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KVPY SB/SX Mock Test - 4

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KVPY SB/SX Mock Test - 4
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  • Question 1
    1 / -0

    If sin x + sin y = 7/5 and cos x + cos y = 1/5, then sin (x + y) equals

    Solution

    sin x + sin y = 7/5 ------(1)

    cos x + cos y = 1/5 ------(2)

    By (1)2 + (2)2, we get

    2 + 2 sin x sin y + 2 cos x cos y = 2

    ⇒ sin x sin y + cos x cos y = 0

    cos (x - y) = 0

    Therefore, x - y = 90o

    By (1) x (2), we get
    sin x cos x + sin x cos y + sin y cos x + sin y cos y = 7/25

    ⇒ sin (90 + y) cos x + sin (x + y) + sin (x - 90) cos y = 7/25

    ⇒ cos y cos x + sin (x + y) - cos x cos y = 7/25

    ⇒ sin (x + y) = 7/25

     

  • Question 2
    1 / -0

    Consider the cubic equation x+ ax2 + bx + c = 0, where a, b and c are real numbers. Which of the following statements is correct?

    Solution

    f(x) = x3 + ax2 + bx + c

    f'(x) = 3x+ 2ax + b

    D = 4a2 - 4.3.b = 4(a2 - 3b)

    If a2 < 2b

    ⇒ a2 < 3b

    ⇒ D < 0

    ⇒ f'(x) = 0 has no real roots.

    Hence, f(x) = 0 has 1 real and two imaginary roots.

     

  • Question 3
    1 / -0

    For an integer n, let Sn = {n + 1, n + 2, ... n + 18}. Which of the following is true for all n ≥ 10?

    Solution

    n + 1, n + 2, ... n + 18
    (1) False, if n = 19
    (3) False if n = 15
    16 to 33
    20, 25, 30 → only three multiples of 5
    (4) Number of odd integers in Sn = 9
    Every third odd integer is the multiple of 3.
    So, maximum prime numbers = 6

     

  • Question 4
    1 / -0

    The solvent used for carrying out a Grignard reaction is

    Solution

    Diethyl ether is a good solvent for the formation of Grignard reagents because ether is aprotic in nature, while water, chloroform, ethyl acetate or alcohol would protonate and destroy the Grignard reagent. This is because the carbon atom in Grignard reagent is highly nucleophilic. This would form a hydrocarbon on reaction with water, alcohol etc.

     

  • Question 5
    1 / -0

    The isoelectronic pair of ions is:

    Solution

    Isoelectronic species have the same number of electrons. As 25Mn2+ and 26Fe3+ both have 23 electrons, both are an isoelectronic pair.

     

  • Question 6
    1 / -0

    For a tetrahedral complex [MCl4]2-, the spin-only magnetic moment is 3.83 BM. The element M is:

    Solution

    It is a high-spin complex as Cl- is a weak field ligand. In [CoCl4]2-, the oxidation state of Co is +2, in which 3 unpaired electrons are present; this gives the spin-only magnetic moment equal to 3.83 BM.

     

  • Question 7
    1 / -0

    Glycolysis is the

    Solution

    Glycolysis is the metabolic pathway that converts glucose into two molecules of pyruvate. The process occurs in the cytoplasm of the cell.

     

  • Question 8
    1 / -0

    This cell organelle consists of two granule-like centrioles and is found in animal cells only. It helps in cell division. It is called

    Solution

    Centrosome is an organelle near the nucleus of a cell which contains the centrioles (in animal cells) and from which, the spindle fibres develop in cell division.

     

  • Question 9
    1 / -0

    The natural source of Ti plasmid is

    Solution

    A Ti or tumour inducing plasmid is a plasmid that often is a part of the genetic equipment that Agrobacterium tumefaciens and Agrobacterium rhizogenes (bacteria) used to transduce their genetic material to plants.

     

  • Question 10
    1 / -0

    In which kind of rocks are fossils most commonly found?

    Solution

    Fossils are more common in some kinds of sedimentary rocks than others. Fossils are most common in limestones. That is because most limestones consist partly or mostly of the shells of organisms.

     

  • Question 11
    1 / -0

    Human chromosomes undergo structural changes during the cell cycle. Chromosomal structure can be best visualised if a chromosome is isolated from a cell at

    Solution

    Metaphase is the stage in which the chromosomes can be best visualised. Metaphase is a stage of mitosis or M phase of the cell cycle.

     

  • Question 12
    1 / -0

    DNA mutations that do not cause any functional change in the protein product are known as

    Solution

    Silent mutations are mutations in DNA that do not significantly alter the phenotype of the organism in which they occur. Silent mutations can occur in non-coding regions (outside of genes or within introns), or they may occur within exons. These mutations do not cause any functional change in the protein product.

