Atomic Structure Test

Result

Atomic Structure Test - 27

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Weekly Quiz Competition

Question 1
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Which of the following conclusions regarding the structure of atom is based on Rutherford’s α-particle scattering experiment?

A
The positive charge is concentrated in a very small volume of the atom

B
The positive charge is scattered with the electrons throughout the atom

C
The volume occupied by the nucleus is half of the volume of atom

D
Most of the space in the atom is occupied by the neutrons

Solution

As a very few α-particles were deflected by sharp angles, it was concluded that the positive charge is concentrated in a very small volume of the atom.
Question 2
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Which of the following observations was not correct during Rutherford’s scattering experiment?

A
Most of the α-particles passed through the gold foil undeflected

B
A small fraction of the α-particles was deflected by small angles

C
A large number of the α-particles were bounced back

D
A very few α-particles (~1 in 12,000) were bounced back

Solution

Very few of bombarded α-particles on gold foil were deflected by sharp angles and therefore, it was concluded that the positive charge is concentrated in a very small volume of the atom called nucleus. Since few were deflected, the size of the nucleus is very small as compared with atom size.
Most of the particles passed through the foil undeflected and was concluded that most of the space in an atom is empty.
Question 3
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How many neutrons are there in ?

A
38

B
50

C
126

D
88

Solution

In
Atomic number = No. of protons = No. of electrons = 38
Atomic mass = 88
Number of neutrons = 88 - 38 = 50
Question 4
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An element with mass number 81 contains 31.7% more neutrons as compared to protons. Find the symbol of the atom

A

B

C

D

Solution

Mass number of the element = 81
i.e., p + n = 81
Let the number of protons be x.
Number of neutrons

Symbol of the element
Question 5
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Which of the following species is isoelectronic with CO?

A
HF

B
N₂

C

D

Solution

Isoelectronic species means species having same number of electrons.
In CO; no. of electrons = 6 + 8 = 14
In N₂; no. of electrons = 7 + 7 = 14