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Electric Current and its Effects Test - 3

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Electric Current and its Effects Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following materials should be used to make the coil of an electromagnet in order to increase its strength?

    Solution

    Copper is a good conductor of electricity, so it should be used for the coil of an electromagnet in order to increase its strength.

     

  • Question 2
    1 / -0

    What is the difference between the wires used in the elements of an electric heater and a fuse?

    Solution

    A fuse wire should have high resistivity and low melting point as fuse melts down to protect the electrical appliances by breaking the circuit when current more than the permissible value passes through it. The wire used in a heater element has high resistivity and high melting point as the heat produced in the element due to large resistivity (hence large resistance) is used to heat the water.

     

  • Question 3
    1 / -0

    If 18.75 × 1019 electrons flow through a conductor in 3 seconds, the total charge that flows through the conductor is

    Solution

    Total charge flown (Q) = number of electrons(n) × charge on the one electron (e)
    Q = ne
    Q = 18.75 × 1019 × 1.6 × 10-19
    Q = 30 C

     

  • Question 4
    1 / -0

    There is no flow of current between two charged bodies when connected because

    Solution

    Current will flow only if there is a potential difference between two points.

    That is, there is no flow of current between two charged bodies when connected because they are at the same potential.

     

  • Question 5
    1 / -0

    The minimum number of cells required to make a battery is

    Solution

    A battery is a combination of cells connected together. The positive terminal of one cell is connected to the negative terminal of the next cell. The minimum number of cells needed to make a battery is 2.

     

  • Question 6
    1 / -0

    Moving a small charge of 1.6 × 10-19 C between two parallel plates increases its electric potential energy by 4.8 × 10-16 J. What is the electric potential difference between the two parallel plates?

    Solution

    V = W/Q = 4.8 × 10-16/1.6 × 10-19 = 3 × 103 V

     

  • Question 7
    1 / -0

    Which of the following statements is/are incorrect?

    (a) An electric bell is an application of electromagnets.
    (b) Heating effect of current is used in an electric bell.
    (c) The coil in a bell behaves like a magnet when no current flows through it.

    Solution

    Heating effect of current is used in heaters and not in a bell, which works on the principle of an electromagnet. The coil in a bell stops behaving like a magnet when no current flows through it.

     

  • Question 8
    1 / -0

    In which of the following is an electromagnet used?

    Solution

    When a soft iron bar is placed inside a solenoid carrying current, it becomes a magnet as long as current flows through the solenoid. Such a magnet is known as an electromagnet. They are used to lift heavy iron pieces. They are fitted on cranes, which lift heavy masses of scrap iron.
    They are also used in many devices, like electric bell, electric horn, telephone receiver, electric relay, microphones, television, loudspeakers, etc.

     

  • Question 9
    1 / -0

    Why does a wire through which current flows attract iron pieces?

    Solution

    A wire through which current flows attracts iron pieces because the wire possesses magnetic force of attraction like a magnet.

     

  • Question 10
    1 / -0

    What is the value of charge when work done is 1760 joules and potential difference is 220 volts?

    Solution

    Potential difference (V) = Work done (W)/Charge (Q)

    Q = W/V

    V = 220 volts, W = 1760 joules

    Q = 1760/220

    Q = 8 C

     

  • Question 11
    1 / -0

    Four cells, each of voltage `V` across them, are joined in parallel to form a battery. What will be the equivalent voltage of the battery?

    Solution

    As the four cells are connected in parallel, the voltage remains the same whatever is the number of cells connected.
    Hence, the equivalent voltage will be V.

     

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