Self Studies
Self Studies
Self Studies
Self Studies
Selfstudy
Selfstudy

KVPY (SA) Mock Test - 10

Result Self Studies

KVPY (SA) Mock Test - 10
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1.25 / -0
    The average of two non-negative integers x and y is 4. How many pairs of (x, y) satisfy this condition?
    Solution
    Total = Average x No. of terms
    Here, total sum of x + y should be equal to 8.
    Possible pairs of x and y are (0, 8), (1, 7), (2, 6), (3, 5), (4, 4), (5, 3), (6, 2), (7, 1), (8, 0)
    Hence, total 9 pairs satisfy the condition.
  • Question 2
    1.25 / -0
    The number of real solution(s) of the equation -2 = x2 - x = 2x is
    Solution
    -2 = x2 - x
    -2 - (x2 - x) = 0
    -2 - = 0
    , not true for any x ∈ R and 2x ≥ 0 for all x ∈ R
    Hence, the given equation has no real solution.
  • Question 3
    1.25 / -0
    In a certain school, 71% students like cricket, 76% students like football and 82% students like tennis. Then, all the three sports are liked by at least
    Solution
    Suppose number of students in a class = 100
    So, the number of students who like cricket = n(c) = 71
    Number of students who like football = n(f) = 76, and
    Number of students who like tennis = n(t) = 82
    From the above three, we can find the number of students who at least like two games
    n(C F) = 56, n(F T) = 58 and n(T C) = 53
    So, n(C F T) = n(C F T) - n(C) - n(F) - n(T) + n(C F) + n(F T) + n(T C)
    n(C F T) = 100 - 71 - 76 - 82 + 56 + 58 + 53 = 38
    Hence, all the three sports are liked by at least 38% students.
  • Question 4
    1.25 / -0
    Find the time taken (in seconds) by two trains to cross each other if they are running at the speeds of 46 kmph and 54 kmph, respectively in the same direction. It is given that the length of one train is 210 m and of the other train is 270 m.
    Solution
    Relative speed = 54 – 46 = 8 kmph
    Relative speed = 8 × 5/18 = 20/9 m/s
    Distance to be covered = 210 + 270 = 480 m
    Time = 480 × 9/20 = 216 seconds
  • Question 5
    1.25 / -0
    One of the factors of x3 + 8y3 + 27z3 – 18xyz is
    Solution
    x3 + 8y3 + 27z3 – 18xyz
    x3 + (2y)3 + (3z)3 – 18xyz
    (x + 2y + 3z) (x2 + 4y2 + 9z2 – 2xy – 6yz – 3zx)
  • Question 6
    1.25 / -0
    Let tn be the number of integral-sided triangles with distinct sides chosen from {1, 2, 3, ……., n}. Then, t20 - t19 equals
    Solution
    T20 = T19 + (T20 with largest side 20)
    Largest side is 20 and another side is a and b.
    a + b > 20
    Suppose a = 2, then the number of possible values of b is 1, b has only b = 19
    and for a = 3, the number of possible values of b is 2, and b = 18, 19
    for a = 4, the number of possible values of b is 3, and b = 17, 18, 19
    for a = 5, the number of possible values of b is 4, and b = 16, 17, 18, 19
    for a = 6, the number of possible values of b is 5, and b = 15, 16, 17, 18, 19
    for a = 7, the number of possible values of b is 6, and b = 14, 15, 16, 17, 18, 19
    for a = 8, the number of possible values of b is 7, and b = 13, 14, 15, 16, 17, 18, 19
    for a = 9, the number of possible values of b is 8, and b = 12, 13, 14, 15, 16, 17, 18, 19
    for a = 10, the number of possible values of b is 9, and b = 11, 12, 13, 14, 15, 16, 17, 18, 19
    for a = 11, the number of possible values of b is 8, and b = 12, 13, 14, 15, 16, 17, 18, 19
    for a = 12, the number of possible values of b is 7, and b = 13, 14, 15, 16, 17, 18, 19
    for a = 13, the number of possible values of b is 6, and b = 14, 15, 16, 17, 18, 19
    for a = 14, the number of possible values of b is 5, and b = 15, 16, 17, 18, 19
    for a = 15, the number of possible values of b is 4, and b = 16, 17, 18, 19
    for a = 16, the number of possible values of b is 3, and b = 17, 18, 19
    for a = 17, the number of possible values of b is 2, and b = 18, 19
    for a = 18, the number of possible values of b is 1, and b = 19
    Hence, the number of possible triangles with largest side = 2 (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8) + 9 = 81
    Hence, T20 - T19 = 81
  • Question 7
    1.25 / -0
    What is the difference of the perimeters of outer and inner boundaries of a park whose figure is given below?

