p-Block Elements Test

Result

p-Block Elements Test - 24

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Weekly Quiz Competition

Question 1
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Direction (Q. Nos. 1-7) This section contains 7 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
Q.
The hybridisation of N in solid state for N₂O₅ is

A
sp and sp²

B
Only sp²

C
sp² and sp²

D
Only sp³

Solution

In solid state, N₂O₅ exists as nitronium nitrate
In nitrogen is sp and in , nitrogen is sp².
Question 2
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PH₃ becomes spontaneously inflammable due to the presence of

A
NH₃

B
N₂H₄

C
P₂H₄

D
All of the above

Solution

Pure phoshine is not inflammable but due to contamination of P₂H₄ and P₄ vapours, it becomes inflammabl.
Question 3
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Which is incorrect among the following options?

A
Reducing property of H₃PO₄ > H₃PO₃ > H₃PO₂

B
Oxidation state of nitrogen N₂O < NO < N₂O₃ < N₂O₅

C
Basicity NH₃ > PH₃> AsH₃ > SbH₃

D
Boiling point of SbH₃ > AsH₃ > NH₃ > PH₃

Solution

Reducing property of P oxyacids is due to P—H bonds in the acid. Correct reducing property order is
Question 4
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The number of P – O bonds and lone pairs of electron present in P₄O₆ molecule respectively

A
12 and 4

B
8 and 8

C
12 and 16

D
12 and 12

Solution

Number of P – O bonds = 12
Number of pair of electron = 16
Question 5
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Which is the correct order of basic strength ?

A
NH₂OH < N₂H₄ < NH₃

B
N₂H₄ < NH₂OH < NH₃

C
NH₃ < N₂H₄ < NH₂OH

D
NH₂OH < NH₃ < N₂H₄

Solution

NH₂OH and NH₂—NH₂ may be considered as NH₃ derivatives in which H is replaced but — OH and NH₂ respectively. Due to their electron withdrawing nature, these groups decreases electron density over nitrogen making them less basic. The effect of — OH group is stronger than —NH₂
Question 6
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Solid PCl₅ and solid PBr₅ exist respectively as

A
I and III

B
I and IV

C
II and III

D
II and IV

Solution

PBr does not split in the same fashion. The anion is not possible due to large size of Br-atoms. Hence, it splits differently.
Question 7
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Number of moles of NaOH needed to neutralise one mole each of H₃PO₂, H₃PO₃ and H₃PO₄ respectively are

A
3, 3 and 3

B
1, 2 and 3

C
2, 2 and 3

D
2, 1 and 3

Solution

H₃PO₂, H₃PO₃ and H₃PO₄ are mono, di and tribasic acids respectively.
Question 8
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Direction (Q. Nos. 8 and 9) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.
Q.
Match the Column I with Column II and mark the correct option from the codes given below.

A

B

C

D

Solution
Question 9
1 / -0

Match the Column I with Column II and mark the correct option from the codes given below.

A

B

C

D

Solution
Question 10
1 / -0

Direction (Q. No. 10) This section is bassed on Statment I and Statment II. II. Select the correct answer from the codes given below.
Q.
Statement I : NF₃ is a weaker ligand than N(CH₃)₃
Statement II : NF₃ ionises to give F^- ions in aqueous solutio

A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statemen I

B
Both Statement I and Statement II are correct but Statement II is not the correct. explanation of Statment I

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

Due to e^- withdrawing capacity of fluorideion, it withdraws. from nitrogen in NF₃ make it weakerlig and while presence of e^- donating methyl group makes the nitrogen in N(CH₃)₃ a strong ligand. In aqueous medium, NF₃ furnishes fluorideion.