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d and f-Block Elements Test - 14

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d and f-Block Elements Test - 14
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  • Question 1
    1 / -0

    Only One Option Correct Type

    Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

    Q. 

    Atomic number of second transition series lies from

    Solution

    Since,1st transition series belongs to 3d orbital and 2nd transition series belongs to 4d-orbital. According to the given option, atomic number 39 to 48 (5s24d1-10) belongs to second transition series.

  • Question 2
    1 / -0

    Which has lower standard reduction potential (SRP) value?

    Solution

    Mn2+/ Mn have - 1.18SRPvalue.

  • Question 3
    1 / -0

    An element has configuration 4d55s2. The element belongs to

    Solution

    Ford-block elements, group number is equal to the number of electrons in (n - 1)d subshell + number of electrons in valence shell (nth shell).

  • Question 4
    1 / -0

    The electronic configuration of palladium is

    Solution

    [Kr]4d105s0

  • Question 5
    1 / -0

    Which has lowest and highest first ionisation enthalpy in 3d series?

    Solution

    Sc (3d1 4s2)has 631 kJ mol-1 and Zn (3d10 4s2) has 906 kJ mol-1 

  • Question 6
    1 / -0

    The electronic configuration of the element which is just above the element with atomic number 42 in the same group

    Solution

    The element lying above Z = 42 has Z value 24, i.e. chromium. Hence, Cr configuration is [Ar]3d54s1

  • Question 7
    1 / -0

    Which one of the following exists in the oxidation state other than +3?

    Solution

    The correct answer is option C

    Ce exist in the oxidation state other than +3 .

     

    (a) B - Boron has +1 and +3 oxidation state.

    (b) Al - Aluminium has +1,+2 and +3 oxidation state.

    (c) Ce - Cerium has +3 and +4 oxidation state.

    (d) Ga - Gallium has +1 and +3 oxidation state.

    Cerium (Ce) have [Xe] 4f²6s² electronic configuration.

  • Question 8
    1 / -0

    Electronic configuration of a transition element X in +3 oxidation state is [Ar] 3d5 and Y in +2 state is [Ar] 3d8. What are the atom ic numbers of the elements?

    Solution

    Fe (Z = 26) in + 3 oxidation state show Fe3+ ([Ar] 3d5) configuration. Ni(28) in +2 oxidation state show Ni2+([Ar]3d8) configuration.

  • Question 9
    1 / -0

    The atomic radii of Cu and Ag are 1.17 Å and 1.34 Å. The atomic radius of gold is expected to be

    Solution

    Due to lanthanide contraction, Ag and Au have nearly same size.

  • Question 10
    1 / -0

    A red solid is insoluble in water. However, it becomes soluble if some KI is added to water. Heating the red solid in a test tube results in liberation of some violet coloured fumes and droplets of a metal appear on the cooler parts of the test tube. The red solid is  

    Solution

  • Question 11
    1 / -0

    Matching List Type

    Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

    Q. 

    Match the Column I with Column II and mark the correct option from codes given below.

    Solution

    (i) → (s), (ii) → (r), (iii) → (q), (iv) → (p)

  • Question 12
    1 / -0

    Which one of the following ions exhibits colour in aqueous solution

    Solution


  • Question 13
    1 / -0

    During the process of electrolytic refining of copper, some metals present as impurity settle as ‘anode mud’ These are

    Solution

    The correct answer is option C
    In Electrolytic refining, the impure metal is made to act as an anode. A strip of the same metal in pure form is used as a cathode. 
    They are put in a suitable electrolytic bath containing a soluble salt of the same metal. 
    The more basic metal remains in the solution and the less basic ones go to the anode mud.
    Copper is refined using an electrolytic method.
    Impurities from the blister copper deposit as anode mud which contains antimony, selenium, tellurium, silver, gold, and platinum; recovery of these elements may meet the cost of refining.

  • Question 14
    1 / -0

    Statement Type

    Direction : This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

    Q. 

    Statement I : The highest oxidation state of osmium is +8.

    Statement II : Osmium is a 5-d block element.

    Solution

    Osmium has the electronic configuration 5de6s2. As 5d and 6s are close in energy, all the 8 electron can participate in bonding. highest oxidation state of osmium is +8 due to its ability to expand their octet by using its all 8 electrons (2 from 6s and 6 from 5d).

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