    Solution
    Perimeter of outside rectangle = (11 + 5) × 2 = 32
    Perimeter of inside rectangle = (8 + 3) × 2 = 22
    Difference = 32 - 22 = 10 m
  • Question 8
    1.25 / -0
    The ratio of the radii of two circular cylinders A and B is 2 : 3 and that of their heights is 5 : 3. If the volume of cylinder B is 27 cm3, then the volume (in cc) of cylinder A is
    Solution
  • Question 9
    1.25 / -0
    The three different face diagonals of a cuboid (rectangular parallelepiped) have lengths 39, 40 and 41. The length of the main diagonal of the cuboid which joins a pair of opposite corners is
    Solution
  • Question 10
    1.25 / -0
    Consider a square ABCD of side 12, and let M and N be the midpoints of AB and CD, respectively. Take a point P on MN and let AP = r and PC = s. Then, the area of the triangle whose sides are r, s and 12 is
    Solution



    Since PA = r and PC = s,

    PB = r and BC = 12
    So, area of triangle PBC = = 36
  • Question 11
    1.25 / -0
    A and B together can complete a piece of work in 25 days. B and C together can complete the same work in 30 days. How many days would A and C take to complete the work?
    Solution
    A and B can do th of the work in 1 day.
    B and C can do th of the work in 1 day.
    From this, we cannot say anything about A and C.
  • Question 12
    1.25 / -0
    The number of real roots of the equation (x2 + 4x)2 - (x + 2)2 - 26 = 0 is
    Solution
    (x2 + 4x)2 - (x + 2)2 - 26 = 0
    (x2 + 4x + 4 - 4)2 - (x + 2)2 - 26 = 0
    ((x + 2)2 - 4)2 - (x + 2)2 - 26 = 0
    Putting (x + 2)2 = y, we get:
    (y - 4)2 - y - 26 = 0
    y2 - 8y + 16 - y - 26 = 0
    y2 - 9y - 10 = 0
    y = 10, -1
    y can't be negative as y = (x + 2)2
    So, (x + 2)2 = 10
    From this, we will get the two values of x. Hence, the given equation has 2 real roots.
  • Question 13
    1.25 / -0
    The sides of a quadrilateral are all positive integers and three of them are 5, 10, 20. How many possible values are there for the fourth side?
    Solution
    To find possible integral value of the 4th side, minimum possible value of the 4th side greater than 0 is 1.
    For maximum possible value,


    Let angles , are slightly smaller than 180°.
    If are 180° then, AD = 35
    So, the maximum value of AD = 34
    Hence, the maximum possible value of the fourth side = 34
  • Question 14
    1.25 / -0
    In a pair of two supplementary angles, the measure of the larger angle is 44° more than the measure of the smaller one. What are the measures of these angles?
    Solution
    Let the smaller angle be x.
    Larger angle = x + 44°
    We know that, the sum of two supplementary angles is 180°.
    Therefore, x + x + 44° = 180°
    2x = 180° - 44° = 136°
    x = 68°
    Smaller angle = 68°
    Larger angle = 68° + 44° = 112°
  • Question 15
    1.25 / -0
    The number of real roots of equation 3x10 + 7x6 + 5x4 + 2x2 + 1 = 0 is
    Solution
    Let f(x) = 3x10 + 7x6 + 5x4 + 2x2 + 1
    Here, f(x) and f(-x) have no change of sign.
    f(x) = 0 has no real root.
  • Question 16
    1.25 / -0
    In the figure below, a ray of light travelling in a medium of refractive index passes through two different connected rectangular blocks of refractive indices and (> ).



