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Classification of Elements & Periodicity in Properties Test 14

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Classification of Elements & Periodicity in Properties Test 14
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  • Question 1
    1 / -0

    What are the two radii shown as 'a' and 'b' in the figure known as?

    Solution

    'a' Represents covalent radius which is the distance between the nuclei of two bonded atoms 'b' represents van der waals'radius which is the distance between nuclei of two closest molecules.

  • Question 2
    1 / -0

    Few values are given in the table in the direction from left to right and top to bottom. Predict the property which could be depicted in the table.

    Solution

    Atomic radius decreases in a period from left to right increases in a group from top to bottom.

  • Question 3
    1 / -0

    Which of the following statements regarding the variation of atomic radii in the periodic table is not true?

    Solution

    Size of atoms decreases with increases in atomic number in a period.

  • Question 4
    1 / -0

    Ionic radius in a group while moving down.

    Solution

    Ionic radius in a group increases from top to bottom since one energy shell is added with each period

  • Question 5
    1 / -0

    Kand Cl- ions are isoelectronic. Which of the statements is not correct?

    Solution

    Cation is smaller than the anion.

  • Question 6
    1 / -0

    Which of the following transitions will involve maximum amount of energy?

    Solution

    M2+ → M3+ + e- ; .IE3 > IE2 > IE1

  • Question 7
    1 / -0

    What is the order of successive ionisation enthalpies?

    Solution

    Third ionisation energy is higher than second ionisation energy which is higher than the first ionisation energy.

  • Question 8
    1 / -0

    Ionisation enthalpy of nitrogen is more than oxygen because of

    Solution

    Ionisation enthalpy of nitrogen is more than oxygen due to extra stability of half filled orbitals.

  • Question 9
    1 / -0

    Which of the following elettients will have highest second ionisation enthalpy?

    Solution

    After losing one electron, the atom will get a stable configuration and its second ionisation energy will be very high. Hence, option (b) is correct.

  • Question 10
    1 / -0

    Which of the following can most easily form unipositive gaseous ion?

    Solution

    Removal of electron from p-orbital is easier than from s-orbital because of less penetrating power of p-orbitals.

  • Question 11
    1 / -0

    Of the metals Be, Mg., Ca and Sr of group 2 in the periodic table, the least ionic chloride will be formed by

    Solution

    Beryllium halides are covalent in nature. This is due to small size and high charge of Be2+ ion i.e., it has high polarising power. However, the halides of the other alkaline earth metals (fluorides, chlorides, bromides and iodides) are ionic solids.

  • Question 12
    1 / -0

    A sudden large jump between the values of second and third ionization energies of an element would be associated with which ofthe following electronic configuration?

    Solution

    A sudden large jump between the values of 2nd and 3rd ionisation energies of an element indicates, that the element has two electrons in its valence shell. Then, the possible electronic configuration may be 1s2, 2s2, 2p6, 3s2.

  • Question 13
    1 / -0

    Few elements are matched with their successive ionisation energies. Identify the elements.

    Solution

    X has highest IE1 and IE2 hence, it is a noble gas. Y has low lE1, but very high IE2 hence, it is an alkali metal.
    Z has low lE1 than IE2 and IE2 is even lower than IE2 of alkali metal hence, it is an alkaline earth metal.

  • Question 14
    1 / -0

    First and second ionisation enthalpies (in kj/mol) of few elements are given below:

    Which of the above elements will form halides with formula MX2?

    Solution

    (ii) is a reactive metal from second group, and (iii) is a reactive non-metal from 17th group.
    For second group elements, the diiFerence in  successive IE is less. The compound formed will be MX2.

  • Question 15
    1 / -0

    The electronic states X and Y of an atom are depicted below:
    X : 1s2 2s2 2p6 3s1
    Y : 1s2 2s2 2p6 3s2 3p6 4s1
    Which of the following statements is not correct?

    Solution

    Given X = 1s2 2s2 2p6 3s1
    Y = 1s2 2s2 2p6 3s2 3p6 4s1
    Less energy is required to remove an electron from X than Y, because the distance between the nucleus and valence shell in Y is greater as compared to X.

  • Question 16
    1 / -0

    Which of the following elements will have highest ionisation energy?

    Solution

    Half-filled orbitals have extra stability hence they have high ionisation energy.

  • Question 17
    1 / -0

    Few values of enthalpies are given below:
    O = - 141 kJ mol-1 F = - 328 kJ mol-1
    S = - 200 kJ mol-1 Cl = - 349 kJ mol-1
    Wliat do these values show?

    Solution

    Negative value of electron gain enthalpy of S is more than that of oxygen and for Cl it is more than that of fluorine.

  • Question 18
    1 / -0

    In the given graph, a periodic property (R) is plotted against atomic numbers (Z) of the elements. Which property is shown in the graph and how is it correlated with reactivity of the elements?

    Solution

    I.E. in a group decreases and reactivity increases.

  • Question 19
    1 / -0

    Which is correct increasing order of their tendency of the given elements to form M3- ion?

    Solution

    On moving down the group, the stability of-3 oxidation state decreases. This is due to the following reasons (i) On descending a group the size of the atom or ion increases. As a result, attraction of the nucleus per newly added electron decreases (ii) A large anion cannot fit easily into lattice ofa small cation, (iii) As the negative charge on the ion increases, it becomes more and more susceptible to polarisation.

  • Question 20
    1 / -0

    Which of the following will have lowest electron affinity?

    Solution

    Electron affinity of noble gases is zero.

  • Question 21
    1 / -0

    Which of the following arrangements represents the correct order of electron gain enthalpy?

    Solution

    Electron gain enthalpy becomes more negative across a period while it becomes less negative in a group.
    However, electron gain enthalpy of O or F is less than that of the succeeding element. When electron is added to n = 2, the repulsion is more than when it is added to n = 3 in case of Cl or S.

  • Question 22
    1 / -0

    Why is the electron gain enthalpy of O or F less than that of S or Cl?

    Solution

    There is more repulsion for the incoming electron when the size of atom is smaller.

  • Question 23
    1 / -0

    Which of the foEowing statements regarding an anion is not true?

    Solution

    The effective nuclear charge decreases when an anion is formed due to increase in number of electrons.

  • Question 24
    1 / -0

    Which of the properties of isotopes of an element is different?

    Solution

    Isotopes differ in physical properties.

  • Question 25
    1 / -0

    Given below are the names of few elements based on their position in the periodic table. Identify the element which is not correctly placed.

    Solution

    Iodine can gain only one electron.
    I + e- → I-

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