Measurement Test

Result

Measurement Test - 2

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Five bottles of jams of equal weight weigh 750 g. One jar of jam weighs 200 g. How much lighter is a bottle of jam than one jar?

A
75 g

B
125 g

C
50 g

D
100 g

Solution

Weight of 5 bottles of jam = 750 g
Weight of 1 bottle of jam = = 150 g
Weight of 1 jar of jam = 200 g
Difference in weight = 200 g - 150 g = 50 g
One bottle of jam is 50 g lighter than one jar of jam.
Hence, option (3) is correct.
Question 2
1 / -0

Which of the following temperatures is the hottest?

A
23^oC

B
13^oC

C
27^oC

D
43^oC

Solution

If we arrange the temperatures in ascending order, the following result will be obtained:
13^οC < 23^oC < 27^oC < 43^oC
According to this arrangement, 43^oC is the hottest.
Hence, option (4) is correct.
Question 3
1 / -0

How long did Riya take to complete her painting?

A
1 hour

B
70 minutes

C
2 hours

D
90 minutes

Solution

She started painting at 11:55 a.m.
She completed the painting at 01:25 p.m.
Time duration from 11:55 a.m. to 12:55 p.m. = 1 hour
Time duration from 12:55 p.m. to 01:25 p.m. = 30 minutes
We know that 1 hour = 60 min.
So Total time duration = 1 hour 30 minutes = (60+30) minutes = 90 minutes
Hence, option (4) is correct.
Question 4
1 / -0

C and D are two boxes of chocolates. Box D being the bigger box has more chocolates than Box C. If there are 6 times more chocolates in Box D as compared to Box C, then how many chocolates do we need to transfer from Box D to Box C so that each box will have 56 chocolates in it?

A
44

B
42

C
40

D
50

Solution

Let the number of chocolates in Box C be x.
Number of chocolates in Box D = 6x
Total number of chocolates in both the boxes = 56 + 56
x + 6x = 112
7x = 112
x = 16
So, there are 16 chocolates in Box C and 96 chocolates (16 x 6) in Box D.
So, number of chocolates that are needed to be transferred = 96 - 56 = 40
Hence, option (3) is correct.
Question 5
1 / -0

Two pencils of different lengths are shown in the given figure. What is the difference between the lengths of the pencils?

A
2.3 cm

B
2 cm

C
3 cm

D
3.5 cm

Solution

Length of pencil A = 7.3 cm
Length of pencil B = 5 cm
Difference between the lengths = 7.3 - 5 = 2.3 cm
Hence, option (1) is correct.
Question 6
1 / -0

What temperature is shown by the given thermometer?

A
10^οC

B
50^οF

C
59^οF

D
5^οC

Solution

The given thermometer shows 59^οF.

Hence, option (3) is correct.
Question 7
1 / -0

Riya and Anjali have drumsticks with them. The length of the drumstick that Riya has is 1.3 m. Anjali has a drumstick that is 5 times as long as the stick of Riya. What is the total length of the both the drumsticks?

A
4.8 m

B
6.5 m

C
7.8 m

D
5.5 m

Solution

Length of Riya's drumstick = 1.3 m
Length of Anjali's drumstick = 5 times the length of Riya's drumstick = 5 x 1.3 = 6.5 m
Total length = 6.5 m + 1.3 m = 7.8 m
Hence, option (3) is correct.
Question 8
1 / -0

A shopkeeper sold some candies from a jar. He had of the candies remaining in the jar. He put 40 more candies in the jar to fill it completely. What was the full capacity of the jar?

A
56 candies

B
48 candies

C
40 candies

D
72 candies

Solution

Number of candies remaining in the jar =
Number of candies sold = 1 - =
Let the full capacity of the jar be X.
of X = 40 candies
X = = 72 candies
Hence, option (4) is correct.
Question 9
1 / -0

In the morning, when Akash went for a movie, the temperature outside was 34^οC. When he came back in the afternoon, the temperature had increased by 6^οC; and in the evening when he met his friend in a park, the temperature had decreased by 4^οC. What was the temperature when he met his friend?

