Hydrogen Test 3

in earth atmosphere hydrogen exists in combined form.

Water has a high boiling point because of the presence of extensive hydrogen bonding interactions between the water molecules in the liquid phase (water is both a strong hydrogen bond donor and acceptor). When heat is first applied to water, it must break the intermolecular hydrogen bonds within the sample.

CaCO₃.Mg(OH)₂ can be precipitate out in order to remove temporary hardness.

In the above picture, we can clearly see that only in first example H₂O₂ is able to oxidize the given sample (Iodine goes to -1 to 0), while in other examples, H₂O₂ has reduced the sample (Fe goes +₃ to +2, Mn goes +7 to +2, and I goes +7 to +5 in the last example). So, the first equation describes the oxidation nature of H₂O₂.

H₂O₂ is antispectic used in the name of perhydrol.

deuterium , also known as heavy hydrogen) is one of two stable isotopes of hydrogen (the other being protium, orhydrogen-1). The nucleus of deuterium, called a deuteron, contains one proton and one neutron, whereas the far more common protium has no neutron in the nucleus.

Heat of vapourisation is the responsible factor.

In Calgon’s method sodium hexametaphosphate is used to remove hardness of water

I₂ gets reduce to I⁻ while  H₂O₂ get oxidize to O₂

Rocket Fuel is used in space research is H₂

Hydrogen is the most abundant element in the universe, accounting for about 75 percent of its normal matter, and was created in the Big Bang.

because of presence of lp of electron on head of oxygen atom the bond angle in water deviates from standard bond angle of 109.8⁰ . bond angle in water is 104.5⁰

The correct answer is option B
There are three isotopic forms of hydrogen: Protium (H), Deuterium (D), Tritium (T). 

The isotopes of hydrogen show similar chemical properties since they possess the same electronic configuration. But they show different physical properties due to different masses. However, the reactivity of protium is more than that of deuterium or tritium. It is due to the relatively stronger D-D or T-T bond.

H₂O₂ behaves as a bleaching agent because it breaks the chemical bonds of the chromophores

Stoichiometric compounds of hydrogen are formed with s-block elements. Only Group I elements form stoichiometric hydrides with Hydrogen as same as halides.

A hydrogen bond is a force between H and either N, O, or F, the three most electronegative elements.. Covalent bonds are much stronger than either, twenty times more than the H-bond and times stronger than the d-d force. A covalent bond involves the sharing of electron pairs between atoms, generally two non-metals.

The water molecule has hydrogen atoms and, therefore, could act as an acid in a reaction. The oxygen atom in the water molecule has two lone pairs, one of which could be used to form a bond with a \(H^+\(, and, therefore, the water molecule could act as a base in a reaction. Since water has the potential to act both as an acid and as a base, water is amphoteric.

H₂O₂ is an oxidizing agent in 1st reaction and Reducing agent in 2nd reaction.

The electronic configuration of the Hydrogen atom is 1s1.

It has one electron in the outermost shell. It exists as a diatomic molecule (H2​) by sharing its' electron with other hydrogen atom.

It cannot form ionic compounds because it cannot donate its' electron and can only form covalent compounds by sharing the electron. It cannot lose an electron to form a cation because the hydrogen atom cannot exist after losing an electron.

Metallic hydrides are non stoichiometric hydride.

Noble gases are inert they donot form any hydrides.

In crystal structure of Copper sulphate pentahydrate there only 4 water molecule of hydration and one water molecule is associated with hydrogen bonding interaction.

Volume strength = 11.2 x M So M = 5/11.2 = 0.446 Strength (g/L ) = 0.446 x 34 = 15.17 g/L

CO + H₂is known as water gas.

The boiling points of NH₃, H₂O and HF are expected to be lower than those of the subsequent group member hydrides on the basis of molecular masses. But boiling points of NH₃ , H₂O and HF will be higher than the hydrides of their subsequent group members. This is because of higher electronegativity of N, O and F. As a result, these exhibit hydrogen bonding in their hydrides.