    The angle of incidence is increased slightly. The angle
    Solution

    From the given figure, if θ1 increases, then angle 1 increases () ⇒ angle 2 decreases
    ⇒ angle 3 decreases ()
    ⇒ angle 4 decreases
    ⇒ θ2 decreases
  • Question 17
    1.25 / -0
    From the top of a tower, a stone is thrown up and reaches the ground in time t1 = 9 s. A second stone is thrown down with the same speed and reaches the ground in time t2 = 4 s. A third stone is released from rest and reaches the ground in time t3, which is equal to
    Solution
    Taking the downward direction as positive
    Displacement of first stone,

    h = -ut1 + gt12 ....(1)

    Displacement of second stone,

    h = ut2 + gt22 ....(2)

    Displacement of third stone,

    h = gt32 ....(3)

    Multiplying Eq. (1) by t2 and Eq. (2) by t1 and adding, we get

    h(t1 + t2) = gt1 t2 (t1 + t2)

    ⇒ h = gt1 t2

    From Eqs. (3) and (4), t32 = t1t2

    or t3 = = 6 s
  • Question 18
    1.25 / -0
    The given blocks A, B and C of the same material are immersed in identical fluids. Volume of C > Volume of B > Volume of A. Which block experiences the greatest buoyant force?

    Solution
    Block C is larger in size than blocks A and B. So, block C experiences the greatest buoyant force.
  • Question 19
    1.25 / -0
    Shyam was initially at a distance of 30 m towards 45° north of west from the school. Later, he was at a distance of 50 m towards 60° south of west from the school. Which of the following diagrams shows the direction of displacement vector correctly for Shyam?
    Solution

    It can be seen form the above diagram that Shyam is initially at 30 m towards 45° north of west from school. Then, he is at a distance of 50 m towards 60° south of west form the school.
    So, the direction of displacement vector for Shyam is shown in option (4).
  • Question 20
    1.25 / -0
    A bomber plane is moving horizontally with a speed of 500 m/s and a bomb released from it strikes the ground in 10 seconds. The angle with the horizontal at which the bomb strikes the ground is (g = 10 m/s2)
    Solution
    Let the vertical component of velocity when the bomb strikes the ground be Vv.
    Let the horizontal component of velocity when the bomb strikes the ground be VH.
    Vv = 0 + gt
    Where, t = 10 seconds, Vv = 10 × 10 = 100 m/s and VH = 500 m/s

    tan =

    Hence,
  • Question 21
    1.25 / -0
    The diameter of the pupil of an eye of a person in dim light was measured to be 7 mm. Which of the following cannot be the measurement of the diameter of his pupil in bright light?
    Solution
    As the light entering the eye increases, the pupil decreases in size. Hence, under bright light, the diameter of the pupil cannot be more than what it was under dim light. Hence, it cannot be more than 7 mm.
  • Question 22
    1.25 / -0
    Refractive index of glass with respect to air is . What is the refractive index of air with respect to glass?
    Solution
    Refractive index of glass with respect to air = μg/μa = 3/2
    So, refractive index of air with respect to glass = μa/μg = 2/3
  • Question 23
    1.25 / -0
    A double convex thin lens made of glass (refractive index = 1.5) has both the radii of curvature of magnitude 20 cm. Incident light rays parallel to the axis of lens will converge at a distance 'd' cm such that
    Solution
    From lens maker's formula,

    = ( - 1)

    Here : = 1.5, R1 = 20 cm, R2 = -20 cm

    So, = (1.5 - 1)

    or = 0.5 ×

    or

    ∴ f = 20 cm
    The incident light rays parallel to the axis of lens will converge at the focus.
    Hence, d = f = 20 or d = 20 cm
  • Question 24
    1.25 / -0
    Consider the given V–I graph for two conductors A and B having resistances R1 and R2.



    Which of the following relations is true?
    Solution
    Slope of the V-I graph gives the resistance. The greater the slope, the greater the resistance.
    Slope of A is more than that of B. Hence, R1 > R2
  • Question 25
    1.25 / -0
    Which of the following phenomena can be demonstrated by light, but not by sound waves in an air column?
    Solution
    Sound waves cannot be polarised. The reason is that sound waves are longitudinal waves, which means molecules vibration takes place in forward and backward direction, but in light waves which are transverse waves, molecules vibration takes place up and down and side by side. This is the reason why light waves can be polarised and sound waves cannot be polarised.
  • Question 26
    1.25 / -0
    If you are provided three resistances of 2Ω, 3Ω and 6Ω, how will you connect them so as to obtain the equivalent resistance of 4?
    Solution
    In the given question in option (3), 3Ω and 6Ω resistances are in parallel, hence equivalent resistance is



    ⇒ R' =2Ω



    The two 2Ω resistances are now connected in series, hence equivalent resistance is

