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Equilibrium Test 10

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Equilibrium Test 10
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  • Question 1
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    Direction (Q. Nos. 1-8) This section contains 8 multiple choice questions. Each question has four
    choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

    Q. For the following equilibrium,

    PCl5(g)  PCl3(g) + Cl2 (g)

    Vapour density is found to be 100 when 1 mole of PCI5 is taken in 10 dm3 flask at 300 K. Thus, equilibrium pressure is

    Solution

    Given, vapour pressure = 100
    So, molecular weight = 200
    Degree of dissociation;α = 1/(n-1)[Mtheo-Mobs/Mobs]

    α   =   1/(2-1)×[208.5-200/208.5]
    α  = 0.0425
    PCl5(s)    ⇌    PCl3(g) + Cl2(g)
    At start      1                 -           -     -
    At eqm.  (1-0.0428)   (0.0428)  (0.0428)
    Total moles at eqm. = 1.0428
    Total pressure at equilibrium; pV = nRT
    p = 1.0428×0.0821×300/10
    p  = 2.5676 atm

  • Question 2
    1 / -0

    For the equilibrium, N2O4(g)  2NO2(g)

    here, d is experimental vapour density and D is theoretical vapour density. Thus, for the equilibrium 

  • Question 3
    1 / -0

    In the following equilibrium at 400 K in 1 dm3 flask,

    COCl2 (g)CO(g) + Cl2 (g),
    ratio of theoretical and experimental vapour density is 1.4. Thus, equilibrium constant Kc is

  • Question 4
    1 / -0

    A(g) is 100% converted into B according to the reaction,
    A(g)  3b(g)
    Value of   at this point is

    Solution

                       A(g)↔3B(g)
    t  = 0               1             0
    t1 = t1                      −x          +3x
    at eq=teq                 1−x         3x
    Given that x=0.90
    Total moles at equilibrium= 1−x+3x = 1+2x
    = 1+2(0.90) = 2.8

  • Question 5
    1 / -0

    In the dissociation of PCI5(g)into PCI3(g)and Cl2(g), values of(1 + x)have been plotted versus D/d. Thus, correct graph is

  • Question 6
    1 / -0

    CCI4(g) dissociates 50% into gaseous free radicals at 1000 K and at equilibrium experimental vapour density is found to be 38.5. Thus, CCI4(g) dissociates under the given conditions to

  • Question 7
    1 / -0

    0.578 g N2O4(g) dissociates into 1dm3 flask at 308 K to give a pressure of 24.12 kPa.
    N2O4 (g)  2NO2(g)
    Thus, degree of dissociation of N2O4 is 

  • Question 8
    1 / -0

    SO3(g)is partially dissociated into SO2(g)and O2(g) at 900K and 1 atm as: 

    The density of the equilibrium mixture was found to be 0.866 gdm-3. Thus, degree of dissociation of SO3 (g) is

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