Coordination Compounds Test

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Coordination Compounds Test - 27

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Weekly Quiz Competition

Question 1
1 / -0

Read the passage given below and answer the following questions:
The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH₃ and H₂O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, [Co(NH₃)₆]³⁺, [Co(CN)₆]³⁻, [Co(H₂O)₆]³⁺

A
A. [Co(CN)₆]³⁻ > [Co(NH₃)₆]³⁺ > [Co(H₂O)₆]³⁺

B
B. [Co(NH₃)₆]³⁺ > [Co(H₂O)₆]³⁺ > [Co(CN)₆]³⁻

C
C. [Co(H₂O)₆]³⁺ > [Co(NH₃)₆]³⁺> [Co(CN)₆]³⁻

D
D. [Co(CN)₆]³⁻> [Co(NH₃)₆]³⁺> [Co(H₂O)₆]³⁺

Solution

[Co(H₂O)₆]³⁺ > [Co(NH₃)₆]³⁺> [Co(CN)₆]³⁻
Question 2
1 / -0

Read the passage given below and answer the following questions:
The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH₃ and H₂O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. An aqueous pink solution of cobalt(II) chloride changes to deep blue on addition of excess of HCl. This is because _____________.

A
A. [Co(H₂O)₆]²⁺ is transformed into [CoCl₆]⁴⁻

B
B. [Co(H₂O)₆]²⁺ is transformed into [CoCl₄]²⁻

C
C. tetrahedral complexes have larger crystal field splitting than octahedral complex.

D
D. None of the above

Solution

[Co(H₂O)₆]²⁺ is transformed into [CoCl₄]²⁻.
Question 3
1 / -0

Read the passage given below and answer the following questions:
The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH₃ and H₂O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. The CFSE for octahedral [CoCl₆]⁴⁻ is 18,000 cm⁻¹. The CFSE for tetrahedral [CoCl₄]²⁻ will be

A
A. 18,000 cm⁻¹

B
B. 16,000 cm⁻¹

C
C. 8,000 cm⁻¹

D
D. 20,000 cm⁻¹

Solution
Question 4
1 / -0

Read the passage given below and answer the following questions:
The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH₃ and H₂O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. A chelating agent has two or more than two donor atoms to bind to a single metal ion. Which of the following is not a chelating agent?

A
A. thiosulphato

B
B. oxalato

C
C. glycinato

D
D. ethane-1,2-diamine

Solution

Thiosulphato is a monodentate ligand whereas Oxalato, glycinato and ethylene diamine are bidentate ligands and can form rings with the central metal ion. So, they are also chelating ligands. Thiosulphato is a monodentate ligand and hence, cannot form chelate rings. Hence, it is not a chelating ligand
Question 5
1 / -0

Read the passage given below and answer the following questions:
According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion (A): In the diamagnetic octahedral complex, [Co(NH₃)₆]³⁺, the cobalt ion is in +3 oxidation state.
Reason (R): Six pairs of electrons, one from each NH₃ molecule, occupy the six hybrid orbitals.

A
A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B
B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C
C. Assertion is correct statement but reason is wrong statement

D
D. Assertion is wrong statement but reason is correct statement.

Solution

In the diamagnetic octahedral complex, [Co(NH₃)₆]³⁺, the cobalt ion is in +3 oxidation state and has the electronic configuration 3d⁶.
Question 6
1 / -0

Read the passage given below and answer the following questions:
According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion (A): [NiCl₄]²⁻ is an inner orbital complex.
Reason (R): An inner orbital or low spin or spin paired complex uses inner d orbitals of the metal ion for hybridisation.

A
A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B
B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C
C. Assertion is correct statement but reason is wrong statement

D
D. Assertion is wrong statement but reason is correct statement.

Solution

[NiCl₄]²⁻ is high spin complex.
Question 7
1 / -0

Read the passage given below and answer the following questions:
According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion (A): In the square planar complexes, the hybridisation involved is dsp².
Reason (R): In [Ni(CN)₄]²⁻. Here nickel is in +2 oxidation state and has the electronic configuration 3d⁸.

