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Atomic Structure Test - 10

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Atomic Structure Test - 10
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  • Question 1
    1 / -0

    A 3d electron having s = + 1/2  can have magnetic quantum number

    Solution

    3d electrons having s = +1/2
    l = 2,
    It can have the following values of magnetic quantum number: -2, -1, 0, +1, +2

     

  • Question 2
    1 / -0

    The number of nodal points in the plot of Rn, 0 versus r is equal to the value of

    Solution

    The number of nodal points in the plot of Rn, 0 versus r is n – (l + 1). For example, R1, 0 (i.e. 1s orbital) has no node, and R2, 0 (i.e. 2s orbital) has one node.

     

  • Question 3
    1 / -0

    For 2s orbital, the nodal surface exists at a distance _____ from the nucleus.

    Solution

    At r = 2a0, there is a node as the value of function R2, 0 is zero at this distance.

     

  • Question 4
    1 / -0

    The maximum number of 3d electrons having spin quantum number s = +1/2 is

    Solution

    The total number of 3d subshells is 10, but the number of electrons with s = + 1/2 is 5.

     

  • Question 5
    1 / -0

    The energy of an orbital in a multielectron atom depends on the

    Solution

    The energy of a single electron species such as H, He+ and Li2+ depends only on the principal quantum number, whereas for a multielectron species it depends on the principal as well as azimuthal quantum number.

     

  • Question 6
    1 / -0

    Which of the following orbital notations does not have spherical node?

    Solution

    The number of nodes is equal to (n – 1) and the number of spherical nodes is given by the expression (n – l – 1).

     

  • Question 7
    1 / -0

    Which of the following sets of quantum numbers (n, l, m and ms, respectively) is not possible?

    Solution

    The value of l cannot exceed n – 1.

     

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