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States of Matter : Gases & Liquids Test 12

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States of Matter : Gases & Liquids Test 12
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  • Question 1
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    Direction (Q. Nos. 1-3) This section contains 3 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

    Q. The critical tem perature of water is higher than that of O2 because the H2O molecules have

    Solution

    Critical temperature is directly proportional to intermolecular force of attraction. H2O is a polar molecule, has greater intermolecular force of attraction than O2, hence higher critical temperature.

  • Question 2
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    Select the correct statement.

  • Question 3
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     (reduced pressure),  (reduced volume) and  (reduced temperature), then,

    Solution

    Let P/PC = π, V/VC = Φ and T/TC = θ
    (P + a/V2)(V-b) = RT
    (πPC + a/Φ2VC2)(ΦVC - b) = RT
    (πa/27b2 + a/Φ29b2)(3Φb - b) = R×8θa/27Rb
    a/27b(π+3/Φ2)(3Φ-1) = 8θa/27b
    (π + 3/Φ2)(3Φ-1) = 8θ

  • Question 4
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    Direction (Q. Nos. 4) Choice the correct combination of elements and column I and coloumn II  are given as option (a), (b), (c) and (d), out of which ONE option is correct.

    Q. Values of different types of temperatures have been given in Column II. Match these values with the correct definition of temperatures in Column I and mark the correct answer from codes :

    Solution

    TC = 8a/27Rb
    TB = a/Rb
    TI = 2a/Rb
    TC/TI = 4/27

  • Question 5
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    Direction (Q. Nos. 5-9) This sectionis based on statement I and Statement II. Select the correct answer from the code given below.

    Q. 

    Statement I : Gases do not liquefy above th e ir Tc (critical temperature), even on applying high pressure.

    Statement Il : Above Tc , m olecular speed is high and interm olecular attractions cannot hold the molecules together, because they escape due to high speed.

    Solution

    The correct answer is option A
    Both statement 1 and statement 2 are true and statement 2 is the correct explanation of statement 1. Gases do not liquefy above their critical temperature, even applying high pressure because above critical temperature, the molecular speed is high and intermolecular attractions cannot hold the molecules together.

  • Question 6
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    Statement I : At Tc , liquid passes into gaseous state im perceptibly and continuously.

    Statement II : At Tc, density of liquid and gaseous phase is equal.

    Solution

    Both assertion and reason are true and reason is the correct explanation of assertion. Gases do not liquefy above their critical temperature, even an applying high pressure because above critical temperature, the molecular speed is high and intermolecular attractions cannot hold the molecules together.

  • Question 7
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    Statement I : At Tc, there is no distinction between the gaseous state and liquid state and no second phase is formed irrespective of the pressure of the system.

    Statement II : At the critical point, densities of a substance in gaseous and liquid states are equal.

    Solution

    At critical temperature, there is no distinction b/w liquid and gases irrespective of pressure applied. Critical temperature depends on the magnitude of intermolecular forces of attraction present between the gas molecules.
    Higher critical temperature represents strong intermolecular forces of attraction present between the gas molecules.
    Such gas can be easily liquified.

  • Question 8
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    Statement I : Reduced equation of state in terms of reduced temperature θ reduced volume and reduced pressure π can be applied to solid, gases and liquid.

    Statement II:   Equation is independent of p, V and T as well as independent of van der Waais’ constant a and b.

    Solution

    Let P/PC = π, V/VC = Φ and T/TC = θ
    (P + a/V2)(V-b) = RT
    (πPC + a/Φ2VC2)(ΦVC - b) = RT
    (πa/27b2 + a/Φ29b2)(3Φb - b) = R×8θa/27Rb
    a/27b(π+3/Φ2)(3Φ-1) = 8θa/27b
    (π + 3/Φ2)(3Φ-1) = 8θ

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