Coordination Compounds Test

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Coordination Compounds Test - 19

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Question 1
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Only One Option Correct Type
Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
Q.
Tris (ethylenediamine) cobalt (III) cation, [Co(en)₃]³⁺ can have

A
three stereoisomers, all chiral and optically active

B
two chiral stereoisomers (enantiomers ) and one achiral

C
three stereoisomers, all achiral

D
two stereoisomers, both achiral

Solution

Optical isomers have mirror images that cannot be superimposed on one another. These are called as enantiomers. The molecules or ions that cannot be superimposed are called chiral.
Question 2
1 / -0

Which of the following types of octahedral complexes will exhibit geometrical isomerism (where, M = metal, a, b = achiral ligands)?

A
[Ma₆]

B
[Ma₅b]

C
[Ma₄b₂]

D
[M(aa)₃]

Solution

Octahedral complexes of formula [Ma₄b₂] in which the two ligands b may be oriented cis or trans to each other, e.g.
Geometrical isomers (cis and trans) of [Co(NH₃)₄CI₂]⁺.
Question 3
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Which of the following can exhibit linkage isomerism?

A

B
H₂O

C
NH₃

D
H₂NCH₂CH₂NH₂

Solution

Ligand which can ligate through two different atoms is called ambidentate ligand. NO₂^- ion can coordinate either through nitrogen or through oxygen to a central metal atom/ion.

Hence, ligand show linkage isomerism, e.g. the complex [Co(NH₃)₅(NO₂)]CI₂ which is obtained as the red form, in which the nitrite ligand is bound through oxygen (—ONO) and as the yellow form, in which the nitrite ligand is bound through nitrogen (— NO₂).
Question 4
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What type of isomerism is shown by [Co(NH₃)₄Br₂]Cl?

A
Geometrical only

B
Ionisation only

C
Geometrical and ionisation

D
Ionisation and optical

Solution

The complex [Co(NH₃)₄Br₂]CI show geometrical and ionisation isomerism.
Question 5
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Which of the following does not show optical isomerism?

A
[Co(en)₃]³⁺

B
[Co(en)₂CI₂]⁺

C
[Co(NH₃)₃CI₃]

D
[Co(en)(NH₃)₂CI₂]⁺

Solution

Due to symmetry in the complex [Co(NH₃)₃CI₃], it failed to show optical isomerism. The type of coordination entity show fac and mer isomerism or geometrical isomerism.

The facial (fac) and meridional (mer) isomers of [Co(NH₃)₃CI₃].
Question 6
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The ionisation isomer of [Cr(H₂O)₄ CI(NO₂)]CI is

A
[Cr(H₂O)₄(O₂N)]Cl₂

B
[Cr(H₂O)₄CI₂] (NO₂)

C
[Cr(H₂O)4CI (ONO)]CI

D
[Cr(H₂O)₄CI₂ (NO₂)] . H₂O

Solution

Ionisation isomerism is due to the exchange of groups between the complex ion and the ions outside it, e.g. [Cr(H₂O)₄CI(NO₂)CI] and [Cr(H₂O)₄CI₂]NO₂ show ionisation isomerism.
Question 7
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Which of the following complex species is not expected to exhibit optical isomerism?

A
[Co(en)₃]³⁺

B
[Co(en)₂CI₂]⁺

C
[CoNH₃Cl₃]

D
[Co(en)(NH₃)₂CI₂]⁺

Solution

[CoNH₃CI₃] do not exhibit optical isomerism. Optical isomerism is shown by M(AA)₂X₂ type, M(AA)₃ type , [M(AA) B₂X₂] type complexes containing hexadentate ligand and ML_a L_b L_c L_dLeft type.
Question 8
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The complex [Co(NH₃)₆[Cr(C₂O₄)₃] and [Cr(NH₃)₆[Co(C₂O₄)₃] exhibit

A
coordination isomerism

B
geometrical isomerism

C
ionisation isomerism

D
linkage isomerism

Solution

Coordination isomerism is possible when both positive and negative ions of a salt are complex ions and two isomers differ in distribution of ligands in the cation and the anion.
Question 9
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Which of the following exhibit cis-trans isomerism?

A
[PtCI₂(NH₃)₂]

B
[PdCl₂BrI]

C
[Pt(NH₃) (py)(Cl) (Br)]

D
All of these

Solution

All the three compounds, i.e. [PtCI₂(NH₃)₂], [PdCl₂Brl] and [Pt(NH₃)(py)(CI)(Br)] exhibit cis and trans isomerism.
Question 10
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Which of the following is considered to be an anticancer species?

A

B

C

D

Solution

cis platin is used as ananticancer drug.
Question 11
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Matching List Type
Direction (Q, Nos. 11 and 12) Choices for the correct combination o f elements from Column I and Column II are given as options (a), (b), (c) and (d) out of which one is correct.
Q.
Match the Column ! with Column II and mark the correct option from the codes given below.

A
a

B
b

C
c

D
d

Solution

[Co(NH₃)₄CI₂]⁺ exhibits geometrical isomerism.
cis-[Co(en)₂CI₂]⁺ because of the absence of symmetry elements exhibit optical isomerism.
[Co(NH₃)₅(NO₂)]CI₂ because of the presence of ambidentate (NO₂) ligand exhibit linkage isomerism. [Co(NH₃)₆][Cr(CN₎6] exhibits coordination isomerism because here, cation and anion both are complex.
(i) → (s), (ii) →(p), (iii) → (t), (iv) → (r)
Question 12
1 / -0

Match the Column I with Column II and mark the correct option from the codes given below.

A
a

B
b

C
c

D
d

Solution

(i) → (r,s), (ii) → (p,q,t), (iii) → (p,q,t), (iv) → (r,s)
Question 13
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Statement Type
Direction: This section is based on Statement I and Statement II. Select the correct answer from the codes given below.
Q.
Statement I : Complexes of MX₆ and MX₅L type do not show geometrical isomerism. Assume that X and L are unidentate.
Statement Il : Geometrical isomerism is not shown by complexes of coordination number 6.

A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

MX₆ and MX₅L type complexes do not exhibit geometrical isomerism, cis [Co(en)₂CI₂]⁺ because of the absence of symmetry elements exhibit optical isomerism.
[Co(NH₃)₅(NO₂)]CI₂ because of the presence of ambidentate (NO₂) ligand exhibit linkage isomerism. [CoNH₃)₆][Cr(CN)₆] exhibits coordination isomerism because here cation and anion both are complex.