Mensuration Test

Result

Mensuration Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

Ganesh took one complete round of a rectangular park 200 m long and 60 m wide. What is the distance covered by him?

A
260 m

B
320 m

C
460 m

D
520 m

Solution

Length of park = 200 m

Breadth of park = 60 m

Total distance covered by Ganesh
= Perimeter of the park = 2(length + breadth)
= 2(200 m + 60 m) = 2(260 m)
= 520 m
Question 2
1 / -0

A 16 cm long wire is used to form a square. What is the perimeter of the square?

A
16 cm

B
32 cm

C
48 cm

D
64 cm

Solution

Perimeter of the square = 16 cm because 16 cm long wire is bent to form a square.
Question 3
1 / -0

A farmer wants to fence a rectangular field which is 300 m long and 160 m wide. What is the length of the fence required?

A
160 m

B
300 m

C
460 m

D
920 m

Solution

Perimeter is the sum of lengths of all sides.
Perimeter of the rectangular field = 2(length + width)
= 2(300 + 160) m
= 2(460) m
= 920 m
Question 4
1 / -0

What is the perimeter of an equilateral triangle whose each side measures 9 m?

A
9 m

B
18 m

C
27 m

D
36 m

Solution

Perimeter = Sum of the lengths of all sides
= 9 m + 9 m + 9 m
= 27 m
Question 5
1 / -0

What is the total distance covered by an athlete who takes 20 rounds of a rectangular park 50 m long and 25 m wide?

A
3000 m

B
1500 m

C
750 m

D
375 m

Solution

Length of rectangular park = 50 m
Breadth of rectangular park = 25 m

Perimeter of the park = 2(length + breadth)
= 2(50 m + 25 m)
= 2(75 m)
= 150 m

Athlete takes 20 rounds of the park.

Distance covered by him = Number of rounds x Perimeter
= 20 x 150 m
= 3000 m
Question 6
1 / -0

What is the total cost of fencing a rectangular park of length 356 m and breadth 244 m at the rate of Rs. 12 per metre?

A
Rs. 14,400

B
Rs. 12,000

C
Rs. 9600

D
Rs. 7200

Solution

Length of rectangular park = 356 m
Breadth of the park = 244 m

Perimeter of the park = 2(356 m + 244 m)
= 2(600) m
= 1200 m

It is given that:
Cost of fencing per metre = Rs. 12

Therefore, total cost of fencing 1200 metres = Rs. 1200 x 12
= Rs. 14,400
Question 7
1 / -0

What is the length of each side of a square having perimeter 60 m?

A
40 m

B
30 m

C
20 m

D
15 m

Solution

Perimeter of square = 60 m

We know:

A square has 4 equal sides.

Let its each side be denoted by S.

Perimeter of square = 4 x S

60 m = 4 x S

S = m = 15 m

Length of each side = 15 m
Question 8
1 / -0

Find the perimeter of the given figure.

A
15 cm

B
20 cm

C
25 cm

D
30 cm

Solution

Perimeter of the given figure = (5 + 3 + 3 + 2 + 2 + 5) cm = 20 cm
Question 9
1 / -0

The top of a rectangular table measures 3 m 25 cm by 2 m 50 cm. What is its perimeter?

A
5.75 m

B
6.75 m

C
10.50 m

D
11.50 m

Solution

Length of tabletop = 3 m 25 cm

Breadth of tabletop = 2 m 50 cm

We know

1 m = 100 cm

3 m 25 cm = 300 cm + 25 cm

Length of tabletop = 325 cm

Similarly,

2 m 50 cm = 200 cm + 50 cm

Breadth of tabletop = 250 cm

Perimeter = Sum of lengths of all sides

= 2(length + breadth)

= 2(325 cm + 250 cm)

= 2(575 cm)

= 1150 cm

Converting 1150 cm to metres:

100 cm = 1 m
Therefore, 1150 cm = = 11.50 m
Thus, perimeter of tabletop is 11.50 m.
Question 10
1 / -0

A piece of string is 30 m long. If the string is used to form an equilateral triangle, what will be the length of each of its sides?

A
10 m

B
7.5 m

C
6 m

D
5.5 m

Solution

Length of string = 30 m
Length of string = Perimeter of equilateral triangle

We know:

All 3 sides of an equilateral are equal.

Perimeter of equilateral = 3 x Length of each side

30 m = 3 x Length of each side

Length of each side = 10 m
Question 11
1 / -0

In the given figures A and B, 9 squares (each of side 2 cm) are arranged in two different forms, i.e. a square and a cross, respectively.

(A) (B)

Which of the following statements is true?

A
Perimeter of B is less than perimeter of A.

B
A and B have the same perimeter.

C
Each of the 9 squares in both A and B has a perimeter of 4 cm.

D
Perimeter of B is greater than perimeter of A.

Solution

(A)

Length of each side of the square in figure (A) is 2 cm + 2 cm + 2 cm = 6 cm.
Perimeter of the square = 4 x side = 4 x 6 cm = 24 cm
Side of each square in figure (B) is 2 cm.
(B)
Perimeter of figure (B) = Sum of lengths of all sides = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= 2 cm + 4 cm + 4 cm + 2 cm + 4 cm + 4 cm + 2 cm + 4 cm + 4 cm + 2 cm + 4 cm + 4 cm
= 40 cm
Perimeter of figure (A) = 24 cm
Perimeter of figure (B) = 40 cm
Perimeter of B (40 cm ) > Perimeter of A (24 cm)
Question 12
1 / -0

The surface enclosed by a closed figure is called its

A
area

B
perimeter

C
circumference

D
region

Solution

The surface enclosed by a closed figure is called its area.

Example: The figure ABCD is a square as shown below:

So, the surface enclosed is the area covered by the figure.

The shaded portion shows the area of square ABCD.
Question 13
1 / -0

What is the area of one side of a rectangular door having length 7 feet and breadth 3 feet?

A
20 sq. feet

B
21 sq. feet

C
30 sq. feet

D
42 sq. feet

Solution

Area of the door = Length x Breadth
= 7 feet x 3 feet
= 21 sq. feet.
Question 14
1 / -0

What is the breadth of a rectangle whose area is 84 cm² and length is 14 cm?

A
6 cm

B
12 cm

C
14 cm

D
70 cm

Solution

Area of rectangle = 84 cm²
Length (L) = 14 cm
Let breadth be B cm.
Area = L x B = 84 cm²
14 cm x B cm = 84 cm²
B = = 6 cm
Question 15
1 / -0

The area of a 60 m long rectangular garden is 960 m². What is the width of the garden?

A
16 m

B
26 m

C
32 m

D
64 m

Solution

Length = 60 m

Area = 960 m²
Suppose width = b

Area of rectangle = Length x Width

960 m² = 60 m x b

b = m

b = 16 m

Therefore, width = 16 m