    R' = 2Ω + 2Ω = 4Ω

    Note:     The value of the equivalent resistance of the resistances connected in parallel is less than the value of the smallest resistance among those resistances.
  • Question 27
    1.25 / -0
    The work done in carrying a packet weighing 10 kg to the top of a building 14 m high is (g = 10 m/s2)
    Solution
    m = 10 kg , h = 14 m, g = 10
    w = F × s = mgh
    = 10 × 14 × 10 = 1400 J
  • Question 28
    1.25 / -0
    Two bulbs, one of 200 W and the other of 100 W, are connected in series with a 100 V battery which has no internal resistance. Then,

    Solution
    In the series, resistance of 100 W is greater than that of 200 W.
    Since P = I2R,
    In the series combination, I is constant.
    P R
    Power of 100 W will be greater.
  • Question 29
    1.25 / -0
    The frequency of a light ray is 6 × 1014 Hz. Its frequency when it propagates in a medium of refractive index 1.5 will be
    Solution
    When a ray of light passes from one medium to another, then its frequency does not change, but its speed and wavelength change.
    Hence, its frequency in a medium of refractive index 1.5 is 6 × 1014 Hz.
    Note: Intensity of light also changes, because a part of it is reflected.
  • Question 30
    1.25 / -0
    A car was moving on a straight horizontal road with speed v. When brakes were applied to give a constant retardation a, the car was stopped at the shortest distance S. If the car is moving on the same road with speed 3v and the same retardation a is applied, then the shortest distance at which the car is stopped is given by
    Solution
    The shortest stopping distance S is given by 0 - v2 = -2 aS or S = .
    Thus, for a given value of a, S ∝ v2.
    If v is increased by a factor of 3, S will increase by a factor (3)2 = 9.
  • Question 31
    1.25 / -0
    The IUPAC name of methyl alcohol (CH3OH) is ________.
    Solution
    The IUPAC name of methyl alcohol (CH3OH) is methanol.
  • Question 32
    1.25 / -0
    Directions: The following question has four choices, out of which ONLY ONE is correct.

    C-Cl bond is stronger than C-I bond because
    Solution
    (i) C - Cl bond length is shorter than C - I bond length because chlorine atom is smaller in size as compared to iodine atom.
    (ii) C - Cl bond is more ionic than C - I bond because of greater difference in electronegativities of C and Cl as compared to that of carbon and iodine.
    (iii) More ionic character of bond, more will be its strength.
    ∴ C - Cl bond is stronger than C - I bond because C - Cl bond is more ionic than C - I bond.
  • Question 33
    1.25 / -0
    The correct sequence of hybridisation of methane, ethene and acetylene is
    Solution
    The first bond between any two atoms is sigma and rest are pi bonds. The pi bond is formed by sideways overlapping of unhybridised p-orbital.

  • Question 34
    1.25 / -0
    To which group of the periodic table does the element with electronic configuration 1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s2, 4p6, 4d10, 5s2, 5p3 belong?
    Solution
    Since each atom of this element contains five valence electrons, it belongs to group 15 of the periodic table.
    Also, it has five shells occupied with electrons, hence it is an element of period V.
  • Question 35
    1.25 / -0
    An element has mass number 40 and has two neutrons in excess of the number of electrons. Find the number of neutrons, if it forms a cation having a unit positive charge and its electronic configuration is equal to that of Argon?
    Solution
    Mass number = 40
    Since the cation (M+) of this element has 18 electrons, Z = 19
    Number of neutrons = 40 - 19 = 21
    The element is potassium (K).
  • Question 36
    1.25 / -0
    Which of the following is a non-polar molecule?
    Solution
    H2 is a non-polar molecule as both atoms are of hydrogen and have same value of electronegativity.
  • Question 37
    1.25 / -0
    How many atoms are present in 20 g of Ca?
    Solution
    40 g of Ca = 6.022 1023 atoms of Ca
    1 g of Ca = atoms of Ca
    20 g of Ca = atoms of Ca
    = 3.011 1023 atoms of Ca
  • Question 38
    1.25 / -0
    A real gas most closely approaches the behaviour of an ideal gas at
    Solution
    A real gas behaves as an ideal gas at a low pressure and high temperature.
  • Question 39
    1.25 / -0
    Sodium zincate is produced when zinc is heated with
    Solution
    On reaction with zinc, caustic soda (NaOH) produces sodium zincate as shown in the following reaction:

