Physics Test 106

Result

Physics Test 106

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Weekly Quiz Competition

Question 1
4 / -1

Find out angle made by resultant of

A
60°

B
45°

C
90°

D
180°

Solution
Question 2
4 / -1

The diagonals of a parallelogram are What is the area of the parallelogram ?

A
0.5 unit

B
1 unit

C
2 unit

D
4 unit

Solution
Question 3
4 / -1

The position of a particle at time t is given by the relationwhere v₀ is a constant and α > 0. The dimensions of v₀ and α are respectively

A
M⁰L¹T^–1 and T^–1

B
M⁰L¹T⁰ and T^–1

C
M L¹T^–1 and T^–2

D
M⁰L¹T^–1 and T

Solution
Question 4
4 / -1

The percentage errors in the measurement of mass and speed are 2% and 3% respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed :-

A
11%

B
8%

C
5%

D
1%

Solution

k = 1/2 mv²
percentage error in K = % error in m + 2 (% error in v)

% error in K = 2% + 2 (3%)

% error in k = 8%
Question 5
4 / -1

If a ball is thrown vertically upwards with speed u, the distance covered during the last ‘t’ seconds of its ascent is :–

A
ut

B
1/2 gt²

C
ut – 1/2 gt²

D
(u + gt)t

Solution

distance covered in t seconds of ascent will be equal to distance covered in t seconds of descent

so x = ut + 1/2 at²

u = 0

x = 1/2 gt²
Question 6
4 / -1

Directions For Questions

For a particle V – x graph is shown

...view full instructions

Corresponding a-x graph will be :-

A

B

C

D

Solution
Question 7
4 / -1

An aeroplane moving horizontally with a speed of 180 km/hr drops a food packet while flying at a height of 490 m. The horizontal range is :-

A
180 m

B
980 m

C
500 m

D
670 m

Solution
Question 8
4 / -1

A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be :- (take g = 10 m/s²)

A
4000/3 m

B
5000/3 m

C
2000 m

D
3000 m

Solution
Question 9
4 / -1

A monkey of 10 kg climbing on a massless rope whose breaking strength is 500 N. Find the maximum acceleration with which monkey can climb on rope :-

A
60 m/s²

B
40 m/s²

C
20 m/s²

D
None

Solution

T = m(g + a)

500 = 10 (10 + a)

10a = 400

a = 40 m/s²
Question 10
4 / -1

A 60 kg man stands on a spring scale in the lift. At some instant he finds, scale reading has changed from 60 kg to 50 kg for a while and then comes back to the original mark. What should we conclude :-

A
The lift was in constant motion upwards

B
The lift was in constant motion downwards

C
The lift while in constant motion upwards, is stopped suddenly

D
The lift while in constant motion downwards, is suddenly stopped.

Solution

For upward motion, R = m (g + a)

Here a = acceleration in upward direction

Initially a = 0

If the lift stops suddenly, the retardation comes into play.

Hence a will be negative i.e. R = m (g – a)

It means that reading of spring scale will be reduced and again a = 0, v = 0, R = mg