Motion and Time Test

Result

Motion and Time Test - 8

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Weekly Quiz Competition

Question 1
1 / -0

A man completes a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey (in km).

A
220 km

B
224 km

C
230 km

D
234 km

Solution

Let the total distance be 'x' km.

15x = 168 20
x = 224 km
Question 2
1 / -0

A man on tour travels the first 160 km at 64 km/hr and the next 160 km at 80 km/hr. What is the average speed for the tour?

A
35.55 km/hr

B
37.23 km/hr

C
71.11 km/hr

D
73.47 km/hr

Solution

Total time taken = hr = hr
Average speed = 320 = 71.11 km/hr
Question 3
1 / -0

A ball moves at 120 metres per second and strikes an object in three seconds. If it moves at the speed of 100 metres per second, how long will it take for the ball to strike the same object?

A
12/5 sec

B
9/5 sec

C
10/5 sec

D
18/5 sec

Solution

Total distance covered by the ball = 120 3 = 360 m
Now, speed of the ball = 100 m/sec
Time taken = = sec
Question 4
1 / -0

A man wants to cover 50 km on his bicycle. His speed is 12.5 km/hr. After every 12.5 km, he takes rest for 20 minutes. How long will he take to cover the whole distance?

A
5 hours

B
4 hours 20 minutes

C
6 hours

D
5 hours 20 minutes

E
7 hours

Solution

Speed = 12.5 km/hr
Distance to be covered = 50 km
Time required = = 4 hours
Rest intervals = 20 minutes × 3 = 60 minutes = 1 hour (After the third stoppage, he will reach his destination.)
Total time = 4 + 1 = 5 hours
Question 5
1 / -0

The distance between two points A and B is 110 km. A motorcyclist starts from A towards B at 7 a.m. at a speed of 20 km/hr. Another motorcyclist starts from B towards A at 8 a.m. at a speed of 25 km/hr. At what time will they cross each other?

A
9 a.m.

B
11 a.m.

C
10 a.m.

D
12 p.m.

Solution

Let both meet at a point P from point A at x and at time t.
Using the formula:
Speed = Distance/Time
Hence, for the motorcyclist at point A,

--- 1

Hence, for the motorcyclist at point B,

--- 2

From 1 and 2,

Solving, x = 60 km

Putting this value in equation 1,

Or we can say, they will meet at t = 10 a.m.
Question 6
1 / -0

Nathan is driving at a speed of 100 km/hr. How much distance will he travel in 90 minutes?

A
120 km

B
150 km

C
200 km

D
250 km

Solution

Speed = 100 km/hr
Time = 90 minutes
Here, we need to convert the given time in hours.
60 min = 1 hr
90 min = hr
Time = 1.5 hr
Distance = ?
Using formula triangle,

Distance = Speed x Time
= 100 x 1.5 = 150 km
Question 7
1 / -0

A train is running at a speed of 48 km/hr. A passenger counts the telephone posts along the line as he passes them. If the posts are 50 m apart, then how many posts will he cross per minute?

A
16

B
20

C
24

D
10

E
12

Solution

Speed of the train = 48 km/hr = m/s = m/min = 800 m/min
Hence, number of posts passed per minute = = 16
Question 8
1 / -0

An ant moves from A to B and then to C. What is the magnitude of its displacement?

A
200 m

B
170 m

C
160 m

D
100 m

Solution

An ant moves from A to B and then to C. Then magnitude of its displacement is the shortest distance from point A to C, i.e. AC.

AC =
=
=
=
= 100 m

Hence, option (4) is correct.
Question 9
1 / -0

Which of the following distance-time graphs shows a car parked on a roadside?

A

B

C

D

Solution

Graph (4) indicates that the car is not moving at all. It is at rest.
Question 10
1 / -0

From the following d-t graph, find the distance travelled after 5 hours.

A
15 km

B
30 km

C
45 km

D
60 km

Solution

The distance travelled after 5 hours as shown in the d-t graph is 30 km.
Question 11
1 / -0

Which of the following parts of the graph represent(s) uniform motion of a moving object?

A
Only a

B
Only b

C
Only c

D
Both a and b

Solution

A body is said to be in uniform motion when it covers equal distances in equal intervals of time.
Question 12
1 / -0

The graph below represents

A
motion with uniform speed

B
motion with uniform acceleration

C
motion with non-uniform acceleration

D
motion with non-uniform velocity

Solution

The graph is between position and time (s) whose slope gives us the velocity of a body.
i.e. Velocity of a body = Slope of the position-time graph
Moreover, increasing curve slope of a graph tells that the body covers unequal displacement in equal intervals of time. So, it represents motion with non-uniform velocity.
Hence, option (4) is correct.
Question 13
1 / -0

On which of the following parameters does the time period of a pendulum depend?

A
Length of the thread

B
Speed

C
Weight of the pendulum

D
Height of the pendulum

Solution

The time period of the pendulum depends upon the length of the thread and it is constant for a particular pendulum.
Question 14
1 / -0

Total time taken = Time period x ________

A
Number of oscillations

B
Total distance

C
Average speed

D
Number of hours

Solution

We know,
Time period = Total time taken ÷ Number of oscillations

So, Total time taken = Time period x Number of Oscillations
Question 15
1 / -0

A simple pendulum takes 15 seconds to complete 5 oscillations. What is the time period of the pendulum?

A
15 sec

B
5 sec

C
3 sec

D
45 sec

Solution

Time taken to complete one oscillation = 15/5 = 3 sec