  • Question 40
    1.25 / -0
    Two moles of PCl5 were heated to 400°C in a 2-litre closed vessel. At equilibrium, 40% of PCl5 was dissociated into PCl3 and Cl2. Its KC will be
    Solution
  • Question 41
    1.25 / -0
    For the reaction ⇌ is equal to
    Solution
    The change in the number of moles = 2 - 4 = - 2
    So H = E + (- 2) RT = E - 2RT
    Hence, option (2) is correct.
  • Question 42
    1.25 / -0
    Which of the following is the correct increasing order of reactivities of elements?
    Solution
  • Question 43
    1.25 / -0
    Which of the following orders of the isomers of pentane is correct in terms of increasing melting points?
    Solution
    As the branching increases, the molecules tend to acquire a spherical shape and become less compact. Due to less compact arrangement of molecules in the crystal lattice, they have lower melting points.
  • Question 44
    1.25 / -0
    A metal 'M' is positioned between sodium and aluminium in the reactivity series. Which of the following metals can displace 'M' from its salt solution?
    Solution
    Metal 'M' is positioned between sodium and aluminium in the reactivity series. This means that metal M is less reactive than sodium, but more reactive than aluminium. In general, a more reactive metal can displace a less reactive metal from its salt solution. Lead and zinc are less reactive than Al. They are less reactive than M and they will not be able to displace M from its salt solution. Potassium is more reactive than sodium. Therefore, it is more reactive than M and it will be able to displace M from its salt solution.
  • Question 45
    1.25 / -0
    If the rate of diffusion of gas 'A' is five times that of gas 'B', what will be the density ratio of A and B?
    Solution
  • Question 46
    1.25 / -0
    What is the pH value of human urine?
    Solution
    The average urine sample tests at about pH 6.0.
  • Question 47
    1.25 / -0
    Which of the following organs is the organ of olfactory receptors?
    Solution
    Nose is the correct option. Olfaction is a chemoreception that forms the sense of smell. Olfaction has many purposes, such as the detection of hazards, pheromones, and food. It integrates with other senses to form the sense of flavour. Olfaction occurs when odorants bind to specific sites on olfactory receptors.
  • Question 48
    1.25 / -0
    AIDS is a ______ disease, that causes damage to the _________.
    Solution
    In case of AIDS, the virus affects the immune system, damages its functions and leads to death.
  • Question 49
    1.25 / -0
    Ascorbic acid is a/an
    Solution
    Vitamin C is known as ascorbic acid.
  • Question 50
    1.25 / -0
    Which of the following modes of arrangement of sepals/petals is seen in pea and bean flowers?
    Solution
    There are five petals, the largest (standard) overlaps the two lateral petals (wings), which in turn overlap the two smallest anterior petals (keel); this type of aestivation is known as vexillary.
  • Question 51
    1.25 / -0
    The part of the brain which acts as a relay centre is
    Solution
    Thalamus is the relay centre of brain.
  • Question 52
    1.25 / -0
    The sequence of different phases of cell cycle is
    Solution
    In eukaryotes, cell undergoes cyclic process of growth and division to produce daughter cells.
  • Question 53
    1.25 / -0
    The softening of ripened fruits can be done by
    Solution
    Both ethylene and calcium carbides are fruit ripeners.
  • Question 54
    1.25 / -0
    Unlike humans, dogs cannot perspire to get rid of excess metabolic heat. They lose metabolic heat by
    Solution
    In dogs, panting is a way to release excess metabolic heat. The more overheated a dog becomes, the heavier he will pant.
  • Question 55
    1.25 / -0
    Seedlings grown in dark
    Solution
    Plants grow fast in the dark, and do so because they operate on circadian cycles. Tall spindly plant is a byproduct of "Shade Avoidance Syndrome," a scientific term for a plant's tendency to increase its production of the growth hormone auxin, allowing the plant to grow and stretch more rapidly toward sunlight to improve its conditions.
  • Question 56
    1.25 / -0
    The epithelium tissues forming the lining of kidney tubules are
    Solution
    Cuboidal epithelium consists of cube-like cells which are square in section, but the free surface appears hexagonal. These are found in kidney tubules and glands. These tissues provide mechanical strength to the part where they occur and produce secretions.
  • Question 57
    1.25 / -0
    Pick odd one out of the following
    Solution
    Vasopressin and oxytocin are the only two hormones released from posterior pituitary.
  • Question 58
    1.25 / -0
    Which of the following plant hormones is gaseous in nature?
    Solution
    Option (2) is correct. Ethylene is a gas that is formed by the breakdown of methionine which is present in all the cells.
  • Question 59
    1.25 / -0
    Which of the following is a synthetic plant hormone?
    Solution
    2,4-D is a synthetic auxin, which is a class of plant hormones, which results in uncontrolled growth and eventually death in susceptible plants. So, it is used as a systemic herbicide which selectively kills most broad leaf weeds by causing uncontrolled growth in them but leaves of most grasses such as cereals, lawn turf and grassland are relatively unaffected.
  • Question 60
    1.25 / -0
    Pachytene occurs during
    Solution
    Third stage of prophase I of meiosis, during which homologous chromosomes are short and thick.
  • Question 61
    1.25 / -0
    The number of solutions of the equation |x2 - 4| = 4 + x2 is
    Solution
    |x2 - 4| = 4 + x2
    Case I: If x2 - 4 ≥ 0
    i.e. x ≤ -2 and x ≥ 2
    Then, |x2 - 4| = x2 - 4
    The given equation becomes x2 - 4 = 4 + x2.
    -4 = 4; which is not possible.
    Case II: If x2 - 4 < 0
    -2 < x < 2
    Then, |x2 - 4| = - (x2 - 4)
    Thus, the given equation becomes - (x2 - 4) = 4 + x2.
    Or 2x2 = 0
    x = 0
    Hence, the given equation has only one solution.
  • Question 62
    1.25 / -0
    The points A (2, 3), B (3, 5), C (7, 7) and D (4, 5) are such that
    Solution
    Since