A
32^οC

B
34^οC

C
36^οC

D
38^οC

Solution

Temperature in the morning = 34^οC
In the afternoon, it had increased by 6^οC.
So, Increased temperature = 34^οC + 6^οC = 40^οC
In the evening, it had decreased by 4^οC.
So, 40^οC - 4^οC = 36^οC
When he met with his friend the temperature was 36^οC
Hence, option(3) is correct.
Question 10
1 / -0

Mohit worked for 6 hours on the last Saturday in the office. For how many minutes did he work?

A
384

B
530

C
830

D
320

Solution

hours = hours
1 hour = 60 minutes
hours = = 384 minutes
Hence, option (1) is correct.
Question 11
1 / -0

The following time was shown on Aryan's and Sam's watches when the actual time was 3:40 p.m.

Calculate the time shown by Aryan's watch when the actual time was quarter past 5 in the evening.

A
16:16

B
17:15

C
17:23

D
16:25

Solution

Actual time = 03:40 p.m. = 15:40
So, Aryan's watch was 8 minutes fast.
If it was 17:15 in the evening, then Aryan's watch would show 17:23.
Hence, option (3) is correct.
Question 12
1 / -0

The following time was shown on Aryan's and Sam's watches when the actual time was 3:40 p.m.

Calculate the time on Sam's watch when the time on Aryan's watch is half past 6.

A
18:39

B
17:39

C
18:25

D
17:30

Solution

Actual time = 03:40 p.m. = 15:40
So, Aryan's watch was 8 minutes fast.
Sam's watch was 17 minutes fast (9 minutes more than Aryan's watch).
Time on Aryan's watch = 18:30
Time on Sam's watch = 18:39 (9 minutes more than Aryan's watch)
Hence, option (1) is correct.
Question 13
1 / -0

Aman and Karan bought some vegetables. Karan bought four times the quantity of vegetable that Aman bought. If Karan bought 4 kg and 160 g of the vegetable, then how much vegetable did Aman buy?

A
2 kg and 20 g

B
2 kg and 40 g

C
1 kg and 20 g

D
1 kg and 40 g

Solution

Karan bought 4 kg and 160 g of vegetables or it can be written as 4.16 kg
Aman bought 4 times lesser than the quantity that Karan bought.
Let the quantity of vegetables bought by Aman be x.
Then ,
4x = 4.16 kg
x = = 1.04 or 1 kg and 40 g
So, Aman bought 1 kg and 40 g of vegetables.
Hence, option (4) is correct.
Question 14
1 / -0

Directions: Consider the following weight balances and answer the question that follows.

What is the weight of A?

A
6 kg

B
8 kg

C
10 kg

D
12 kg

Solution

Weight of two D's = 8 kg
Weight of one D = 4 kg
Weight of C + Weight of D = 12 kg
Therefore, weight of C = (12 - 4) kg = 8 kg
Weight of C + Weight of A = 14 kg
8 kg + Weight of A = 14
Weight of A = (14 - 8) kg = 6 kg
Hence, option (1) is correct.
Question 15
1 / -0

If is the difference between 6.40 kg and 4.60 kg, and is thrice the value of , then what is the value of ?

A
2.80 kg

B
3.60 kg

C
4.50 kg

D
5.40 kg

Solution

According to the question, we have
= (6.40 - 4.60) kg = 1.80 kg
= 3 () = 3 x 1.80 kg = 5.40 kg
Hence, option (4) is correct.
Question 16
1 / -0

Saurabh made 4.8 L of mango shake. Naveen made twice as much mango shake as Saurabh made. How much mango shake did they make altogether?

A
10.2 L

B
12.8 L

C
14.4 L

D
16.6 L

Solution

Quantity of mango shake Saurabh made = 4.8 L
Quantity of mango shake Naveen made = 2 x 4.8 L= 9.6 L
So, total quantity of mango shake they made altogether = (4.8 + 9.6) L = 14.4 L
Hence, option (3) is correct.

Question 17

1 / -0

Raw mangoes	Rs. 40 per kg
Sour mangoes	Rs. 45 per kg
Ripe mangoes	Rs. 50 per kg

The table given above shows the prices of 3 different types of mangoes. Shruti purchased of raw mangoes, of sour mangoes and the rest were ripe mangoes. If Shruti spent a total amount of Rs. 750 on the raw and sour mangoes, then how much did she spend on the ripe mangoes?

