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Weekly Quiz Competition
  • Question 1
    1 / -0

    If the area of a rectangular plot is \(180 sq . m\) and its length is \(15 m\), then its breadth is:

    Solution

    Given,

    Length \(=15 m\)

    Let Breadth \(=x\)

    Area of a rectangle \(=180 sq \cdot m\)

    As we know,

    Area of a rectangle \(=\) Length \(\times\) Breadth

    \(180=\) Length \(\times\) Breadth

    \(\Rightarrow 180=\) Length \(\times x\)

    \(\Rightarrow 180=15 \times x\)

    \(\Rightarrow x=\frac{180}{15}\)

    \(\Rightarrow x=12 m\)

    So, its breadth is \(12 m\).

    Hence, the correct option is (A).

  • Question 2
    1 / -0

    Direction: What approximate value should come in the place of question mark (?).

    \(120.09 ÷ 14.88 × 23.03 – 20.94 × 3.96 = ?\)

    Solution

    Given,

    \(120.09 ÷ 14.88 × 23.03 – 20.94 × 3.96 = ?\)

    \(\Rightarrow ?=120.09 \div 14.88 \times 23.03-20.94 \times 3.96\)

    \(\Rightarrow ?= 120 \div 15 \times 23-21 \times 4\)

    \(\Rightarrow ?= 8 \times 23-21 \times 4\)

    \(\Rightarrow ? =184-84\)

    \(\Rightarrow ?= 100\)

    Hence, the correct option is (A).

  • Question 3
    1 / -0

    Direction: What approximate value should come in the place of question mark (?).

    \(61 – 5.4 × 16.2 + 24.3 = ?\)

    Solution

    Given,

    \(61 – 5.4 × 16.2 + 24.3 = ?\)

    \(\Rightarrow?=61-5.4 \times 16.2+24.3\)

    \(\Rightarrow ?=61-5 \times 16+24\)

    \(\Rightarrow? =61-80+24\)

    \(\Rightarrow ?= 5\)

    Hence, the correct option is (A).

  • Question 4
    1 / -0

    Compute \(150 \%\) of \(60 \).

    Solution

    Given,

    \(150 \%\) of \(60\)

    \(=\left(\frac{150}{100}\right) \times 60 \)

    \(=\left(\frac{3}{2}\right) \times 60 \)

    \(=3 \times 30 \)

    \(=90\)

    \(\therefore\) The value of \(150 \%\) of \(60\) is \(90\).

    Hence, the correct option is (D).

  • Question 5
    1 / -0

    Suhani walks \(30\) metres in \(1\) minutes. How much distance, she will cover in \(6\) minutes?

    Solution

    Given,

    Distance \(=30\) metres

    Time \(=1\) minutes

    As we know,

    Speed \(=\frac{\text { Distance }}{\text { Time }}\)

    Distance \(=\) Speed \(\times\) Time

    In first condition:

    \(\Rightarrow\) Speed \(=\frac{30}{1}=30\) metres \(/\) minutes

    In second condition:

    Distance \(=\) Speed \(\times\) Time

    \(\Rightarrow\) Distance \(=30 \times 6=180\) metres

    \(\therefore\) The distance covered by Suhani is \(180\) metres.

    Hence, the correct option is (A).

  • Question 6
    1 / -0

    Simplify \(27-[18-\{16-(5-4-1)\}]\).

    Solution

    Given,

    \(27-[18-\{16-(5-4-1)\}]\)

    \(=27-[18-\{16-0\}]\)

    \(=27-[18-16]\)

    \(=27-2\)

    \(=25\)

    Hence, the correct option is (D).

  • Question 7
    1 / -0

    A car travels \(300 km\) in \(5.5 hrs\) and another \(400 km\) in \(8.5 hrs\). Find the average speed of the car during the entire journey.

    Solution

    As we know,

    Speed \(=\frac{\text { distance }}{\text { Time }}\)

    Total distance travelled \(=300+400=700 km\)

    Total time taken \(=5.5+8.5=14 hrs\)

    \(\therefore\) Average speed \(=\frac{\text { Total distance travelled }}{\text { Total Time taken }}\)

    \(=\frac{700}{14}\)

    \(=50 km / hr\)

    Hence, the correct option is (B).

  • Question 8
    1 / -0

    Simplify \(36-[18-\{14-(15-4 \div 2 \times 2)\}]\).

    Solution

    Given,

    \(36-[18-\{14-(15-4 \div 2 \times 2)\}] \)

    \(=36-\left[18-\left\{14-\left(15-\frac{4}{2} \times 2\right)\right\}\right] \)

    \(=36-[18-\{14-11\}] \)

    \(=36-[18-3] \)

    \(=36-15 \)

    \(=21\)

    Hence, the correct option is (D).

  • Question 9
    1 / -0

    If the perimeter of a square is \(36 cm\), then its area is:

    Solution

    Given,

    Perimeter of a square \(=36 cm\)

    As we know,

    Perimeter of a square \(=4 \times\) length of a side

    \(\Rightarrow 4 \times\) length of a side \(=36\)

    \(\Rightarrow\) length of a side \(=\frac{36}{4}=9 cm\)

    Area of a square \(=\)(Length of a side)\(^{2}=(9 cm )^{2}=81 cm ^{2}\)

    Hence, the correct option is (D).

  • Question 10
    1 / -0

    If \(100 \%\) of a number is \(15\), what is \(50 \%\) of the number?

    Solution

    Let \(n\) be the number.

    \(100 \%\) of a number is \(15\) is written as:

    \(100 \% \times n=15\)

    \(\Rightarrow n=15\)

    We now need to find \(50 \%\) of the number

    \(50 \%\) of \(15\)

    \(=\left(\frac{50}{100}\right) \times 15\)

    \(=\frac{750}{100}\)

    \(=7.5\)

    Hence, the correct option is (D).

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