    D = (4, 5) is the centroid of the triangle ABC and hence lies inside the ΔABC.
  • Question 63
    1.25 / -0
    Let p and q be the roots of the quadratic equation x2 - (α - 2) x - α - 1 = 0. What is the minimum possible value of p2 + q2?
    Solution
    Sum of roots = (α - 2)
    Product of roots = - (α + 1)
    p2 + q2 = (p + q)2 - 2pq
    = (α - 2)2 + 2(α + 1)
    = α2 - 2α + 6
    = (α - 1)2 + 5
    Since, minimum value of square can be zero, the minimum possible value of p2 + q2 is 5.
  • Question 64
    1.25 / -0
    ABC is a right-angled triangle with angle A = 90° and 2s = a + b + c, where a > b > c. The notations have their usual meanings. Which of the following relations is correct?
    Solution
    Let a = 5, b = 4 and c = 3
    Since it is a right-angled triangle, and 3, 4 and 5 are a Pythagorean triplet;
    s = (a + b + c)/2 = 12/2 = 6
    Substitute these values and check which condition satisfies this.
    Let us take choice (3).
    L.H.S. (s - a)(s - b) = (6 - 5)(6 - 4) = 2
    R.H.S. s(s - c) = 6(6 - 3) = 18
    L.H.S. < R.H.S.
    It satisfies the given condition.
    Hence, choice (3) is the right answer.
  • Question 65
    1.25 / -0
    If sin α and cos α are the roots of ax2 + bx + c = 0, then
    Solution
    Sum of roots = sin α + cos α = -b/a
    Product of roots = sin α cos α = c/a
    Squaring the 1st equation, we get
    sin2 α + cos2 α + 2 sin α cos α =
    ⇒ 1 + =
    ⇒ a2 - b2 + 2ac = 0
  • Question 66
    1.25 / -0
    In the figure, what is the equivalent resistance between A and B?

    Solution
    Equivalent circuit of the given circuit is



    Between points C and D resistors 2 , 2 and 2 are in series, therefore their equivalent resistance,
    R' = 2 + 2 + 2 = 6
    Resistors R` and 6 are In parallel, therefore their equivalent resistance is given by


    R" = 3

    Now between points A and B, 1 , 3 and 1 are in series
    Therefore, resultant resistance is
    R = 1 + 3 + 1 = 5
  • Question 67
    1.25 / -0
    What is the escape velocity for a body on the surface of a planet on which the acceleration due to gravity is (3.1)2 ms-2 and whose radius is 8100 km?
    Solution
    Escape velocity, ve =
    Given,
    g = (3.1)2 ms-2,
    R = 8100 km = 8100 × 103 m.

