Self Studies
Self Studies
Self Studies
Self Studies

p-Block Elements Test - 8

Result Self Studies

p-Block Elements Test - 8
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    Identify the alloy containing a non-metal as a constituent.

    Solution

    (1) Steel is an alloy of iron and carbon containing less than 2% carbon and 1% manganese, and small amounts of silicon, phosphorus, sulphur and oxygen.
    (2) Invar is a 36% nickel iron alloy, which has the lowest thermal expansion among all metals and alloys in the range from room temperature up to approximately 230°C.
    (3) Bell metal is a hard alloy used for making bells and related instruments, such as cymbals. It is a form of bronze, usually in approximately a 4 : 1 ratio of copper to tin (e.g. 78% copper and 22% tin by mass).
    (4) Bronze is an alloy consisting primarily of copper, commonly with about 12% tin and often with the addition of other metals (such as aluminium, manganese, nickel or zinc).

     

  • Question 2
    1 / -0

    Reaction of diborane with ammonia initially gives

    Solution

    Diborane initially forms an addition compound on reacting with NH3.
    The compound, upon heating, gives borazine (B3N3H6), also called inorganic benzene.
    3B2H6 + 6NH3 → [BH2(NH2)2][BH4]- → 2B3N3H6 + 12H2

     

  • Question 3
    1 / -0

    Group 13 elements form halides with the chemical formula MCl3. Out of the following halides of group 13, the most acidic halide is:

    Solution

    AlCl3 is relatively less electron deficient due to dimerisation; hence, it is a weaker acid.
    BBr3 is most acidic and it can accept electron pair most readily among the given halides of boron because the extent of pπ-pπ back bonding is least in BBr3.

     

  • Question 4
    1 / -0

    As we move down the group, the atomic and ionic radii of elements increase with increase in the atomic number. But the atomic radius of Ga is less than that of Al and there is very little increase in radius from Ga to Tl. This is because of:

    Solution

    The anomalous trends of the atomic radii, observed in the elements of the group 13 is because of the ineffective shielding by the intervening d- and f-electrons which results in an increase in the effective nuclear charge.

     

  • Question 5
    1 / -0

    The change in the hybridisation of boron during the following conversion is:

    BF3 + F- → [BF4]-

    Solution

    The hybridisation of boron changes from sp2 in BF3 to sp3 in BF4-.
    Hence, the bond angle changes from 120° in BF3 (trigonal planar structure) to 109.5° in BF4- (tetrahedral structure).

     

  • Question 6
    1 / -0

    The boron compound that forms π-bonds in addition to σ-bonds is:

    Solution

    In BF3, boron is sp2-hybridised and forms sigma bonds with each F atom.
    The empty unhybridized p-orbital of Boron participates in the pπ-pπ back bonding with the filled p-orbitals of fluorine atoms.

     

Self Studies
User
Question Analysis

  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now