Rs. 18

Rs. 22

Rs. 28

Rs. 32

Solution

Let the total number of mangoes be x.
Number of raw mangoes =
Number of sour mangoes =
Number of ripe mangoes = x - =
Now, = 750
=750
=750
x = =36
Amount spent on ripe mangoes = = Rs. 18
Hence, option (1) is correct.

Question 18
1 / -0

Rajesh pours 3 L and 200 mL of water equally into 8 glasses. How much water is there in each glass?

A
300 mL

B
400 mL

C
500 mL

D
600 mL

Solution

Total quantity of water = 3 L and 200 mL = 3.2 L
Number of glasses = 8
Quantity of water in 1 glass = (3.2 ÷ 8) L= 0.400 L = 400 mL
Hence, option (2) is correct.
Question 19
1 / -0

Hitesh's bottle has 2 L and 125 mL of lemonade in it, while his jug has 5 L and 450 mL of lemonade in it. How much lemonade is there in both the jug and bottle altogether?

A
5 L and 345 mL

B
6 L and 465 mL

C
7 L and 575 mL

D
8 L and 685 mL

Solution

Quantity of lemonade in the bottle = 2 L and 125 mL
Quantity of lemonade in the jug = 5 L and 450 mL
Total quantity of lemonade = (2 L and 125 mL) + (5 L and 450 mL)
= 7 L and 575 mL
Hence, option (3) is correct.
Question 20
1 / -0

Surabhi had 195 kg of wheat. She poured of it into a wheat-storage container and packed of the remainder into 13 bags. How much wheat was there in each bag?

A
6 kg

B
8 kg

C
10 kg

D
12 kg

Solution

Total quantity of wheat Surabhi had =195 kg
Quantity of wheat poured into the container = = 78 kg
Quantity of wheat left = 195 - 78 = 117 kg
So, quantity of wheat to be packed in the bags = = 78 kg
Number of bags = 13
Quantity of wheat in each bag = 78 ÷ 13 = 6 kg
Hence, option (1) is correct.
Question 21
1 / -0

A table costs Rs. 25 more than a chair. The total cost of 3 such tables and 7 such chairs is Rs. 550. What is the cost of one chair?

A
Rs. 43.5

B
Rs. 45.5

C
Rs. 47.5

D
Rs. 49.5

Solution

The cost of 1 table is Rs. 25 more than that of 1 chair.
Cost of 3 tables and 7 chairs = Rs. 550
Cost of (3 x tables + 7 x chairs) = Rs. 550
Cost of (3(Rs. 25 + 1 chair) + 7 chairs) = Rs. 550
Rs. 75 + Cost of (3 chairs + 7 chairs) = Rs. 550
Cost of 10 chairs = Rs. (550 - 75) = Rs. 475
Cost of 1 chair = Rs. (475 ÷ 10) = Rs. 47.5
Hence, option (3) is correct.
Question 22
1 / -0

Harpreet had 18.25 m of piece of cloth. He cutit into 8 smaller pieces, each of length of 1.25 m. How many metres of cloth were left?

A
8.25 m

B
9.25 m

C
10.25 m

D
11.25 m

Solution

Total length of the piece of cloth = 18.25 m
Length of 1 small piece of cloth = 1.25 m
Length of 8 small pieces of cloth = 8 x 1.25 = 10 m
Length of the remaining piece of cloth = (18.25 - 10) m = 8.25 m
Hence, option (1) is correct.
Question 23
1 / -0

340 g of tiny yellow marbles are mixed with 360 g of tiny red marbles. Himesh packed the mixture of tiny marbles into 7 bags of same weight. How many grams of the mixture are there in each bag?

A
70 g

B
80 g

C
90 g

D
100 g

Solution

Weight of the mixture = (340 + 360) g = 700 g
Number of bags = 7
Weight of the mixture in each bag = (700 ÷ 7) g = 100 g
Hence, option (4) is correct.
Question 24
1 / -0

A cloth retailer had a piece of ribbon. He cut 5 smaller pieces of ribbon, each measuring . If he was left with of ribbon, find the total length of the ribbon.