    ∴ ve =

    ve = 12.5 × 103 m/s
    ⇒ ve = 12.5 km/s ≈ km-1
  • Question 68
    1.25 / -0
    Two identical cells, whether connected in parallel or in series, give the same current when connected to an external resistance of 1.5. Find the value of internal resistance of each cell.
    Solution
    Let n cells be in series and m in parallel, then



    ⇒ n = R + nr

    ⇒ nRm + nr = Rm + mnr
    ⇒ 6 + 2r = 3 + 4r
    ⇒ 2r = 3
    ⇒ r = 1.5
  • Question 69
    1.25 / -0
    An electron enters a uniform electric field maintained by parallel plates and value of E = Vm-1; with a velocity v ms-1. If the plates are separated by a distance d metre, then acceleration of the electron in the field is:
    Solution
    Let acceleration due to force F be a, then force due to electric field E is balanced by force acceleration a
    ∴ Fe = Fa
    - eE = ma
    ⇒ a = -
  • Question 70
    1.25 / -0
    Two wires with the same dimensions and resistivities 1 and 2 are connected in series. The equivalent resistivity of the combination is
    Solution
  • Question 71
    1.25 / -0
    For Zn2+/Zn = - 0.76 V, Cl2/Cl- = 1.36 V, H+/H2 = 0 V and Fe3+/Fe2+ = 0.77 V, the increasing order of strengths as a reducing agent is
    Solution
    The substances with a lower value of reduction potential are stronger reducing agents.
    Hence, the increasing order of the strengths as reducing agents is:
    Cl2, Fe3+, H2, Zn
  • Question 72
    1.25 / -0
    Which of the following is the least basic?
    Solution
    C6H5NH2 is least basic as phenyl group withdraws the electron density from the nitrogen atom.
  • Question 73
    1.25 / -0
    The maximum number of structural isomers possible for the hydrocarbon having the molecular formula C4H6 is
    Solution
    The possible structural isomers of C4H6 are 9, as shown below:

  • Question 74
    1.25 / -0
    The empirical formula of a compound is CH2. The mass of one mole of this compound is 42 g. Its molecular formula is
    Solution
    Empirical formula: CH2
    Empirical formula weight = 14
    Mass of 1 mole = 42 g
    Molecular weight = 42
    N = = 3
    Molecular formula = (CH2)3 = C3H6
  • Question 75
    1.25 / -0
    PCl3 (g) + Cl2 (g) PCl5 (g) Kc (250°C) for this reaction is 26. The value of Kp at the same temperature is
    Solution
    = 1 - (1 + 1) = - 1
    Kp = Kc .
    = 26 × (0.082 × 523)-1 = 0.6
  • Question 76
    1.25 / -0
    The type of epithelium which lines the inner surfaces of fallopian tubes, bronchioles and small bronchi is known as
    Solution
    The type of epithelium which lines the inner surfaces of fallopian tubes, bronchioles and small bronchi is known as ciliated epithelium.
  • Question 77
    1.25 / -0
    In a cross between a white-eyed female dragonfly and red-eyed male, how many female progenies will inherit white eyes? (White eyes are X-linked recessive)
    Solution
    All the female eggs will have X chromosome with the white-eye mutation while the sperm will posses either a normal X chromosome or a Y chromosome. By using Punnett square, we can predict the outcome of this cross. Female progenies will receive X chromosome from both the sperm and egg cells. All females receive the dominant, red-eyed allele from their fathers and the recessive, white-eyed allele from their mothers.
  • Question 78
    1.25 / -0
    With which of the following functions are chromosomes primarily concerned with?
    Solution
    Chromosomes are mainly concerned with hereditary transmission.
  • Question 79
    1.25 / -0
    An intrapetiolar type of stipule is present in
    Solution
    Stipule refers to outgrowths borne on either side (sometimes just one side) of the base of a leafstalk. A stipule is "interpetiolar" if it is located in between the petioles, and generally one stipule from each leaf is fused together, so it appears that there's just one stipule between each leaf. This type of stipule is present in Gardenia, which is a genus of flowering plants in the coffee family, Rubiaceae.
  • Question 80
    1.25 / -0
    In which of the following can erythroblastosis foetalis occur?
    Solution
    Erythroblastosis foetalis are the conditions where newborn infants suffer from anaemia, jaundice, enlarged spleen or liver and in severe cases, stillbirth or death soon after birth.
Self Studies
User
Question Analysis

  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now