A
A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B
B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C
C. Assertion is correct statement but reason is wrong statement

D
D. Assertion is wrong statement but reason is correct statement.

Solution

The dsp²hybrid orbitals are inner orbital complexes in which the electrons get paired up due to the presence of a strong field ligand. So, the electron pairs of the ligands occupy one d orbital, one s orbital and then 2p orbitals in a square planar geometry.
The 2s orbital is mixed with all three of the 2p orbitals, creating four hybridized sp³ orbitals. Each of these has 25% s and 75% p character; electron repulsion favours a tetrahedral shape, so the orbitals are 109.5° apart from each other.
Question 8
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Read the passage given below and answer the following questions:
According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion (A): The paramagnetic octahedral complex, [CoF₆]³⁻ uses outer orbital (4d) in hybridisation (sp³d²).
Reason (R): It is a high spin complex.

A
A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B
B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C
C. Assertion is correct statement but reason is wrong statement

D
D. Assertion is wrong statement but reason is correct statement.

Solution

The paramagnetic octahedral complex, [CoF₆]³⁻ uses outer orbital (4d) in hybridisation (sp³d²). It is a low spin complex.
Question 9
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Read the passage given below and answer the following questions:
The existence of coordination compounds with the same formula but different arrangements of the ligands was crucial in the development of coordination chemistry. Two or more compounds with the same formula but different arrangements of the atoms are called isomers. Isomers are compounds with the same molecular formula but different structural formulas and do not necessarily share similar properties. There are many different classes of isomers, like stereoisomers, enantiomers, and geometrical isomers. There are two main forms of isomerism: structural isomerism and stereoisomerism. The different chemical formulas in structural isomers are caused either by a difference in what ligands are bonded to the central atoms or how the individual ligands are bonded to the central atoms.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. What kind of isomerism exists between [Cr(H₂O)₆]Cl₃ (violet) and [Cr(H₂O)₅Cl]Cl₂.H₂O (greyish green)?

A
A. linkage isomerism

B
B. solvate isomerism

C
C. ionisation isomerism

D
D. coordination isomerism

Solution

Solvate (or hydrate) isomerism exists between [Cr(H₂O)₆]Cl₃ (violet) and [Cr(H₂ O)₅Cl]Cl₂.H₂O (greyish-green).
For [Cr(H₂O)₆]Cl₃(violet), the number of water molecules inside the coordination sphere is six and the number of water molecules outside the coordination sphere is 0.
For, [Cr(H₂O)₅Cl]Cl₂.H₂O (greyish-green), the number of water molecules inside the coordination sphere is five and the number of water molecules outside the coordination sphere is one.
Question 10
1 / -0

Read the passage given below and answer the following questions:
The existence of coordination compounds with the same formula but different arrangements of the ligands was crucial in the development of coordination chemistry. Two or more compounds with the same formula but different arrangements of the atoms are called isomers. Isomers are compounds with the same molecular formula but different structural formulas and do not necessarily share similar properties. There are many different classes of isomers, like stereoisomers, enantiomers, and geometrical isomers. There are two main forms of isomerism: structural isomerism and stereoisomerism. The different chemical formulas in structural isomers are caused either by a difference in what ligands are bonded to the central atoms or how the individual ligands are bonded to the central atoms.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. Due to the presence of ambidentate ligands, coordination compounds show isomerism. Palladium complexes of the type [Pd(C₆H₅)₂(SCN)₂] and [Pd(C₆H₅)₂(NCS)₂] are

A
A. linkage isomers

B
B. coordination isomers

C
C. ionisation isomers

D
D. geometrical isomers

Solution

Linkage isomerism arises in a coordination compound containing ambidentate ligand. A simple example is by complexes containing the thiocyanate ligand, NCS−, which may bind through the nitrogen to give M−NCS or through sulphur to give M−SCN.
Question 11
1 / -0

