Algebra Test

Result

Algebra Test - 14

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following is the formula for the following statement?

Mr. Naitik`s age is six times the age of his son, and the sum of their ages is 35.

A
6 x = 35

B
(6 + x) x = 35

C
x + 6x = 35

D
6x = . y

Solution

Let Naitik`s son`s age = x
Naitik`s age = 6x
Sum of their ages = 35
x + 6 x = 35
This is the required formula.
Question 2
1 / -0

Sachin bought 5 apples and 6 oranges. The cost of an apple is Rs. 2 more than the cost of an orange. The total money he spent on apples and oranges is Rs. 43. What is the formula for this statement?

A
5x + 6(x + 2) = 43

B
5(x + 2) + 6x = 43

C
11x + 2 = 43

D
5x + 6x = 4

Solution

Let the cost of an orange = Rs. x
Cost of apple = Rs. (x + 2)
A.T.Q: 5(x + 2) + 6(x) = Rs. 43
5(x + 2) + 6x = 43
This is the required formula.
Question 3
1 / -0

The radius of a circle is 2 more than x. What is the area of the circle?

A
(x + 2)²

B
(x + 2)²

C
2 ( + x + 2)

D
2 (x + 2)

Solution

Radius of circle = x + 2
Area of the circle = r²
= (x + 2)²
Question 4
1 / -0

Rajiv bought 10 chairs and a table for Rs. 2500. The cost of a table is Rs. 100 more than the price of a chair. Frame a formula to express this.

A
10x + 100x = 2500

B
10 + x + 100 = 2500

C
10x + (100 + x) = 2500

D
100 + x = 2500

Solution

Let the cost of a chair be Rs. x.
Cost of a table = Rs. (100 + x)
Total cost = Rs. 2500
10 (x) + (100 + x) = Rs. 2500
10x + (100 + x) = 2500
Question 5
1 / -0

Rs. 500 is divided among two brothers. One brother gets Rs. 100 more than the other. Find the formula to express this.

A
x + (x + 100) = 500

B
x + 100 + 500

C
x²+ 100 = 500

D
x (x + 100) = 500

Solution

Let one brother gets Rs. x.
Other brother gets Rs. 100 more than x.
Other brother gets = Rs. (x + 100)
Thus, x + (x + 100) = 500
Question 6
1 / -0

Mr. Mehta bought some articles for Rs. 4800. He sold the articles at Rs. 50 each. Then, he made profit equal to the cost price of 10 articles. Frame a formula for this statement.

A
10x² = 50x - 4800

B
10x + 50x = 4800

C

D

Solution

Let the total number of articles = x
Cost price of all articles = Rs. 4800
Cost price of one article = Rs.
Cost price of 10 articles =
Selling price of one article = Rs. 50
Selling price of x articles = (50 x) = Rs. 50x
Profit incurred = Cost price of 10 articles =
Thus, Profit = S.P - C.P
Question 7
1 / -0

Ram and Sham has total 500 toffees with them. Ram has 100 toffees more than the half of toffees with Sham. Frame the formula for the statement.

A
+ 100 = 500

B
+ 100 = 500

C
3x + 100 = 500

D
x +

Solution

Let Sham has x toffees with him.
Then, Ram has toffees =
From the question, x + = 500
Question 8
1 / -0

If x = 2, y = 3 and z = 5, find the value of x²yz + xy² + (y - zx) + (z - yx) + (x - yz).

A
121

B
129

C
135

D
130

Solution

x²yz + xy² z + (y - zx) + (z - yx) + (x - yz)
Putting x = 2, y = 3 and z = 5, we get
= (2)² (3) (5) + (2) (3)² (5) + (3 - (5)(2)) + (5 - (2)(3)) + (2 - (3)(5))
= 60 + 90 + (-7) + (-1) + (-13)
= 150 - 7 - 1 - 13
= 150 - 21
= 129
Question 9
1 / -0

Change the subject of the formula f = to b.

A

B

C

D

Solution

f =
f(2 + 5b) = 3a + 4b. (On cross multiplying)
2f + 5fb = 3a + 4b
2f + 5fb - 4b = 3a + 4b - 4b
b(5f - 4) = 3a - 2f
b = .
Question 10
1 / -0

If y = , find the value of x at a = 2, y = 1 and b = 3.

A
-2

B
-1

C
4

D
1

Solution

y =
y(4x - b) = 3x -a
4yx - by = 3x - a
4yx - 3x = -a + by
x(4y - 3) = -a + by
x =
At, a = 2, b = 3 and y = 1
x =
= = = 1
Question 11
1 / -0

Find the value of 2abc + a² + b² + c² at a = 2, if b = -1 and c = -3.

A
24

B
23

C
26

D
27

Solution

2abc + a²+ b²+ c²
a = 2, b = -1, c = -3
= 2 (2) (-1) (-3) + (2)² + (-1)² + (-3)²
= 12 + 4 + 1 + 9
= 26
Question 12
1 / -0

Find the value of `l` from the formula A = rl at A = 66, r = 3 and = .

A
7

B
-4

C
-3

D
6

Solution

A = rl
l =
If A = 66, r = 3 and =
Then, I =
l =
l = 7
Question 13
1 / -0

Changing the subject of m = to n, find n where l = -2 and m = 4.

A
-4

B
-2

C
4

D
6

Solution

m =
(3l - n) m = 2l + n
3lm - mn = 2l + n
-n - mn = 2l - 3lm
n(-1 - m) = 2l - 3lm
If l = -2 and m = 4
n =
n =
n =
n =
n =
n = -4
Question 14
1 / -0

Find the value of 'a' in = 6 at y = 2.

A

B

C

D

Solution

= 6
y – 3a = 6 (y + 3a)
y – 3a = 6y + 18a
5y = –21a
a = = = .
Question 15
1 / -0

Making R as the subject of the formula A = P , find R when A = 9261 and p = 8000.

A
6

B
5

C
8

D
10

Solution

A = P
=
= 1 +
x 100 = R
A = 9261 and P = 8000
Then, R = x 100 = R = x 100
= R = x 100 = 5