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Coordination Compounds Test - 23

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Coordination Compounds Test - 23
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following species is not expected to be a ligand?

    Solution

    The correct answer is option B
    Complexes are formed when ligands donate a pair of electrons to metals. In ammonia, N atom has one lone pair of electrons. Nitrogen donates this lone pair of electrons to protons to form ammonium ion. So NH4+​ ion does not have a lone pair of electrons which it can donate to central metal ions. Hence it cannot behave as a ligand.

  • Question 2
    1 / -0

    A complex cation is formed by Pt(in some oxidation state) with ligands (in proper number so that coordination number of Pt becomes six). Which of the following can be its correct IUPAC name?

    Solution

    (A) [Pt(en)(SCN)2 (NH3)2]0 ; it is not ion
    (B) [Pt(en)(SCN)2 (NH3)2]2+ ; it should not be platinate
    (C) correct name
    (D) [Pt(en)2(SCN)2(NH3)2]2+ ; its co-ordination number = 8

  • Question 3
    1 / -0

    Which of the following is not correctly matched?

    Solution

    Sodium(ethylenediaminetetraacetato)chromate(II) and Na2​[Cr(CH3​COO)4​(en)] are not correctly matched.
    Sodium(ethylenediaminetetraacetato)chromate(II) is the name of the coordiation compound having formula Na2​[Cr(edta)]
    The name of the compound Na2​[Cr(CH3​COO)4​(en)] is sodium tetraacetato(ethylenediamine)chromate(II).

  • Question 4
    1 / -0

    The EAN of metal atoms in [Fe(CO2)(NO+)2] and Co2(CO8) respectively are:

    Solution

    Oxidation state of iron in [Fe-2(CO0)2 (NO+)2] = x+2(0) + 2 = 0; x= -2

    So EAN = 28 =8=36

    Oxidation state of cobalt in Co2(CO)8 = 2x + 8 (-8) = x=0

    So Ean = 27 + 1+ 8 = 36

  • Question 5
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    Match the complex ions listed in column-I with the characteristics listed in column-II using the codes given below.

    Solution

  • Question 6
    1 / -0

    Which of the following statements is correct?

    Note : NO is three electrons donor

    Solution

  • Question 7
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    All the following complex ions are found to be paramagnetic
    P : [FeF6]3- ; Q : [COF6] 3- ; R : [V(H2O)6] 3+ ; S : [Ti(H2O)6]3+
    The correct order of their paramagnetic moment (spin only) is

    Solution

  • Question 8
    1 / -0

    Among [NiCl2 (PPh3)2], [Ni(HDMG)2] and [Ni(CO)4] complexes the hybridisation statesof Ni atom are respectively.

    Solution

  • Question 9
    1 / -0

    Amongst [Co(ox)3]3- , [CoF6]3- and [Co(NH3)6]3+

    Solution

  • Question 10
    1 / -0

    All the following complexes show decrease in their weights when placed in a magnetic
    balance then the group of complexes having tetrahedral geometry is:
    (i) Ni(CO)4

    (ii) K[AgF4]

    (iii) Na2[Zn(CN)4]

    (iv) K2[PlCl4]

    ( v )[RhCl(PPh3)3]

    Solution

  • Question 11
    1 / -0

    The ‘brown ring’ formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+. Which of the following statements are correct for this complex [u = 3.87 B.M.)
    (i) Oxidation state of Fe is +1 and NO exists as NO+.
    (ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridisation.
    (iii) The complex is paramagnetic and has three unpaired electrons due to transfer of  electron from NO to Fe2+.
    (iv) The complex is in octahedral geometry as attained by d2sp3 hybridisation.
    (v) The brown colour of the complex is attributed to d-d transition of electron.

    Solution

  • Question 12
    1 / -0

    Which of the following statements is most likely to be incorrect?

    Solution

  • Question 13
    1 / -0

    Identify the correct order of wavelength of light absorbed for the following complex ions.

    Solution

  • Question 14
    1 / -0

    The possible geometric isomers shown by [Co(en)Br2Cl2]- is:

    Solution

  • Question 15
    1 / -0

    The total number of isomers of the complex, [Co(NH3)4(NO2) 2(NO3) complex is :

    Solution

  • Question 16
    1 / -0

    Which of the following has both face-mer and optical isomers?

    Solution

  • Question 17
    1 / -0

    Statement–1 : In complex [Cr(NH3)4 BrCl]Cl, the ‘spin only’ magnetic moment is close to 1.73 B.M.
    Statement–2 : All known mononuclear complexes of chromium(III), irrespective of the strength of the ligand field, must have three unpaired electrons.

    Solution

  • Question 18
    1 / -0

    Statement–1 : The magnitude of for a given ligand increases as the charge on he metal ion increases.
    Statement–2 : NH3 is a weak field ligand towards Co2+ but acts as a strong field ligand towards Co3+.

    Solution

    As metal ion charge increases the ligands are drawn closer to the metal ion because
    of its increased charge density. As the ligands move closer, they cause greater splitting of tghe d-orbital, there by producing a large Δ value.

  • Question 19
    1 / -0

    Statement–1 : tris (ethane-1, 2 – diamine)nickel(II) chloride is homoleptic outer orbital complex
    Statement–2 : The geometry of Ni in tris (ethane-1, 2 – diamine)nickel(II) chloride is trigonal bipyramidal

    Solution

  • Question 20
    1 / -0

    Statement–1 : [Ni (H2O)6]2+ is green but a solution of [Ni(CN)4]2- is colourless.
    Statement–2 : Energy difference between d levels (i.e. ) for H2 O complex (paramagnetic) is in the visible region and that for the cyano complex (diamagnetic) is in the UV region

    Solution

    Cyanide is stronger ligand than water. It causes much higher crystal field splitting. Energy difference between d levels (i.e.)for [Ni(H2O)6]2+ complex (paramagnetic) is in the visible region and that for the [Ni(CN4)]2 complex (diamagnetic) is in the UV region.
    Hence, [Ni(H2O)6]2+ forms green color solution whereas [Ni(CN4)]2 forms colorless solution.
     

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