     

  • Question 13
    1 / -0

    A reflex action is a quick involuntary response to stimulus. Which of the following is an example of BOTH, unconditioned and conditioned reflex?

    Solution

    A conditioned reflex is an automatic response established by training to an ordinarily neutral stimulus. An unconditioned reflex is a reflex that is inborn or dependent on physiological maturation rather than on learning. Salivation in response to the aroma of food is an example of both.

     

  • Question 14
    1 / -0

    A horse has 64 chromosomes and a donkey has 62. Mules result from crossing a horse and a donkey. State which of the following is INCORRECT.

    Solution

    Mules are a hybrid of two species – a female horse and a male donkey – so they end up with an odd number of chromosomes. A horse has 64 chromosomes and a donkey has 62. A mule inherits 63. Mules can be either male or female, but, because of the odd number of chromosomes, they can't reproduce.

     

  • Question 15
    1 / -0

    Fruit wrapped in paper ripens faster than when kept in open air because

    Solution

    Fruits produce ethylene on ripening. Ethylene serves as a ripening hormone. The fruit wrapped in paper ripens faster as ethylene produced is retained better.

     

  • Question 16
    1 / -0

    Out of the following combinations of cell biological processes, which one is associated with embryogenesis?

    Solution

    Embryogenesis is the process by which the embryo forms and develops. Embryogenesis starts with the fertilisation of the egg cell (ovum) by a sperm cell (spermatozoon). Once fertilised, the ovum is referred to as a zygote, a single diploid cell. The zygote undergoes mitotic divisions with no significant growth (a process known as cleavage) and cellular differentiation, leading to development of a multicellular embryo.

     

  • Question 17
    1 / -0

    The distance between two consecutive DNA base pairs is 0.34 nm. If the length of a chromosome is 1 mm, the number of base pairs in the chromosome is approximately

    Solution

    The total length of double helix DNA in an organism can be calculated by multiplying the total number of base pairs with distance between two consecutive base pairs.
    Let the total number of base pairs be x.
    Length of DNA = Total number of base pairs X Distance between two consecutive base pairs
    1 mm = x X 0.34 X 10-9 m
    By solving this, we get x = 2.9 X 106 bp
    This is equivalent to 3 million base pairs.

     

  • Question 18
    1 / -0

    If the sequence of bases in DNA is 5'-ATGTATCTCAAT-3', then the sequence of bases in its transcript will be

    Solution

    Base pairing is according to Chargaff rule. According to it, a hydrogen bonds with T by two H bonds. G is hydrogen bonded to C by 3 H bonds during DNA replication. When RNA synthesis occurs from DNA, T is replaced by U.

     

  • Question 19
    1 / -0

    Carbon dioxide in the blood is mostly carried

    Solution

    Some of the carbon dioxide is transported dissolved in the plasma. Some carbon dioxide is transported as carbaminohaemoglobin. However, most carbon dioxide is transported as bicarbonate.

     

  • Question 20
    1 / -0

    Modern evolutionary theory consists of the concepts of Darwin modified by knowledge concerning

    Solution

    Modern evolutionary theory consists of the concepts of Darwin modified by knowledge concerning the process of natural selection. This explains that adaptability has genetic basis, which proves fitness of an organism and nature selects organism for its fitness and allows to produce its progeny in large numbers.

     

  • Question 21
    1 / -0

    Crossing over occurs at which of the following stages of meiosis I?

    Solution

    Pachytene is the third stage of the prophase of meiosis, following zygotene, during which the paired chromosomes shorten and thicken, the two chromatids of each separate and exchange of segments between chromatids may occur.

     

  • Question 22
    1 / -0

    If DNA codons are ATG GAA, then insertion of thymine after the first codon results in

    Solution

    A nonsense mutation is a point mutation in a sequence of DNA that results in a premature stop codon. Entry of T causes formation of stop codon.

     

  • Question 23
    1 / -0

    According to Mendel, ..................................... segregate and ........................... assort independently.

    Solution

    According to the law of segregation, during gamete formation, the alleles for each gene segregate from each other so that each gamete carries only one allele for each gene. According to the law of independent assortment, genes for different traits can assort or segregate independently during the formation of gametes.

     

  • Question 24
    1 / -0

    Stroke could be prevented/treated with

    Solution

    Blood thinners do not actually thin blood, but they can stop blood clots from forming or growing larger. Hence, they prevent cardiovascular accidents, which can cause stroke.

