Self Studies
Selfstudy
Selfstudy

Qualitative Analysis Test - 3

Result Self Studies

Qualitative Analysis Test - 3
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    Consider following compounds and decide as to which of the following statements are true ?

    Solution

     

  • Question 2
    1 / -0

    The Prussian blue colour obtained during the test of nitrogen by Lassaigne's test is due to the formation of-

    Solution

    Hint: Ferriferrocyanide is obtained as product.

    The reaction takes place in Lassaigne's test are as follows:

     

  • Question 3
    1 / -0

    A compound that does not give a positive test in Lassaigne’s test for nitrogen is:-

    Solution

    Hint: Molecule must contain C-N bond

    When a compound containing CN bond reacts with sodium metal then it will form NaCN as a product. If the molecule does not contain a C-N bond then NaCN is not possible.

    The structures of given compounds are as follows:

    So, Hydrazine H2N-NH2 does not contain a C-N bond, hence, it will not give Lassaigne’s test.

     

  • Question 4
    1 / -0

    The silver sulphate solution is used to separate:

    Solution

     

  • Question 5
    1 / -0

    Soda extract is prepared by-

    Solution

    Hint: The process to prepare soda extract is as follows:

    To prepare soda extract, mixture/salt is mixed with pure Na2CO3 in 1 : 2 ratio and a sufficient amount of water are added. The whole content is boiled for 15-20 minutes and then filtered. The filtrate is used as soda extract.

    The reaction is as follows:

    (a) Some cations interfere in the confirmatory test of some anions when present in solution. Such cations are eliminated in the form of insoluble carbonates as a result of treatment with sodium carbonate.

    (b) It becomes easier to identify anions in such mixture which are insoluble in water and dil. acids.

     

  • Question 6
    1 / -0

    The Lassaigne's extract is boiled with a concentration HNO3 while testing for halogens. By doing so it

    Solution

    Hint: H2S is gas and HCN boiling point is 26 oC

    Actually, Na2S& NaCN is removed as H2S & HCN by conc. HNO3. Concentrate HNO3 convert Na2S into H2S and NaCN into HCN. The reaction is as follows:

    HCN is having boiling point 26 oC and H2S is gas. So, they were removed easily. 

     

  • Question 7
    1 / -0

    Lassaigne's test can detect -

    Solution

    HINT- This test is employed to detect the presence of nitrogen, sulphur, halogens, and phosphorous in an organic compound.

    STEP1- These elements are present in the covalent form in an organic compound. These are converted into the ionic form by fusing the compound with sodium metal.

    STEP2- The cyanide, sulphide, and halide of sodium formed are extracted from the fused mass by boiling it in distilled water. The extract so obtained is called Lassaigne’s extract. This Lassaigne’s extract is then tested for the presence of nitrogen, sulphur, halogens, and phosphorous.

     

  • Question 8
    1 / -0

    Nitric acid is added to sodium extract before adding silver nitrate for testing halogens because

    Solution

    Hint: Lassaigne's test is used to detect halogens, N, P, and S

    Step 1: 

    While testing Lassaigne’s extract for the presence of halogens, it is first boiled with dilute nitric acid. This is done to decompose NaCN to HCN and Na2S to H2S and to expel these gases. That is, if any nitrogen and sulphur are present in the form of NaCN and Na2S, then they are removed.

    Step 2: 

    The chemical equations involved in the reaction are represented as:

     

  • Question 9
    1 / -0

    A mixture of calcium sulphate and camphor can be separated by- 

    Solution

    Hint: The process of sublimation is used to separate  sublimating substances from non-sublimating compounds

    In this process, the sublimable compound changes from solid to vapour state without passing through the liquid state. Camphor is a sublimable compound and calcium sulphate is a non-sublimable solid. Hence, on heating, camphor will sublime while calcium sulphate will be left behind. 

     

  • Question 10
    1 / -0

    A gas among the following that can be absorbed by potassium hydroxide is -

    Solution

    Hint: Carbon dioxide is acidic in nature and potassium hydroxide is a strong base. 

    Step 1:

    Carbon dioxide reacts with potassium hydroxide to form potassium carbonate and water. The reaction is as follows:

    2KOH  + CO2  → K2CO3  + H2O

    Step 2:

    The mass of the U-tube containing KOH increases. This increase in the mass of Utube gives the mass of CO2 produced. From its mass, the percentage of carbon in the organic compound can be estimated.

     

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now