Read the passage given below and answer the following questions:
The existence of coordination compounds with the same formula but different arrangements of the ligands was crucial in the development of coordination chemistry. Two or more compounds with the same formula but different arrangements of the atoms are called isomers. Isomers are compounds with the same molecular formula but different structural formulas and do not necessarily share similar properties. There are many different classes of isomers, like stereoisomers, enantiomers, and geometrical isomers. There are two main forms of isomerism: structural isomerism and stereoisomerism. The different chemical formulas in structural isomers are caused either by a difference in what ligands are bonded to the central atoms or how the individual ligands are bonded to the central atoms.
The following questions are multiple choice questions. Choose the most appropriate answer:
Q. Which of the following complexes show linkage isomerism?

A
A. [Co(H₂O)₅CO]³⁺

B
B. [Cr(NH₃)₅SCN]²⁺

C
C. [Fe(en)₂Cl₂]⁺

D
D. All of the above

Solution

Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand. Typical ligands that give rise to linkage isomers are: thiocyanate, SCN −, isothiocyanate, NCS −
Question 12
1 / -0

Read the passage given below and answer the following questions:
Coordination compounds are formulated and named according to the IUPAC system.
Few rules for naming coordination compounds are:
(I) In an ionic complex, the cation is named first and then the anion.
(II) In the coordination entity, the ligands are named first and then the central metal ion.
(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge
The following questions are multiple choice question. Choose the most appropriate answer:
Q. The IUPAC name of [Ni(CO)₄] is

A
A. tetracarbonylnickel(II)

B
B. tetracarbonylnickel(0)

C
C. tetracarbonylnickelate(II)

D
D. tetracarbonylnickelate(0)

Solution

When we write the IUPAC name for a coordination complex, if the coordination entity is neutral, then the name of Ligands comes first followed by the name of the metal and the oxidation state in ().
Thus, the IUPAC name for [Ni(CO)₄] is Tetracarbonylnickel (0).
Question 13
1 / -0

Read the passage given below and answer the following questions:
Coordination compounds are formulated and named according to the IUPAC system.
Few rules for naming coordination compounds are:
(I) In an ionic complex, the cation is named first and then the anion.
(II) In the coordination entity, the ligands are named first and then the central metal ion.
(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge
The following questions are multiple choice question. Choose the most appropriate answer:
Q. The IUPAC name of the complex [Pt(NH₃)₃Br(NO₂)Cl]Cl is

A
A. triamminechlorobromonitroplatinum(IV) chloride

B
B. triammine bromo nitro chloro platinum(IV) chloride

C
C. triammine bromidochloronitro platinum(IV) chloride

D
D. triammine nitro chloro bromo platinum(IV) chloride

Solution

We need to follow the alphabetical order while naming the compound. The oxidation number of metal is +4.
Hence the IUPAC name is- Triamminebromochloronitroplatinum (IV) chloride.
Question 14
1 / -0

Read the passage given below and answer the following questions:
Coordination compounds are formulated and named according to the IUPAC system.
Few rules for naming coordination compounds are:
(I) In an ionic complex, the cation is named first and then the anion.
(II) In the coordination entity, the ligands are named first and then the central metal ion.
(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge
The following questions are multiple choice question. Choose the most appropriate answer:
Q. Which of the following represents the correct formula of dichloridobis(ethane-1,2-diamine)cobalt(III) ion?

A
A. [CoCl₂(en)]²⁺

B
B. [CoCl2(en)2]²⁺

C
C. [CoCl2(en)]⁺

D
D. [CoCl₂(en)₂]⁺
Question 15
1 / -0

Read the passage given below and answer the following questions:
Coordination compounds are formulated and named according to the IUPAC system.
Few rules for naming coordination compounds are:
(I) In an ionic complex, the cation is named first and then the anion.
(II) In the coordination entity, the ligands are named first and then the central metal ion.
(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge
The following questions are multiple choice question. Choose the most appropriate answer:
Q. As per IUPAC nomenclature, the name of the complex [Co(H₂O)₄(NH₃)₂]Cl₃ is

A
A. tetra aqua diamine cobalt(II) chloride

B
B. tetra aqua diamine cobalt(III) chloride

C
C. diammine tetraaqua cobalt(II) chloride

D
D. diammine tetraaqua cobalt(III) chloride

Solution

The IUPAC name of the complex given is Diamminetetraaquacobalt (III) chloride. The charge on the central Co atom is +3.

