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Fractions & Decimals Test - 2

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Fractions & Decimals Test - 2
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  • Question 1
    1 / -0
    The sum of (6 tens 11 tenths and 32 hundredths) and (5 tens 15 hundredths and 38 thousandths) is
    Solution
    6 tens 11 tenths and 32 hundredths
    = 6 x 10 + +
    = 60 + 1.1 + 0.32
    = 61.42

    5 tens 15 hundredths and 38 thousandths
    = 5 x 10 + +
    = 50 + 0.15 + 0.038
    = 50.188

    Sum = 61.42 + 50.188 = 111.608
  • Question 2
    1 / -0
    In the division of 32.64 and 4, find the place value of digit '6'.
    Solution
    32.64 ÷ 4 = 8.16
    Place value of digit 6 in 8.16 = 0.06
  • Question 3
    1 / -0
    Multiply the difference of 4.9 and 0.89 by 7.
    Solution
    Difference = 4.9 - 0.89 = 4.01
    Product = 4.01 x 7 = 28.07
  • Question 4
    1 / -0
    What is 8050.329 rounded to the nearest hundredths?
    Solution
    When we round the numbers to nearest hundredth, we look at the thousandths place.
    In the given number the digit at the thousandths place is 9, which is greater than 5.
    Hence we round up the digit at the hundredths place, i.e. 2 becomes 3.
    So, 8050.329 rounded to the nearest hundredths is 8050.33
  • Question 5
    1 / -0
    Which of the following decimals are arranged in descending order?
    Solution
    When we have to arrange the numbers in descending order, we arrange them from largest to smallest.
    Now, the whole numbers are 11, 10 and 9.
    11.89 > 10.98 > 9.631
  • Question 6
    1 / -0
    During morning walk, Anita walked and Sunita walked . How much less did Anita walk than Sunita?
    Solution
    Anita walked = (Change mixed number into improper fraction)

    Sunita walked =

    Now make the fractions 'like fractions' (having same denominator).

    The LCM of 9 and 8 is 72.

    =
  • Question 7
    1 / -0
    Emma made the following figure in her drawing class. What fraction of the figure is shaded?


    Solution
    Total number of parts (Triangles in yellow) = 10
    Number of shaded parts = 5
    Fraction of shaded portion =
  • Question 8
    1 / -0
    Mia bought a chocolate bar. She gave of the chocolate bar to each of her 4 friends. What fraction of the chocolate bar is left with her?
    Solution
    Amount of chocolate bar given to 4 friends altogether =
    Amount of chocolate bar left = 1 -

  • Question 9
    1 / -0
    Find the sum of 12 and the difference of 569 hundredths and 3409 thousandths. (Round off the answer up to one decimal place.)
    Solution
    569 hundredths can be written as:

    = 5.69


    Similarly,

    = 3.409

    Difference = 5.69 - 3.409 = 2.281
    Sum = 12 + 2.281 = 14.281
    Round off your answer up to one decimal place = 14.3
    (We have to round it to nearest tenths, and the digit at the hundredths place is 8, which is greater than 5.)
  • Question 10
    1 / -0
    Mia uses m of red ribbon instead of every m of yellow color ribbon while decorating a frame. How many red ribbons will she use in place of 1 m yellow ribbon?
    Solution
    m of red ribbon = m of yellow ribbon

    1 m of yellow ribbon = m of yellow ribbon + m of yellow ribbon + m of yellow ribbon + m of yellow ribbon

    Replacing the length of the yellow ribbon with the red ribbon, we get:

    1 m of yellow ribbon = red ribbon + red ribbon + red ribbon + red ribbon = red ribbon
  • Question 11
    1 / -0
    What fraction of the given figure is not shaded?


    Solution
    Number of total parts = 16
    Number of parts which are not shaded = 10
    Fraction of parts which are not shaded =

  • Question 12
    1 / -0
    The length of two photo frames is 7.250 inches and inches. Which option correctly compares the lengths of these frames?
    Solution
    Covert mixed fraction into decimal form = = 7.25
    So, both of these are equal.
    Hence, option 3 is correct.
  • Question 13
    1 / -0
    How many small triangles (of equal sizes) in the given figure must be left unshaded when th of the figure is shaded?

    Solution
    Number of small triangles = 32
    Shaded fraction =
    Fraction of triangles which are not to be shaded = 1 -
    Therefore, number of triangles which will remain unshaded =
  • Question 14
    1 / -0
    Mia was thinking of a decimal number. After that she added 3.5 to it, divided the result by 4 and then subtracted 2.3 from it, she got 0.7. What is the decimal number about which Mia was thinking?
    Solution
    The number equation according to the question:









    ? + 3.5 = 12

    ? = 12 - 3.5

    ? = 8.5
  • Question 15
    1 / -0
    Find the sum of 561.126 and 401.
    Solution
    The sum can be calculated as:
    561.126 + 401.000 = 962.126

  • Question 16
    1 / -0
    Which of the following fractions are in order from the greatest to the least?
    Solution
    To find the answer, we need to make the denominators same.
    This can be done by taking the LCM.
    LCM of 3,4 and 12 is 12.








    =

    Hence, option 1 is correct.
  • Question 17
    1 / -0
    What is the missing value in the below given mathematical statement?

    0.75 x 4 + 1.25 x 10 + 2.50 x 2 = 0.5 x ?
    Solution
    0.75 x 4 + 1.25 x 10 + 2.50 x 2 = 0.5 x ?
    3 + 12.5 + 5 = 0.5 x ?
    20.5 = 0.5 x ?
    ? = 20.5 ÷ 0.5
    ? = 41
  • Question 18
    1 / -0
    Find the missing value.

