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Weekly Quiz Competition
  • Question 1
    1 / -0

    What will be the breadth of a rectangle whose length and perimeter are 60 cm and 200 cm, respectively?

    Solution

    Let the length of the rectangle be denoted by l and the breadth be denoted by b. (both being in cm)
    Now, l = 60.
    Also, 2(l + b) = 200
    Substituting for the value of l in the above equation, we get b = 40.
    Thus, the breadth of the rectangle = 40 cm.

     

  • Question 2
    1 / -0

    What will be the cost of fencing an orchard of length 250 m and breadth 200 m by 4 rounds of barbed wire at a rate of Rs. 30 per metre?

    Solution

    Length of orchard = 250 m, and Breadth = 200 m
    Barbed wire required for 1 round = Perimeter of the orchard
    = 2 × (250 + 200) = 2 × 450 = 900 m
    Number of rounds = 4
    Length of the wire required for fencing = 900 × 4 = 3600 m
    Total cost = 3600 × 30 = Rs. 1,08,000

     

  • Question 3
    1 / -0

    I am a rectangular cloth. I have whole number dimensions. I occupy 24 square metre area. What should be the magnitudes of my length and breadth so that I can cover a rectangular wooden cardboard with largest possible perimeter?

    Solution

    Here the area of the table cloth = 24 square cm
    Then we have to find the length and breadth with largest possible perimeter.
    The possible factors of 24

    Case I : 24 = 1×24
    If length is 24 cm and breadth = 1 cm
    The perimeter = 2× (24 + 1)

    = 2× 25
    = 50 cm
    Case II: 24 = 2×12

    If length is 12 cm and breadth = 2 cm
    then perimeter = 2× (12 + 2)
    = 2× 14
    = 28 cm

    Case III:- 24 = 3×8
    If length is 8 cm and breadth = 3 cm
    the perimeter = 2× (8 + 3)

    = 2× 11
    = 22 cm

    Case IV: 24 = 4× 6
    If length is 6 cm and breadth = 4 cm

    then perimeter = 2× (6 + 4)
    = 2× 10
    = 20 cm

     

  • Question 4
    1 / -0

    The dimensions of the floor of a dining room are 15 m × 12 m. A square carpet of side 10 m is spread in the middle of this room. How much area of this room is not carpeted?

    Solution

    Length of the room = 15 m
    Breadth of the room = 12 m

    The area of the room = Length × Breadth
    = 15 × 12
    = 180 m2

    The side of square carpet = 10 m
    Area of the carpet = (Side)2
    = 10× 10
    = 100 m2

    Uncarpeted area = 180 - 100
    = 80 m2

     

  • Question 5
    1 / -0

    What is the length of the altitude of a triangle with base 30 cm and area 240 square cm?

    Solution

    area = 1/2 x altitude x base
    240 cm2 = 1/2 x alt. x 30 xcm
    therefore, altitude = 16 cm

     

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