Liquid Test

Result

Liquid Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

Joule-Thomson coefficient (∂T/∂P)_H for an ideal gas is:

A
zero

B
+ve

C
-ve

D
none of these

Solution

Ideal gas does not show Joule-Thomson effect.
Question 2
1 / -0

All the three states H₂O, i.e., the triple point for H₂O the equilibrium,

Ice ⇌ Water ⇌ Vapour exist at:

A
3.85 mm and 0.0981 °C

B
4.58 mm and 0.0098 °C

C
760 mm and 0°C

D
none of the above

Solution

The conditions for triple point of H₂O.

the particular temperature and pressure at which the solid, liquid, and gaseous phases of a given substance are all at equilibrium with one another.
Question 3
1 / -0

A gas cannot be liquefied if:

A
Forces of attraction are low under ordinary conditions

B
Forces of attraction are high under ordinary conditions

C
Forces of attraction are zero under ordinary conditions

D
Forces of attraction either high or low under ordinary conditions

Solution

Hint: In the case of Ideal gas, the force of attraction between molecules is zero.

Ideal gas molecules are separated from each other by large space and the actual volume of the gas molecule is negligible with respect to the volume of gas. Due to large intermolecular spaces, there is no force of attraction between the ideal gas molecules and they are completely independent of each other.
Question 4
1 / -0

The gas among the following can be most steadily liquefied is -

A
NH₃

B
Cl₂

C
SO₂

D
CO₂

Solution

Hint: Gas having a high force of attraction liquify easily

SO₂ has a higher value of van der Waals' forces of attraction and thus, is more easily liquefied.

value of 'a" for

SO₂ has higher value of "a" hence it has maximum forces of attraction, thus, it will liquify easily.
Question 5
1 / -0

The correct statement regarding the van der Waal constant of N₂ & NH₃ is -

A

B

C

D

Solution

Hint- a is measure of intermolecular strength and b depends upon molecular weight

EXPLANATION

Higher the polarity, easier to liquify.

The ease of liquification of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant ‘a’.

Hence, higher the value of ‘a’, greater the intermolecular force of attraction, easier the liquification.

In the present case, NH₃ has highest ‘a’, can most easily be liquefied.Molecular weight of nitrogen is greater than ammonia ,SO the value of b for nitrogen
Question 6
1 / -0

Maximum deviation from ideal gas is shown by-

A
H_2(g)

B
N_2(g)

C
CH_4(g)

D
NH_3(g)

Solution

Hint: Easily liquefiable gases exhibit maximum deviation

Easily liquefiable gases like NH₃, SO₂ etc. exhibit maximum deviation from ideal gas as for them Z<<< 1 .

CH₄ also exhibits deviation but it is less as compared to NH₃.
Question 7
1 / -0

Joule-Thomson expansion of an ideal gas is an

A
Isothermal process

B
Isobaric process

C
Isoenthalpic process

D
Ideal process

Solution

Joule-Thomson effect occurs at constant enthalpy.
Question 8
1 / -0

Choose the correct statement for viscosity (η) variation with T and P for an ideal gas-

A
η of a gas increases with increase in temperature (T), but it is independent of pressure

B
η of a gas decreases with increase in T and increases with increase in P

C
η of a gas is independent of temperature and pressure

D
η of a gas increases with increase in both T and P

Solution

In the case of gases, the viscous resistance arises from the transport of molecules from one layer to another, with transfer of momenta, so that the fast moving molecules in one layer are slowed down, while the slow moving molecules in the other are accelerated. This momentum transfer increases with increase in temperature. A simple expression for the viscosity of a gas
Question 9
1 / -0

The critical temperature and critical pressure of a gas obeying Van dar Waal's equation are 30^oC and 73 atm, respectively. Its Van der Waal's constant b (in litres mol⁻¹) is:

A
0.500

B
0.060

C
0.265

D
0.0425

Solution
Question 10
1 / -0

The critical volume of a gas is 0.072 lit. mol⁻¹. The radius of the molecule will be, in cm:

A

B

C

D

Solution

The critical volume is three times the Van der Waals constant 'b'.