Atomic Structure Test

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Atomic Structure Test - 18

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Weekly Quiz Competition

Question 1
1 / -0

The energy of a photon in Joules that has a wavelength of 9.0 m is:

A
6.0 ×10^-23

B
4.5 ×10²⁵

C
4.5 × 10^-25

D
2.2 ×10^-26

Solution
Question 2
1 / -0

The ratio of the energy of a photon of 2000 Çº wavelength radiation to that of 4000 Çº radiation is:

A
2

B
½

C
¼

D
4

Solution

We have E = hc/λ
E₁/E₂ = 4000Å/2000Å = 2
Question 3
1 / -0

A radio operator broadcast on the 6-meter band. The frequency of this electromagnetic radiation is __________ MHz.

A
500

B
20

C
50

D
200

Solution

The speed of all form of electromagnetic wave is related by the equation c = λ.ν,
Where c is the speed of light = 3.00 x 10⁸ m/s, λ is the wavelength in m and ν is the frequency is s^-1 or Hz.
Therefore, ν = 3.0 x10⁸ / 6 = 5 x 10⁸ s^-1 = 50 MHz
Question 4
1 / -0

Electromagnetic radiation travels through vacuum at a speed of __________ m/s.

A
10,000

B
It depends on wavelength.

C
3.00 × 10⁸

D
186,000

Solution

The speed of light (electromagnetic radiation) through vacuum has a constant value of 3.00 x 10⁸m/s and is independent of the wavelength in vacuum.
Question 5
1 / -0

What is the frequency of light in s^-1 that has a wavelength of 3.12 x 10^-3 cm?

A
9.62 × 10¹²

B
1.04 ×10¹³

C
2.44 × 10¹⁶

D
3.69

Solution

The wavelength (λ) and frequency (ν) of electromagnetic wave is related by the equation c = λ.ν,
Where c is the speed of light = 3.00 x 108 m/s, λ is the wavelength in m and ν is the frequency is s^-1or Hz.
Substituting the values in the formula, we get,
c = λ.ν
ν = c/λ
ν = 3.0 x 10⁸ / 3.12 x 10^-5
= 0.96 x 10¹³ m = 9.62 X 10¹²
Question 6
1 / -0

The ejected electrons from the surface of metal in photoelectric effect are called:

A
Photoelectrons

B
Proton

C
Electron

D
Neutron

Solution

If light beyond a specific threshold frequency hits a metal surface, electrons are ejected from the surface of the metal. The minimum energy required to eject an electron from the surface is called the work function of the metal. These ejected electrons are called photoelectrons. The kinetic energy of the most energetic electron among these photoelectrons is called the maximum kinetic energy.
Question 7
1 / -0

If the value of azimuthal quantum number is 3, the possible values of magnetic quantum numbers would be:

A
0, 1, 2, 3

B
3, -2, -1, +1, +2, +3

C
0, -1, -2, -3

D
-3, -2, -1, 0, +1, +2, +3

Solution

The total possible values of m for l range from – through 0 to +.
Question 8
1 / -0

What is the energy of a photon that has a wavelength of 13.2 nm?

A
4.42 × 10^-23 J

B
1.507 x 10⁻¹⁵ J

C
1.51 × 10^-17 J

D
1.99 × 10^-25 J

Solution

= 1.507 x 10^-15J.
Question 9
1 / -0

What is correct about wave number?

A
It is defined as the number of waves which pass through a particular point in one second

B
It is defined as the number of wavelengths per unit length

C
It is defined as the distance between two neighbouring crests or troughs of wave

D
It is the distance travelled by a wave in one second

Solution

Wavenumber is defined as the number of complete wave cycles per unit length of a linear space. It can also be referred to as the spatial frequency of the waves represented in radians per unit distance, or cycles per unit distance. It is usually measured in units of reciprocal centimeters (cm^-1) and reciprocal meters (m^-1).
Question 10
1 / -0

The wavelength of light that has a frequency of 1.20 × 10¹³s^-1 is __________ m.