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Coordination Compounds Test - 27

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Coordination Compounds Test - 27

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Question 1

A. [Co(CN)6]3− > [Co(NH3)6]3+ > [Co(H2O)6]3+

B. [Co(NH3)6]3+ > [Co(H2O)6]3+ > [Co(CN)6]3−

C. [Co(H2O)6]3+ > [Co(NH3)6]3+> [Co(CN)6]3−

D. [Co(CN)6]3−> [Co(NH3)6]3+> [Co(H2O)6]3+

Solution

Question 2

A. [Co(H2O)6]2+ is transformed into [CoCl6]4−

B. [Co(H2O)6]2+ is transformed into [CoCl4]2−

C. tetrahedral complexes have larger crystal field splitting than octahedral complex.

D. None of the above

Solution

Question 3

A. 18,000 cm−1

B. 16,000 cm−1

C. 8,000 cm−1

D. 20,000 cm−1

Solution

Question 4

A. thiosulphato

B. oxalato

C. glycinato

D. ethane-1,2-diamine

Solution

Question 5

A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C. Assertion is correct statement but reason is wrong statement

D. Assertion is wrong statement but reason is correct statement.

Solution

Question 6

A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C. Assertion is correct statement but reason is wrong statement

D. Assertion is wrong statement but reason is correct statement.

Solution

Question 7

A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C. Assertion is correct statement but reason is wrong statement

D. Assertion is wrong statement but reason is correct statement.

Solution

Question 8

A. Assertion and reason both are correct statements and reason is correct explanation for assertion.

B. Assertion and reason both are correct statements but reason is not correct explanation for assertion.

C. Assertion is correct statement but reason is wrong statement

D. Assertion is wrong statement but reason is correct statement.

Solution

Question 9

A. linkage isomerism

B. solvate isomerism

C. ionisation isomerism

D. coordination isomerism

Solution

Question 10

A. linkage isomers

B. coordination isomers

C. ionisation isomers

D. geometrical isomers

Solution

Question 11

A. [Co(H2O)5CO]3+

B. [Cr(NH3)5SCN]2+

C. [Fe(en)2Cl2]+

D. All of the above

Solution

Question 12

A. tetracarbonylnickel(II)

B. tetracarbonylnickel(0)

C. tetracarbonylnickelate(II)

D. tetracarbonylnickelate(0)

Solution

A. [Co(CN)₆]³⁻ > [Co(NH₃)₆]³⁺ > [Co(H₂O)₆]³⁺

B. [Co(NH₃)₆]³⁺ > [Co(H₂O)₆]³⁺ > [Co(CN)₆]³⁻

C. [Co(H₂O)₆]³⁺ > [Co(NH₃)₆]³⁺> [Co(CN)₆]³⁻

D. [Co(CN)₆]³⁻> [Co(NH₃)₆]³⁺> [Co(H₂O)₆]³⁺

A. [Co(H₂O)₆]²⁺ is transformed into [CoCl₆]⁴⁻

B. [Co(H₂O)₆]²⁺ is transformed into [CoCl₄]²⁻

A. 18,000 cm⁻¹

B. 16,000 cm⁻¹

C. 8,000 cm⁻¹

D. 20,000 cm⁻¹

A. [Co(H₂O)₅CO]³⁺

B. [Cr(NH₃)₅SCN]²⁺

C. [Fe(en)₂Cl₂]⁺

A. [CoCl₂(en)]²⁺

B. [CoCl2(en)2]²⁺

C. [CoCl2(en)]⁺

D. [CoCl₂(en)₂]⁺