     

  • Question 25
    1 / -0

    In a large isolated population, alleles p and q at a locus are at Hardy-Weinberg equilibrium. The frequencies are p = 0.6 and q = 0.4. The proportion of the heterogeneous genotype in the population is

    Solution

    In Hardy-Weinberg equation (p² + 2pq + q² = 1), prepresents the frequency of the homozygous genotype AA, qrepresents the frequency of the homozygous genotype aa and 2pq represents the frequency of the heterozygous genotype Aa.
    Heterozygous population = 2pq = .48

     

  • Question 26
    1 / -0

    A stream of photons having energy 3 eV each impinges on a potassium surface. The work function of potassium is 2.3 eV. The emerging photo-electrons are slowed down by a copper plate placed 5 mm away. If the potential difference between the two metal plates is 1 V, then the maximum distance the electrons can move away from the potassium surface before being turned back is

    Solution

    Kmax = 3 - 2.3 = 0.7 eV
    Now from W.E. theorem:
    If voltage difference is 1 V, then distance = 5 mm.
    So, if voltage difference is 0.7 V, then d = 0.7 x 5 = 3.5 mm

     

  • Question 27
    1 / -0

    The amount of Na2S2O3.5H2O required to completely reduce 100 mL of 0.25 N iodine solution is

    Solution

    N1V1 = N2V2

    Mili eq. of hypo = 0.25 x 100

    Mili eq. of hypo = 25

    Eq. of hypo = 0.025

    Mole of hypo = 0.025 x 1

    Weight of hypo = 0.025 x 248 = 6.2 g

     

  • Question 28
    1 / -0

    Gregor Mendel showed that unit factors exist in pairs and exhibit a dominant-recessive relationship. These unit factors, in modern terminology, are called

    Solution

    Each of the two alternative forms of a gene that arise by mutation and are found at the same place on a chromosome are called alleles. These exist in pairs and exhibit a dominant-recessive relationship.

     

  • Question 29
    1 / -0

    Greatest proportion of photosynthesis in the world is carried out by

    Solution

    It is estimated that marine plants produce between 70 and 80 percent of the oxygen in the atmosphere. Nearly all marine plants are single-celled, photosynthetic algae.

     

  • Question 30
    1 / -0

    In cattle, the coat colours red and white are two dominant traits which express equally in F1 to produce roan (red and white colours in equal proportion). If F1 progeny are self-bred, the resulting progeny in F2 will have phenotypic ratio (red : roan : white)

    Solution

    Let the red colour be represented by R and white by W (as both are dominant). Parental generation: RR X WWF1 generation will give roan colour ---RW

    On self crossing F1: RW X RW, the genotypes formed will be: RR : RW : RW: RR.

    This gives a genotypic ratio of 1 : 2 : 1.

     

  • Question 31
    1 / -0

    The following sequence contains the open reading frame of polypeptide. How many amino acids will the polypeptide consist of?

    5' AGCATATGATCTCGTTTCTGCTTTGAACT-3'

    Solution

    An ORF is a continuous stretch of codons that contains a start codon (usually AUG) and a stop codon (usually UAA, UAG or UGA). An ATG codon within the ORF (not necessarily the first) may indicate where translation starts.

     

  • Question 32
    1 / -0

    The amino acid sequences of a bacterial protein and a human protein carrying out similar functions are found to be 60% identical. However, the DNA sequences of the genes coding for these proteins are only 45% identical. This is possible because

    Solution

    The condition given can be explained by Wobble hypothesis. The Wobble Hypothesis explains why multiple codons can code for a single amino acid. One tRNA molecule (with one amino acid attached) can recognise and bind to more than one codon, due to the less-precise base pairs that can arise between the 3rd base of the codon and the base at the 1st position on the anti-codon.

     

  • Question 33
    1 / -0

    Although blood flows through large arteries at high pressure, when the blood reaches small capillaries the pressure decreases because

    Solution

    The total cross-sectional area of capillaries arising from an artery is much greater than that of the artery. This leads to lowering of the blood pressure when it reaches the capillary network.

     

  • Question 34
    1 / -0

    Nocturnal animals have retinas that contain

    Solution

    Nocturnal animals have retinas that contain a high percentage of rods to increase sensitivity to low light conditions.

     

  • Question 35
    1 / -0

    From an early amphibian embryo, the cells that would give rise to skin in adults were transplanted into the developing brain region of another embryo. The transplanted cells developed into brain tissue in the recipient embryo. What do you infer from this experiment?

    Solution

    Differentiation of cells in the embryo is brought about by both internal cellular factors as well as extracellular factors, that act on the cell from the outside.

     

  • Question 36
    1 / -0

    In some species, individuals forego reproduction and help bring up another individual's offspring. Such altruistic behaviour cannot be explained by which of the following?

    Solution

    Individuals are predicted to behave more altruistically and less competitively toward their relatives, because they share a relatively high proportion of their genes (e.g., one-half for siblings and one-eighth for cousins). Consequently, by helping a relative reproduce, an individual passes its genes to the next generation, increasing their Darwinian fitness. Altruistic behaviour toward relatives may at some later time lead to increased competition between relatives, reducing or even completely removing the net selective advantage of altruism. 

     

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