Statistics Test

Result

Statistics Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

The given data shows the runs scored by Rahul Dravid in the first ten one day matches of his career.

110 82 94 181 186

81 78 93 127 78

The range of the data is ______.

A
100

B
110

C
108

D
132

Solution

Range of data is defined as the difference between two extreme observations of distribution
Or range = maximum value - minimum value.

Maximum value = 186
Minimum value = 78
So, Range = 186 - 78 = 108

Question 2

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Class Interval	Frequency
0 - 10	a
10 - 20	b
20 - 30	c
30 - 40	d
40 - 50	f
50 - 60	d
60 - 70	h
70 - 80	i
80 - 90	j
90 - 100	k

If 'f' is the highest frequency of the given data, then which of the following values is nearest to the mode?

30

32

45 Cannot be determined

Solution

Since 'f' is the highest frequency and succeeding and preceding frequencies are the same, so mode = 45.

Question 3
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The mean, median and mode for the following set of data are equal.

{-30, -40, -80, -50, a}

Which of the following is a possible value of a?

A
-30

B
-40

C
-50

D
30

Solution

Go with the options.

If a = -30, mode = -30 and mean = -(30 + 30 + 40 + 50 + 80)/5 = -46
Since mode is not equal to mean for a = 30, so this option is not true.

If a = -40, mode = -40 and mean = -(30 + 40 + 40 + 50 + 80)/5 = -48
Since mode is not equal to mean for a = 40, so this option is not true.

If a = -50, mode = -50, mean = -(30 + 40 + 50 + 50 + 80)/5 = -50 and median = -50
Since mode = Mean = Median for a = -50, so this option is true.
Question 4
1 / -0

The median of set of 9 distinct observations is 20.5. If each of the largest 4 observations of the set is increased by 2, then the median of the new set

A
is increased by 2

B
is decreased by 2

C
is two times the original median

D
remains the same as that of the original set

Solution

Let 9 observations arranged in ascending order be a, b, c, d, e, f, g, h and i.
Its median is e.

If the largest 4 observations is increased by 2 then, the arrangement is a, b, c, d, e, f + 2, g + 2, h + 2 and i + 2.

Now, the new median again is e.

So, the median remains the same as that of the original set.