Fractions & Decimals Test

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Fractions & Decimals Test - 1

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Question 1
1 / -0

The sum of 8 tens 21 tenths and 37 hundredths and 6 tens 19 hundredths and 56 thousandths is

A
144.716

B
142.716

C
141.560

D
139.726

Solution

8 tens 21 tenths and 37 hundredths
= 8 × 10 + + = 80 + 2.1 + 0.37 = 82.47
6 tens 19 hundredths and 56 thousandths
= 6 × 10 + + = 60 + 0.19 + 0.056 = 60.246
Required sum = 82.47 + 60.246 = 142.716
Question 2
1 / -0

In the product of 39.57 and 5, find the place value of digit '5'.

A
50

B
5

C
0.5

D
0.05

Solution

Required product: 39.57 x 5 = 197.85
The place value of digit 5 in 197.85 is 0.05.
Question 3
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Divide the sum of 5.9 and 0.95 by 5.

A
1.68

B
1.59

C
1.37

D
1.35

Solution

Sum = 5.9 + 0.95 = 6.85
Now, 6.85 ÷ 5 = 1.37
Question 4
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What is the value of 7587.9810 rounded to the nearest tenth?

A
7588

B
7590

C
7591

D
7593

Solution

To round the number to the nearest tenth, we will look at the digit at hundredths place. If the digit at hundredths place is 5 or more, then the digit at tenths place will be increased by 1.
Given number = 7587.9810
Digit at hundredths place = 8
So, the given number would be rounded to 7588.
Question 5
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In which of the following options are decimals arranged in descending order?

A
8.87, 8.89, 8.8

B
99.99, 99.9, 9.999

C
5.05, 5.02, 5.5

D
7.7, 7.75, 7.055

Solution

Descending order means from the highest to the lowest.
99.99 > 99.9 > 9.999
Hence, option (2) is correct.
Question 6
1 / -0

On Sunday, shop A sold kg of sugar and shop B sold kg of sugar. How much more sugar was sold by shop A than shop B?

A
kg

B
kg

C
kg

D
kg

Solution

Shop A sold = kg of sugar = = kg of sugar

Shop B sold = kg of sugar = kg of sugar

Therefore, required difference = = kg of sugar
Question 7
1 / -0

Find the fraction of unshaded parts in the following figure.

A

B

C

D

Solution

Total number of parts when divided equally = 12
Number of unshaded parts = 8
Therefore, required fraction =
Question 8
1 / -0

Alex's father bought a cake for Alex's birthday. The cake was divided into 11 equal pieces. Alex invited 8 friends over on his birthday and served one piece of cake to each of his friends. What fraction of cake was left with Alex?

A

B

C

D

Solution

Fraction of cake served to each friend =
Fraction of cake served to 8 friends = 8 x =
Fraction of cake left with Alex = 1 - =
Question 9
1 / -0

Find the product of 5 and the sum of 8715 thousandths and 199 hundredths. Round the answer to one decimal place.

A
53.5

B
53.4

C
53

D
53.6

Solution

Sum of and = 8.715 + 1.99 = 10.705
Now, required product = 10.705 x 5 = 53.525
Rounding 53.525 to 1 decimal place, we get 53.5.
Question 10
1 / -0

A chef is preparing a tomato sauce in which he uses spoon of garlic paste for every spoon of vinegar. How many spoons of vinegar will the chef use for 1 spoon of garlic paste?

A

B

C

D

Solution

Let spoon of garlic paste = spoon of vinegar
1 spoon of garlic paste = + + + +
For 1 spoon of garlic paste, the number of spoons of vinegar used
= + + + + =
Question 11
1 / -0

What fraction of the figure is shaded?

A

B

C

D

Solution

After rearranging the shaded parts, we get the following figure:

Fraction of figure shaded =
Question 12
1 / -0

The widths of two boards are 9.181 inches and 4 inches. Which option correctly compares the widths of these two boards?

A
4 > 9.181

B
4 = 9.181

C
4 < 9.181

D
None of these

Solution

4 = = 4.71
Therefore, 9.181 is greater than 4.71.
Hence, option 3 is correct.
Question 13
1 / -0

How many parts of the given figure must be shaded in order to make the fraction of unshaded parts ?

A
10

B
15

C
18

D
20

Solution

Total number of parts = 16
Fraction of unshaded parts =

So, fraction of shaded parts = 1 - =

Number of parts to be shaded = 16 x = 10
Question 14
1 / -0

Ammy thinks of a decimal number. After he subtracts 1.4 from it, multiplies the result by 4, and then adds 1.5 to it, he gets 13.5. What is the decimal number Ammy thought of?

A
2.5

B
2.8

C
3.6

D
4.4

Solution

Let the decimal number be X.
According to question, we have
(X - 1.4) x 4 + 1.5 = 13.5
(X - 1.4) x 4 = 12
(X - 1.4) = 3
X = 4.4
Question 15
1 / -0

Find the difference between 325.241 and 400.

A
74.052

B
74.562

C
74.759

D
75.236

Solution

Required difference = 400 - 325.241 = 74.759
Question 16
1 / -0

Which of the following options contains fractions arranged in ascending order?

A
,,

B
,,

C
,,

D
,,

Solution

We need to convert the given fractions into like fractions.
L.C.M of 4, 4 and 3 = 12

=

=

=

So, arranging them in ascending order, we get:

< <
Question 17
1 / -0

What is the value missing in the given mathematical equation?

0.50 × 8 = 0.50 × 2 + 0.50 × 2 + 0.50 × ___

A
2

B
4

C
6

D
8

Solution

Let the missing number be X.
Using distributive property, we get:
0.50 × 8 = 0.50 × (2 + 2 + X)
0.50 × 8 = (0.50 × 4) + (0.50 × X)
4 = 2 + 0.50X
2 = 0.50X
X = 2 ÷ 0.5
X = 4
Question 18
1 / -0

What is the value missing in the given mathematical equation?

