Statistics Test

Result

Statistics Test - 4

Score
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out of -
Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1
1 / -0

What is the mode of the following data, if the students are standing according to the marks they scored in the class?

51, 58, 56, 96, 85, 75, 87, 23, 25, 56, 57, 66, 69, 85, 45, 96, 52, 43, 85, 99, 92, 47, 59 and 66.

A
85

B
75

C
69

D
66

Solution

Arrange the data in ascending order,
23, 25, 43, 45, 47, 51, 52, 56, 56, 57, 58, 59, 66, 66, 69, 75, 85, 85, 85, 87, 92, 96, 96 and 99

Since 85 comes three times.
So, 85 is the mode.

Question 2

1 / -0

Find the mode of the fee paid by the students of the college.

Fee paid	No. of the student
Rs. 20000	12
Rs. 30000	17
Rs. 40000	11
Rs. 50000	21
Rs. 60000	15
Rs. 70000	19
Rs. 80000	16

Rs. 60,000

Rs. 50,000

Rs. 40,000

Rs. 30,000

Solution

The arithmetic mode of the given data is Rs. 50 000 as the highest frequency 21 is associated with Rs. 50,000.

Question 3
1 / -0

The mean of 20 observations is p. If each observation is multiplied by 3 and then 1 is added to it, the new mean obtained will be

A
3p + 20

B
p + 20

C
3p + 1

D
3(p + 1)

Solution

Mean of 20 observations is p.
So, sum of the observations will be 20p.

When each observation is multiplied by 3, the mean will become (3 x 20p)/20
When 1 is added to each observation, new mean will be (20 + 60p)/20

So, new mean obtained after multiplying each observation by 3 and adding 1 to it = (20 + 60p)/20 = 3p + 1.
Question 4
1 / -0

If the median of a set of 7 distinct observations is 40.5 and each of the largest 3 observations of the set is increased by 17.5, then what will be the change in the median?

A
14

B
0

C
1.5

D
17.5

Solution

The median is the middle of a sorted list of numbers.
When the number of observations is odd, the median is the middle value.

When the number of observations is even, the median is the average of the two middle values.
Here, 7 is the odd number and median is 40.5.

So, when we increase the last three values by 17.5 there will be no change in the median as it is the 4th term.

Therefore, net change is zero.
Question 5
1 / -0

Find the difference between the ranges of the given data sets.

Set 1 89 73 84 91 87 77 94

Set 2 78 67 85 69 70 73 56

A
6

B
7

C
8

D
9

Solution

Range of the 1^st data set = 94 - 73 = 21
Range of the 2^nd data set = 85 - 56 = 29
Difference between the ranges = 29 - 21 = 8