the presence of a small amount of electrolyte.
Question 4
1 / -0

Brownian motion is due to the

A
temperature fluctuation within the liquid phase

B
electrostatic interactions between charged particles

C
convection current

D
impact of solvent molecules on the colloidal particles

Solution

Brownian motion is the random motion of particles suspended in a fluid (a liquid or a gas) resulting from their collision with the quick atoms or molecules in the gas or liquid.
Question 5
1 / -0

When electricity is passed through a colloidal solution, colloidal particles conduct electricity by movement of ions in a particular direction. What is this phenomenon called?

A
Brownian movement

B
Electrophoresis

C
Electroosmosis

D
Conductivity

Solution

The student is aware that particles of colloids are electrically charged and carry positive or negative charge. So, on application of electricity by electrodes, the charged particles travel in a particular direction resulting in conduct of electricity. This process is called electrophoresis.
Question 6
1 / -0

Directions For Questions

The following question has four choices out of which ONLY ONE is correct.

...view full instructions

Ferric chloride is applied to stop bleeding due to a cut because

A
Fe³⁺ ion coagulates blood which is a negatively charged sol

B
Cl^- ion coagulates blood which is a positively charged sol

C
Fe³⁺ ion coagulates blood which is a positively charged sol

D
Cl^- ion coagulates blood which is a negatively charged sol

Solution

This is the correct option as ferric chloride is applied to stop bleeding due to a cut because Fe³⁺ion coagulates blood which is negatively charged sol.
Question 7
1 / -0

Hardy-Schulze rule explains the effect of electrolytes on the coagulation of colloidal solution. According to this rule, which of the following orders is correct for coagulation powers of the cations?

A
Ba⁺² > Na⁺ > Al⁺³

B
Al⁺³ > Na⁺ > Ba⁺²

C
Al⁺³ > Ba⁺² > Na⁺

D
Ba⁺² > Al⁺³ > Na⁺

Solution

The greater the valency, the more the coagulation of colloidal solution.
Question 8
1 / -0

Which of the following statements is wrong?

A
Elastic gels undergo imbibitions.

B
Dilution test may be applied to distinguish between water in oil and oil in water types of emulsions.

C
The higher the gold number, the greater the protective power of the lyophilic colloid.

D
Chemisorption increases with temperature to a maximum and then decreases with the further increase in the temperature.

Solution

Gold number is the minimum amount of lyophilic colloid required for protection. So, the lower the gold number, the greater the protective power.

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Surface Chemistry Test - 6

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Surface Chemistry Test - 6

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Question 1

KClO3

H2O2

Na2SO3

KMnO4

Solution

Question 2

boiling

persistent dialysis

electrophoresis

All of the above

Solution

Question 3

peptisation

dialysis

protective action

dissolution

Solution

Question 4

temperature fluctuation within the liquid phase

electrostatic interactions between charged particles

convection current

impact of solvent molecules on the colloidal particles

Solution

Question 5

Brownian movement

Electrophoresis

Electroosmosis

Conductivity

Solution

Question 6

Fe3+ ion coagulates blood which is a negatively charged sol

Cl- ion coagulates blood which is a positively charged sol

Fe3+ ion coagulates blood which is a positively charged sol

Cl- ion coagulates blood which is a negatively charged sol

Solution

Question 7

Ba+2 > Na+ > Al+3

Al+3 > Na+ > Ba+2

Al+3 > Ba+2 > Na+

Ba+2 > Al+3 > Na+

Solution

Question 8

Elastic gels undergo imbibitions.

Dilution test may be applied to distinguish between water in oil and oil in water types of emulsions.

The higher the gold number, the greater the protective power of the lyophilic colloid.

Chemisorption increases with temperature to a maximum and then decreases with the further increase in the temperature.

Solution

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KClO₃

H₂O₂

Na₂SO₃

KMnO₄

Fe³⁺ ion coagulates blood which is a negatively charged sol

Cl^- ion coagulates blood which is a positively charged sol

Fe³⁺ ion coagulates blood which is a positively charged sol

Cl^- ion coagulates blood which is a negatively charged sol

Ba⁺² > Na⁺ > Al⁺³

Al⁺³ > Na⁺ > Ba⁺²

Al⁺³ > Ba⁺² > Na⁺

Ba⁺² > Al⁺³ > Na⁺