4.50 ÷ 8 + 2 - (4.5 × 0.2) = ______ ×

A
11.4

B
15.3

C
17.6

D
18.4

Solution

Let the missing number be X.
Using BODMAS, we have:

4.50 ÷ 8 + - (4.5 × 0.2) = X

4.50 ÷ 8 + - 0.9 = X

0.5625 + 2.25 - 0.9 = X

1.9125 × 8 = X
15.3 = X
Question 19
1 / -0

Divide 51.23 by the difference between 73 tenths and 550 hundredths.

A
21.36

B
25.45

C
28.46

D
29.56

Solution

Difference between 73 tenths and 550 hundredths = 7.3 - 5.50
= 1.8
Now, 51.23 ÷ 1.8 = 28.46
Question 20
1 / -0

Which of the following options is true?

A
4.2356 > 4.3205

B
5.2364 < 5.1235

C
2.5236 < 2.6523

D
1.2356 > 1.4523

Solution

(1) 4.2356 > 4.3205 (Incorrect)
(2) 5.2364 < 5.1235 (Incorrect)
(3) 2.5236 < 2.6523 (Correct)
(4) 1.2356 > 1.4523 (Incorrect)
Question 21
1 / -0

Sapan takes hour to walk from his home to the school and hour to walk from the school to the park. How much time does it take him to walk from his home to the school and then to the park?

A
hour

B
hour

C
hour

D
hour

Solution

Sapan takes hour to walk from his home to the school and hour to walk from the school to the park.
Time he takes to walk from his home to the school and then to the park =
=

= hour
Question 22
1 / -0

A shopkeeper packed kg of flour in each of 64 bags. Find the total weight of flour he packed.

A
50 kg

B
51 kg

C
54 kg

D
56 kg

Solution

Weight of flour in 1 bag = kg
Weight of flour in 64 bags = = 56 kg
Question 23
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In a shopping mall, Ansh and Taran together spent Rs. 1818, and Ansh and Salman together spent Rs. 550. If Ansh spent of what Taran spent, then find the amount of money spent by Salman.

A
Rs. 135

B
Rs. 138

C
Rs. 142

D
Rs. 146

Solution

Amount spent by Ansh and Taran together = Rs. 1818
We are told that the amount of money spent by Ansh = of the amount of money spent by Taran
So, of amount of money spent by Taran + Amount of money spent by Taran = Rs. 1818

() of amount of money spent by Taran = Rs. 1818

of amount of money spent by Taran = Rs. 1818

Amount of money spent by Taran = 1818 x = Rs. 1414

So, amount of money spent by Ansh = = Rs. 404

And, amount of money spent by Ansh and Salman together = Rs. 550
Therefore, amount of money spent by Salman = 550 - 404 = Rs. 146
Question 24
1 / -0

Taranjot was solving a problem in which he needed to multiply 21.55 by 8. By mistake, he multiplied 2.115 by 8. What is the difference between the two values?

A
160.26

B
157.16

C
155.48

D
151.12

Solution

Original value = 21.55 × 8 = 172.4
Miscalculated value = 2.115 × 8 = 16.92
So, required difference = 172.4 - 16.92 = 155.48
Question 25
1 / -0

Gaurav played chess separately with two of his friends. He played chess with Goldy for hour and with Harman for hour. For how long did Gaurav play chess in total?

A
hour

B
hour

C
hour

D
hour

Solution

Time for which he played with Goldy = hour
Time for which he played with Harman = hour
Total time spent =
=

= hour

= hour
Question 26
1 / -0

_Evaluate .

A
19.17

B
18.42

C
24.79

D
23.53

Solution

₌

₌

=
Question 27
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Find the value of the following expression:

101.2 - 101.0 + 39.9 - 39.8 + 40.5 - 40.4 + 40.3 - 40.2 + 40.1 - 40 + 39.7 - 39.6 + 39.5 - 39.4 + 39.3 - 39.2 + 39.1 - 39.0 + 40.5 - 40.1

A
1.8

B
1.7

C
1.5

D
1.4

Solution

(101.2 - 101.0) + (39.9 - 39.8) + (40.5 - 40.4) + (40.3 - 40.2) + (40.1 - 40) + (39.7 - 39.6) + (39.5 - 39.4) + (39.3 - 39.2) + (39.1 - 39.0) + (40.5 - 40.1)
= 0.2 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.4
= 1.4
Question 28
1 / -0

Find the values of A, B, C and D:

A
A = 1, B = 1.0, C = , D = 1.5

B
A = , B = 0.3, C = , D = 2.5

C
A = , B = 0.6, C = , D = 1.7

D
A = 2, B = 2.0, C = 1, D = 1.0

Solution

Shaded portion in first figure =
Shaded portion in second figure =

Required values =
Question 29
1 / -0

Which of the following statements is CORRECT?

A
and are equivalent fractions.

B
hour is equal to 55 minutes.

C
2 cm is equal to .

D
hour is equal to 50 seconds.

Solution

2 cm = because 1 m = 100 cm
So, 2 cm =
Question 30
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Find the value of A x B + C using the following equations:

1. B + 26.8 = 28.8
2. 254.8 ÷ 9.8 = A
3. 187.5 - C = 87.5

A
148

B
152

C
156

D
157

Solution

B + 26.8 = 28.8
B = 2
254.8 ÷ 9.8 = A
A = 26
187.5 - C = 87.5
C = 100
A x B + C = 26 x 2 + 100
= 52 + 100
= 152