Coordination Compounds Test

Result

Coordination Compounds Test - 24

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Question 1
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Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
Q.
Among the following complexes the one which shows zero crystal field stabilisation energy is

A
[Co(H₂O)₆]²⁺

B
[Co(H₂O)₆]³⁺

C
[Mn(H₂O)₆]³⁺

D
[Fe(H₂O)₆]³⁺

Solution

In [Fe(H₂O)₆]³⁺, iron has 3d⁵ configuration. Since, H₂O is weak ligand the distribution is .
Hence, CFSE = - 3 x 0.4 + 2 x 0.6 = 0.0
Question 2
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The wavelength of light absorbed is highest in

A
[Co(NH₃)₅CI]²⁺

B
[Co(NH₃)₅H₂O]³⁺

C
[Co(NH₃)₆]³⁺

D
[Co(en)₃]³⁺

Solution

Among all the coordination aforesaid in complex [Co(NH₃)₅Cl]²⁺ unpaired electrons are present with the central element cobalt so it required less energy for excitation. Thus, the wavlength of light absorbed will be the highest.
Question 3
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The CFSE for octahedral [CoCI₆]^4- is 18000 cm^-1. Then the CFSE for tetrahedral [CoCI₄]^2- will be

A
18000cm^-1

B
16000cm^-1

C
8000cm^-1

D
20000cm^-1

Solution

CFSE for [CoCI₄]^2- will be
i.e. = 8000cm^-1
Question 4
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The crystal field splitting energy (Δ_o) of
I. [CoBr₆]^3- II. [CoF₆]^3-
III. [Co(NCS)₆]^3- IV. [Co(CN)₆]^3- is in the order of

A
I < II < III < IV

B
II < IV < I < III

C
Ill < I < IV < II

D
IV < III < II < I

Solution

Crystal field splitting energy depends on strength of ligand. Strong ligands have more value of CFSE (Δ_o).
Hence, Br^- < F^- < NCS < CN^-
Question 5
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A magnetic moment of 1.73 BM will be shown by one among the following

A
[Cu(NH₃)₄]²⁺

B
[Ni(CN)₄]^2–

C
TiCl₄

D
[CoCl₆]^4–

Solution

The correct answer is Option A.
Electronic configuration of Cu²⁺ ion in [Cu(NH₃)₄]²⁺.
Cu²⁺ ion =[Ar]3d⁹4s⁰.
∴Cu²⁺ ion has one unpaired electron.
Magnetic moment of [Cu(NH₃)₄]²⁺ (μ) = BM
where, n = no. of unpaired electrons

Whereas Ni²⁺ in [Ni(CN)₄]²⁻ , Ti⁴⁺ in TiCl₄ and Co²⁺ ion [COCl₆]⁴⁻ has 2,0 and 3 unpaired electrons respectively.
Question 6
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The correct order o f ligand field strength is

A
H₂O < Cl^- < CO < NH₃

B
CO < NH₃ < Cl^- < H₂O

C
H₂O < CO < NH₃ < Cl^-

D
Cl^- < H₂O < NH₃ < CO
Question 7
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The crystal field splitting energies (CFSE) of high spin and low spin d⁶ metal complexes in octahedral complex in terms of Δ_o respectively are

A
-0.4 and -2.4

B
-2.4 and -0.4

C
-0.4 and 0.0

D
-2.4 and 0.0

Solution

For high spin d⁶, CFSE = - 4 x 0.4 + 2 x 0.6 = -0.4
For low spin d⁶, CFSE= - 6 x 0.4 = -2.4
Question 8
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The Δ_t of the following complexes follows the order
I. [CoCI₄]^2-
II. [CoBr₄]^2-
III. [Co(NCS)₄]^2-

A
Ill > I > II

B
I > II > III

C
II > I > III

D
Ill > II > I

Solution

Correct Answer :- d
Explanation : Bonding Energy :
[CoCI₄]² -2084.67
[CoBr₄]² -3139.39
[Co(NCS)₄]^2- - 8559.48
Correct order is : III > II > I
Question 9
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In which of the following coordination entities, the magnitude Δ_o (CFSE in octahedral field) will be maximum ?

A
[Co(H₂O)₆]³⁺

B
[Co(NH₃)₆]³⁺

C
[Co(CN)₆]^3-

D
[Co(C₂O₄)^3-

Solution

Increasing order of ligand field strength
l^- < Br^- < SCN^- < CI^- < S^2- < F^- < OH^-< H₂O < NCS^- < edta^4- < NH₃ < en < CN^- < CO
Question 10
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The increasing order of wavelength of absorption for the complex ions
I. [Cr(NH₃)₆]³⁺
II. [CrCI₆]^3-
III. [Cr(H₂O)₆]³⁺
IV. [Cr(CN)₆]^3-
is :

A
IV < I < III < II

B
IV < III < II < I

C
IV < II < III < I

D
II < III < I < IV

Solution

Stronger ligand causes greater splitting between two energy levels.
The energy of light absorbed is more and the wavelength of light absorbed is less for the stronger ligand.
Hence order of wavelength absorption will be reverse of the order of the strength of ligands.
Hence A is correct.
Question 11
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Matching List Type
Direction (Q. No. 11-12) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d) out of which one is correct.
Q.
Match the Column I with Column II and mark the correct option from the codes given below.

A
a

B
b

C
c

D
d

Solution

(i) → (r), (ii) → (s), (iii) → (q), (iv) → (p)
Question 12
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Match the Column I with Column II and mark the correct option from the codes given below.

A
a

B
b

C
c

D
d

Solution

(i) → (q), (ii) → (p,s), (iii) → (r,t), (iv) → (s)
Question 13
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Statement Type
Direction (Q. No. 13) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.
Q.
Statement I : The value of CFSE for the octahedral complex [Co(NH₃)₆]³⁺ is - 2.4Δ_o.
Statement II : The ammonia molecule is strong field ligand.

A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

In [Co(NH₃)₆]³⁺ Co, have d⁶ configuration and NH₃ is strong field ligand.

CFSE_(OCt) = -0.4 x 6 + 0.6 x 0 = -2.4Δ_o