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Physics Test 97

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Physics Test 97
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Weekly Quiz Competition
  • Question 1
    4 / -1

    What should the width of each slit be to obtain 20 maxima of the double slit pattern within the central maximum of the single slit pattern ? (Distance between both slit = 2 mm)

    Solution

     

  • Question 2
    4 / -1

    For what distance is ray optics a good approximation when the aperture is 3 mm wide and the wavelength is 500 nm ?

    Solution

     

  • Question 3
    4 / -1

    In double slit experiment using light of wavelength 600 nm the angular width of a fringe formed on a distance screen is 0.1 degree. Find distance between both slits ?

    Solution

     

  • Question 4
    4 / -1

    Ratio of intensities of two light waves is given by 4 : 1. The ratio amplitudes of the waves is :-

    Solution

     

  • Question 5
    4 / -1

    In Y.D.S.E. λ = 4000 Å is used and fringes are formed at 2 m distance and has a fringe width of 0.6 mm. If whole of the experiment is performed in a liquid of refractive index 1.5 then width of the fringe will be

    Solution

     

  • Question 6
    4 / -1

    The slits in a Y.D.S.E.  have equal widths and the source is placed symmetrically relative to the slits. The intensity at the central fringe is I0/4. If one of the slits is closed, the intensity at this point will be :

    Solution

     

  • Question 7
    4 / -1

    Colours of thin films results from :-

  • Question 8
    4 / -1

    Ray diverging from a point source form a wave front that is

  • Question 9
    4 / -1

    In Y.D.S.E. max intensity is I then the position where the intensity becomes I/4 is :-

    Solution

    I/4 = I cos(ϕ/2) ⇒ f = 120o = 2π/3

    Δx = λ/3

    d sinθ = λ/3

    sin θ = λ/3d ⇒ θ = sin–1(λ/3d)

     

  • Question 10
    4 / -1

    In single slit diffraction pattern :-

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