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States of Matter: Gases and liquids Test - 5

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States of Matter: Gases and liquids Test - 5
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  • Question 1
    1 / -0

    The interaction energy of London force is inversely proportional to the sixth power of the distance between two interacting particles, but their magnitude depends upon

    Solution

    The London dispersion force is the weakest intermolecular force. The London dispersion force is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles. This force is sometimes called an induced dipole-induced dipole attraction. Their magnitude depends upon polarisability of interacting particles.

     

  • Question 2
    1 / -0

    The enthalpies of vaporisation of H2O, C2H5OH and CS2 are 40.6, 38.6 and 26.8 kJ/mol, respectively. The decreasing order of intermolecular forces in these liquids is:

    Solution

    The intermolecular forces are responsible for holding the liquid together. The enthalpy of vaporisation is directly proportional to the strength of the intermolecular forces.

     

  • Question 3
    1 / -0

    What is the dominate intermolecular force that must be overcome for converting liquid CH3OH into vapour?

    Solution

    As H–bonding is the predominant force of attraction between the molecules in alcohols, it has to be overcome so that CH3OH changes into the vapour phase.

     

  • Question 4
    1 / -0

    Dipole–induced dipole interactions are present in which of the following pairs?

    Solution

    HCl is polar and He is non–polar, therefore, dipole–induced dipole interactions are the inter particle forces that come into play.

     

  • Question 5
    1 / -0

    An open vessel at 37oC is heated until 3/5 of the air in it has been expelled. Assuming that the volume of the vessel remains constant, the temperature to which the vessel is heated is

    Solution

    T1 = 273 + 37 = 310 K
    Initial moles of air left = n moles
    Moles of air left = n - 3/5 n = 2/5 n
    Final temperature = 310 x 5/2 = 775 K
    Or 775 – 273 = 502oC

     

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