Chemical Bonding and Molecular Structure Test 5

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Chemical Bonding and Molecular Structure Test 5

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Weekly Quiz Competition

Question 1
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Direction (Q. Nos. 1-12) This section contains 12 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.
Q. Which of the following compounds are soluble in H₂O ?

A
CH₃CHO

B
CH₃COCH₃

C
CH₃CH₂OH

D
All of these

Solution

All these are soluble in water due to intermolecular H-bonding.
Question 2
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Which of the following has maximum boiling point?

A

B
CH₃CH₂CH₂OH

C
H₂O

D
CH₃CH₂CH₂CH₃

Solution

Due to intermolecular H-bonding at two terminals boiling point of glycol is maximum.
Question 3
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In which of the following boiling point of Column I is not higher than that of Column II?

A
a

B
b

C
c

D
d

Solution

(a) Intermolecular H-bonding, boiling point increases with molecular weight for compounds within the same family.
(b) H-bonding is absent is CH₃CH₂CH₃.
(c) Methanol is the larger molecule but H₂O has more H-bonding because of two O—H bonds.
Thus, boiling point of H₂O(ll) > CH₃OH(l).
(d) Molecular weight of butanol is much higher and overcomes attractive forces of butanol.
Question 4
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Which of the following correctly represents H-bonding?

A

B

C

D

Solution

H-bonding is between polar and electronegative 0, N and F C-atom or H attached to C is not polar. Thus, (a), (c), (d) are incorrect.
Question 5
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In dimer formation of which O-atom(s) is/are involved through H-bonding?

A
Only 1

B
Only 2

C
Both a. and b.

D
None of these

Solution
Question 6
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In the following compounds, select the points of interm olecular H-bonding (linear),

A
1, 2, 3

B
1, 3, 4

C
1,2,4

D
1,4

Solution

1. Enoiic H, acidic and polar takes part in H-bonding.
2. 3° alcohol least acidic maximum basic.
3. Carbonyl oxygen is not involved.
4. Acidic and polar H, takes part in H-bonding.
Question 7
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In the following alcohol, which — OH group is involved to the maximum extent in H-bonding?

A
a

B
b

C
c

D
d

Solution

O — H group is attached to (ene) is m ost a cidic and thus, has maximum intermolecular H-bonding.
Question 8
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Among the following sets, highest boiling points are of the species.
I. HF, HCI, HBr, HI
II. H₂O, H₂S, H₂Se, H₂Te
III. NH₃,PH₃, AsH₃,SbH₃

A
HF, H₂O, NH₃

B
HCI, H₂S, PH₃

C
HBr, H₂Te, AsH₃

D
HI, H₂S, AsH₃

Solution

F, O and N are electronegative elements. Thus, HF molecules are associated by intermolecules H-bonding giving it a liquid state and thus highest boiling point out of HF, HCl.HBr and HI.
Similarly, H₂O has highest boiling point, and NH₃ has highest boiling point.
Question 9
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The H-bond is shortest in

A
S— H---S

B
N— H ... O

C
F— H ... F

D
F— H ... O

Solution

(EN) of S < 0 < F
Thus, H is attracted to larger extent by F atom making (H.......F) bond shortest.
Question 10
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What is the dominant intermolecular force or bond that must be overcome in converting liquid CH₃CH₂OH to vapours?

A
H-bonding

B
Dipole-dipole interactions

C
Covalent bonds

D
London dispersion force

Solution

CH₃CH₂OH is in liquid state due to association as a result of intermolecular H-bonding.
Question 11
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Number of water molecules directly attached to one water molecule is

A
1

B
2

C
3

D
4

Solution

One water molecule is directly attached to four water molecules. Thus, coordination number of water is 4.
Question 12
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Consider the following compounds
I. HCI
II. HF
III. CH₃COOH
IV. CH₄
V. CH₃OH
VI. CH₃COO^-
Q.
H-bonding is not present in

A
I, III and IV

B
I, IV and VI

C
II, III and V

D
None

Solution

HCI: EN of Cl is smaller, hence less polar than HF.
CH₄ :non-polar
CH₃COO^- : H attached to C-atom is non-polar hence
HCI, CH_4, CH₃COO^- — lack H-bonding.
Question 13
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Direction : Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.
Q. Match the species in Column I with rank order of their boiling point in Column II. (Species with lowest boiling points is at S_N1).

A
a

B
b

C
c

D
d

Solution

n-butane lacks H-bonding. Hence, its boiling point is least.

due to difference in polar H⁺ for H-bonding.
Boiling point of CH₃CH₂CH₂CH₂OH > H₂O due to much larger size of alcohol.