    3.25 - 10 x + ( 32.4 ÷ 2) = - ?
    Solution
    Let the missing number = x

    3.25 - 10 x + ( 32.4 ÷ 2) = - x

    3.25 - 10 x + 16.2 = - x

    3.25 - 22 + 16.2 = - x

    3.25 + 16.2 - 22 = - x

    19.45-22 = -x.

    x = + 22 - 19.45
    x = + 2.55

    x =

    x = 3.35
  • Question 19
    1 / -0
    Multiply 30 by the sum of 99 tenths and 630 thousandths.
    Solution
    We know that 99 tenths = = 9.9
    Also,
    630 thousandths = = 0.630 = 0.63

    Difference = 9.9 - 0.63 = 9.27
    Product = 30 x 9.27 = 278.1
  • Question 20
    1 / -0
    Which of the following options is true?
    Solution
    To compare the decimal numbers we start from left hand side.
    In option 2, the digit at the ones and tenths place are same.
    However, digit at the hundredths place is bigger for the second number.
    Hence, only option 2 is correct.
  • Question 21
    1 / -0
    Simran went to market to buy shoes and then to restaurant. She took hour to go to market to buy shoes and hour to go to restaurant from market. How much time, in total, did she take in going to market and then to restaurant?
    Solution
    Time taken in going to market = hour
    Time taken in going to restaurant from market = hour

    Hence, total time taken = + = = hour

  • Question 22
    1 / -0
    Samar donated 308 packets of rice in an orphanage and the weight of each packet is kg. What was the total weight of rice donated by him?
    Solution
    Weight of 1 packet = kg
    Therefore, weight of 308 packets = = 192.5 kg
  • Question 23
    1 / -0
    Thomas, Venin and Liah went to a restaurant for dinner. Thoman and Venin gave Rs. 864, whereas Venin and Liah gave Rs. 1254 for bill. After calculating, they got to know that Venin gave of what Liah gave. How much did Thomas spend?
    Solution
    Amount of money given by Venin = of money given by Liah

    Amount of money given by Venin and Liah = Rs. 1254

    of money given by Liah + amount of money given by Liah = Rs. 1254

    ( + 1) amount of money given by Liah= Rs. 1254

    = x amount of money given by Liah = Rs. 1254
    Amount of money given by Liah = = Rs. 912
    = Therefore, amount of money Venin spent = x 912 = Rs. 342

    Amount of money spent by Thomas = 864 - 342 = Rs. 522
  • Question 24
    1 / -0
    Saloni bought 8 chocolates costing Rs. 78.25 each. While calculating the total cost that she had had to pay, she multiplies 7.825 with 8, instead of 78.25 with 8. What will be the difference in both the amounts?
    Solution
    Cost of 8 chocolates = = Rs. 626

    Calculation done by Saloni = = Rs. 62.6

    Difference = 626 - 62.6 = Rs. 563.4
  • Question 25
    1 / -0
    Malkeet went to his relative Gautam's house. He spent hour there and then he went to his friend Rohit's house and spent hour there. After that he came home. How much time did he spend at his relative and his friend's house altogether?
    Solution
    Time spent at Gautam's house = hour
    Time spent at Rohit's house = hour
    Total time spent by him = +

    =

    = hour
  • Question 26
    1 / -0
    Evaluate:


    Solution
    We have:




    =

    =

    =

    =

    = = 6
  • Question 27
    1 / -0
    Find the value of missing number in the following equation.

    16.25 - 3.15 + 87.32 - 8.22 + 65.45 - 64.35 + 19.38 - 17.28 + 54.34 - 53.24 + ___ = 264.5
    Solution
    16.25 - 3.15 + 87.32 - 8.22 + 65.45 - 64.35 + 19.38 - 17.28 + 54.34 - 53.24 + ___ = 264.5

    (16.25 - 3.15) + (87.32 - 8.22) + (65.45 - 64.35) + (19.38 - 17.28) + (54.34 - 53.24) + ___ = 264.5



    13.1 + 79.1 + 1.1 + 2.1 + 1.1 + ___ = 264.5


    = 96.5 + x = 264.5

    x = 264.5 - 96.5 = 168
  • Question 28
    1 / -0
    A is the sum of fraction of shaded portion of all the squares in Row-I. C is the sum of all the fraction of shaded portion for all squares in Row - II. B and D represents the decimal values of the A and C resp. Find the values of A, B, C and D.


    Solution
    Shaded fraction in first figure = = =
    A = =

    B = 2.25
    Now, shaded fraction in second figure = = =
    C =

    D = 2.75
  • Question 29
    1 / -0
    Choose the incorrect statement

    A. There are kg in a gram.

    B. is equivalent to .

    C. of an hour = 45 minutes

    D. 1 ton = 10000 kg
    Solution
    A. As there are 1000 grams in a Kg.
    Therefore, there will be kg in a gram.
    B. =

    C. of an hour = x 60 = 45 minutes

    D. There are 1000 kg in a ton. Hence, option 4 is incorrect.
  • Question 30
    1 / -0
    Find the value of



    (i) 5.8 x A = 245.34

    (ii) 1373.36 - 895.36 = B

    (iii) C + 2442.86 = 3834.56
    Solution
    (i) 5.8 x A = 245.34
    A = 245.34 ÷ 5.8
    A = 42.3

    (ii) 1373.36 - 895.36 = B
    B = 478

    (iii) C + 2442.86 = 3834.56
    C = 3834.56 - 2442.86 = 1391.7

    Now,
    A + C = 42.3 + 1391.7 = 1434
    (A + C) ÷ B
    1434 ÷ 478 = 3
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