A
2.50 × 10^-5

B
0.0400

C
25.0

D
12.0

Solution

The speed of all form of electromagnetic wave is related by the equation c = λ.v, whereby, λ = 3.0 x 10⁸ / 1.2 x 10¹³= 2.5 x 10 ^-5m.
Question 11
1 / -0

Which of the following radiation has the shortest wavelength.

A
Infra red

B
ultraviolet

C
microwave

D
X-ray

Solution

Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma raysare all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.
Question 12
1 / -0

Who discovered and first used the constant h = 6.6 x 10^-34 J.s?

A
De Broglie

B
Einstein

C
Bohr

D
Planck

Solution

Max Planck gave the Planck’s quantum theory and was the first to determine the value of h which is the Planck’s constant.
Question 13
1 / -0

The energy of a photon of light has what kind of proportionality to its frequency and its wavelength.

A
directly, inversely

B
inversely, directly

C
inversely, inversely

D
directly, directly

Solution

As E=h(frequency) E is directly proportional to frequency and as frequency = speed of light / wavelength frequency is inversely proportional to wavelength.
Question 14
1 / -0

What is the wavelength of light (nm) that has a frequency 4.62 ×10¹⁴s^-1?

A
1.54 × 10^-3

B
649

C
932

D
1.07 × 10⁶

Solution

The wavelength (λ) and frequency (ν) of electromagnetic wave is related by the equation c = λ.ν, whereby, λ = 3.0 x10⁸ / 4.62 ×10¹⁴ = 0.649 x 10^-6 m = 649nm
Question 15
1 / -0

What is the frequency of a photon that has an energy of 3.7 x 10^-18J?

A
2.5 Ã— 10^-15

B
5.58 x 10¹⁵HZ

C
1.8 Ã— 10^-16

D
5.6 Ã— 10¹⁵

Solution

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Atomic Structure Test - 18

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Atomic Structure Test - 18

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Question 1

6.0 ×10-23

4.5 ×1025

4.5 × 10-25

2.2 ×10-26

Solution

Question 2

2

½

¼

4

Solution

Question 3

500

20

50

200

Solution

Question 4

10,000

It depends on wavelength.

3.00 × 108

186,000

Solution

Question 5

9.62 × 1012

1.04 ×1013

2.44 × 1016

3.69

Solution

Question 6

Photoelectrons

Proton

Electron

Neutron

Solution

Question 7

0, 1, 2, 3

3, -2, -1, +1, +2, +3

0, -1, -2, -3

-3, -2, -1, 0, +1, +2, +3

Solution

Question 8

4.42 × 10-23 J

1.507 x 10−15 J

1.51 × 10-17 J

1.99 × 10-25 J

Solution

Question 9

It is defined as the number of waves which pass through a particular point in one second

It is defined as the number of wavelengths per unit length

It is defined as the distance between two neighbouring crests or troughs of wave

It is the distance travelled by a wave in one second

Solution

Question 10

2.50 × 10-5

0.0400

25.0

12.0

Solution

Question 11

Infra red

ultraviolet

microwave

X-ray

Solution

Question 12

De Broglie

Einstein

Bohr

Planck

Solution

6.0 ×10^-23

4.5 ×10²⁵

4.5 × 10^-25

2.2 ×10^-26

3.00 × 10⁸

9.62 × 10¹²

1.04 ×10¹³

2.44 × 10¹⁶

4.42 × 10^-23 J

1.507 x 10⁻¹⁵ J

1.51 × 10^-17 J

1.99 × 10^-25 J

2.50 × 10^-5

1.54 × 10^-3

1.07 × 10⁶

2.5 Ã— 10^-15

5.58 x 10¹⁵HZ

1.8 Ã— 10^-16

5.6 Ã— 10¹⁵