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Solutions Test - 10

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Solutions Test - 10
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  • Question 1
    1 / -0

    The following question has four choices out of which ONLY ONE is correct.

    Which of the following statements is true for 0.1 M aqueous solution of glucose and an aqueous solution of potassium chloride of the same concentration?

    Solution

    π = iCRT. Since i = 1 for glucose and i > 1 for KCl, osmotic pressure of glucose is less than that of KCl. So, (3) is correct and option (4) is incorrect.
    Since KCl ionizes to give K+ and Cl- ions, the apparent molality of KCl is more than that of glucose. Thus, the boiling point of KCl is higher. So, (1) is wrong.
    Depression in the freezing point is more for KCl than for glucose. So, the freezing point of KCl will be less. Thus, (2) is wrong.

     

  • Question 2
    1 / -0

    Which of the following colligative properties can provide molar masses of proteins (or polymers or colloids) with the greatest precision?

    Solution

    Molecular masses of polymers are best determined by osmotic pressure method because the values given by other colligative properties are low and cannot be measured accurately.

     

  • Question 3
    1 / -0

    The following question has four choices out of which ONLY ONE is correct.

    Blood cells do not shrink in blood because blood is ______ with respect to the cell cytoplasm.

    Solution

    Two solutions having the came concentration when separated by a semipermeable membrane will have same osmotic pressure at the same temperature and are known as isotonic solutions.
    Blood cells do not shrink in blood because blood plasma is isotonic with respect to the cell cytoplasm and no net osmosis occurs.

     

  • Question 4
    1 / -0

    Isotonic solutions have the same

    Solution

    Isotonic solutions refer to two solutions having the same osmotic pressure across a semipermeable membrane. This state allows for the free movement of water across the membrane, without changing the concentration of solutes on either side.

     

  • Question 5
    1 / -0

    The van't Hoff factor of benzoic acid in benzene is found to be

    Solution

    Benzoic acid dimerizes in benzene. Its van't Hoff factor will be 1/2.

     

  • Question 6
    1 / -0

    The van't Hoff factor for 0.1 M Ba(NO3)2 is 2.35. What is the percentage dissociation of Ba(NO3)2?

    Solution

    The formula for dissociation is α = (i - 1)/(n - 1), where α is partial dissociation, i is van't Hoff factor and n is number of species formed on dissociation.

     

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