A
7 m

B
8 m

C
9 m

D
10 m

Solution

Length of 1 small piece =
Length of 5 smaller pieces =m =
Length of the ribbon left = =
Total length of the ribbon = = = 9m
Hence, option (3) is correct.
Question 25
1 / -0

Heena can walk from point X to point Y and return to point X in 1 hour. She can walk there and cycle back in 40 minutes. How much time will she take to cycle there and cycle back?

A
20 minutes

B
30 minutes

C
40 minutes

D
25 minutes

Solution

Total time taken to walk from point X to point Y and return from point Y to point X = 1 hour
Time taken to walk from point X to point Y = 30 minutes
Total time taken to walk from point X to point Y and to cycle back from point Y to point X = 40 minutes, i.e.
Time taken to walk from point X to point Y + Time taken to cycle from point Y to point X = (30 + 10) minutes
Time taken to cycle from Y to X = 40 - 30 = 10 minutes
Total time taken to cycle from X to Y and to cycle back from Y to X = 10 + 10 = 20 minutes
Hence, option (1) is correct.
Question 26
1 / -0

Nikita made 21.5 L of orange juice for a festival. Jasmine made 2.5 L more orange juice than Nikita. At the end of the day, Jasmine had sold of her orange juice. Also, Jasmine had four times as much orange juice left with her as Nikita had. How much orange juice did Nikita sell?

A
16.5 L

B
17.5 L

C
18.5 L

D
19.5 L

Solution

Quantity of orange juice Nikita made = 21.5 L
Quantity of orange juice Jasmine made = (2.5 + 21.5) L = 24 L
Quantity of orange juice Jasmine sold = x 24 = 16 L
Quantity of orange juice left with Jasmine = (24 - 16) L = 8 L
Jasmine is left with 8 L which is 4 times the juice Nikita had after selling.
Juice left with Jasmine = 4 Juice left with Nikita
So, quantity of orange juice left with Nikita = L = 2 L
Quantity of orange juice Nitika sold = (21.5 - 2) L = 19.5 L
Hence, option (4) is correct.
Question 27
1 / -0

A pink piece of cloth is 3 m and 68 cm long and it is half as long as a yellow piece of cloth. Jessica used m of the yellow piece of cloth to stitch a frock. She then cut the rest of the yellow piece of cloth into 6 equal pieces to use it in another dress. Calculate the length of each remaining piece of yellow cloth.

A
0.65 m

B
0.75 m

C
0.81 m

D
0.85 m

Solution

Length of pink piece of cloth = 3 m 68 cm = 3.68 m
Length of yellow cloth = 2 length of pink cloth
Length of yellow cloth = 3.68 2 m = 7.36 m
Length of yellow cloth Jessica used = m = m = 2.5 m
Length of remaining piece of yellow cloth = 7.36 - 2.5 = 4.86 m
Number of pieces cut of equal length = 6
Length of each piece = (4.86 ÷ 6) m = 0.81 m
Hence, option (3) is correct.
Question 28
1 / -0

Directions: Consider the following weight balances and answer the question that follows.

What is the weight of W?

A
6 kg

B
7 kg

C
8 kg

D
9 kg

Solution

Weight of K = = 7 kg
Now, weight of K + weight of L = 16 kg
Weight of L = (16 - 7) = 9 kg
Weight of W and L = 18 kg
Weight of W = (18 - 9) kg = 9 kg
Hence, option (4) is correct.
Question 29
1 / -0

The given chart shows the weights of pebbles. What is the weight of pebble J?

A
220 g

B
330 g

C
340 g

D
350 g

Solution

Weight of H + J + J = 720 g ... (1)
Weight of J + B + W = 700 g ... (2)
Weight of H + W + B = 760 g ... (3)

From (1);
H = 720 - 2J ...(4)

From (2);
B + W = 700 - J ...(5)

Equation (3);
B + W + H = 760

700 - J + 720 -2J = 760 ...(from 4 and 5)

1420 - 3J = 760

1420 - 760 = 3J

J = 220
Question 30
1 / -0

A
kg

B
kg

C
kg

D
kg

Solution

Here, = Rabbit
= Mouse
= Cat
Now, weight of a rabbit = kg (given)
Weight of a mouse + 1 kg = kg (weight of a rabbit)

Weight of a mouse = - 1 = = kg
In second weight balancing machine,
Weight of 2 mice = Weight of a cat
Weight of a cat = Weight of mouse + Weight of a mouse = kg