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Profit and Loss Test - 14

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Profit and Loss Test - 14
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  • Question 1
    1 / -0
    A certain sum of money lent on simple interest doubles itself in 10 years. In how many years will it triple itself?
    Solution
    Let the P = Rs. 100
    Amount = Rs. 200
    Time = 10 years
    Hence, SI = 200 - 100 = Rs. 100
    R = = 10%
    P = Rs. 100
    Amount = Rs. 300
    R = 10%
    SI = 300 - 100 = Rs. 200
    Time = = 20 years
  • Question 2
    1 / -0
    Find the minimum number of years for which simple interest must be reckoned at 5% p.a. on Rs. 512.50 so that the interest may be an exact number in rupees.
    Solution
    Let P = Rs. 512.50
    R = 5%
    Let Time = x
    ∴ S.I. =
    can be an exact number (minimum) if x = 8.
    Therefore, time = 8 years.
  • Question 3
    1 / -0
    John borrowed Rs. 3000 from Mohan at a rate of 10% p.a simple interest for 3 years. At the end of the year, he paid the interest for that year and part of the loan, altogether Rs. 800. Similarly, he paid Rs. 800 at the end of the 2nd year. What sum must he pay now to clear off the debt?
    Solution
    Total Amount to be paid In first year = Rs.3300

    Remaining amount after paying interest plus part of the loan = 3300- 800 = RS.2500

    Now, Total Amount to be paid after second year = Rs.2750 ( P + SI)

    Remaining amount after paying interest plus part of the loan = 2750- 800 = Rs.1950

    Total amount to be paid off in the 3rd year = 1950 + 10 % SI = Rs. 2145


  • Question 4
    1 / -0
    Seema lent a certain sum of money at 12%; and in 7 years, the interest amounted to Rs. 800 less than the sum lent. What was the sum lent?
    Solution
    Let sum = x
    Interest = (x - 800)
    x - 800 =
    100x - 80,000 = 84x
    100x - 84x = 80,000
    16x = 80,000
    x = 5000
  • Question 5
    1 / -0
    Two equal sums of money were invested at simple interest, one at 3% and the other at 3.5%. At the end of 3 years, the interest received from the latter investment exceeded that received from the former investment by Rs. 120. Find the sum invested.
    Solution
    Let sum = x
    Rate = 3%
    Time = 3 years
    S.I. =
    2nd time sum = x
    Rate = 3.5%
    Time = 3 years
    S.I. =
    = 120
    = 120
    x = = Rs.8000
  • Question 6
    1 / -0
    Sudhir has Rs. 7000. He lends Rs. 3000 at 5% and Rs. 2000 at 6%. At what rate must he lend the remainder of his money so that his total income may be 8% on Rs. 7000? (Duration of all the lending is 1 year.)
    Solution
    Income on Rs. 3000 = = Rs. 150
    Income on Rs. 2000 = = Rs. 120
    Remainder amount = 7000 - 5000 = Rs. 2000
    Income desired = = Rs. 560
    Interest required on Rs. 2000 = 560 - (150 + 120) = 560 - 270 = Rs. 290

    Rate = = 14%
  • Question 7
    1 / -0
    What annual payment will discharge a debt of Rs. 4910 due in 5 years, the rate of interest being 9% per annum?
    Solution
    Let Rs. P is the annual payment
    The amount of Rs. P for 4 years at 9% =
    The amount of Rs. P for 3 years at 9% =
    The amount of Rs. P for 2 years at 9% = P
    The amount of Rs. P for 1 year at 9% = P
    These four amounts and the last annual payments of Rs. P will discharge the debt of Rs.4910
    = 4910
    = 4910
    = 4910
    P = = 832.20.
  • Question 8
    1 / -0
    A man borrows Rs. 3000 at 6% per annum from B. Each year, he pays Rs. 400 for interest and part payment of the debt. What amount does A owe at the end of 3 years?
    Solution
    Sum = Rs.3000
    R = 6%
    T = 3 years
    SI for 1st year =
    = 180
    Amount = 3000 + 180 = 3180
    Remaining sum = 3180 - 400
    = 2780
    SI for 2nd year = = 166.80
    Amount = 2780 + 166.80
    = 2946.80
    Remaining sum = 2946.80 - 400
    = 2546.80
    SI for 3rd year =
    = 152.81
    = 2546.80 + 152.81
    Amount = Rs.2699.61
    Hence, amount to be given = 2699.61 - 400 = Rs. 2299.61
  • Question 9
    1 / -0
    A and B borrow a total sum of Rs. 30000 from C at 4% p.a. for 5 years and 5% for 4 years, respectively. Find out the sum borrowed by A, if A's interest is double than that of B's interest.
    Solution
    Let the sum borrowed by A = Rs. x

    Then, the sum borrowed by B = Rs. 30000 - x

    Hence, interest of A =

    Interest of B = =

    Hence, =

    x = 60000 - 2x

    3x = 60000

    x = Rs. 20000
  • Question 10
    1 / -0
    Divide Rs. 30,000 into the two sums such that if the first be put out at S.I. for 5 years at p.c; and the second for 4 years at 5%, Interest of the first sum shall be double that of the second. If first part be x & other is y, then find the value of y.
    Solution
    Let the 1st part = x
    And 2nd part = y = 30,000 - x
    Interest for 1st part =
    Interest for 2nd part =
    =

    20x = 40 ´ 30000 - 40x
    60x = 40 ´ 30000
    x = 20,000
    hence y = 30,000 - 20,000
    = Rs.10,000
  • Question 11
    1 / -0
    A machinery depreciates in cost every year at the rate of 5% of its value in the beginning of that year. Find out its original value if at the end of 3 years, its depreciated value is Rs. 205770
    Solution
    Let the value of machinery = x
    Rate of depreciation = 5%
    Time = 3 years
    205770 =
    =
    x =
    = Rs.240,000
  • Question 12
    1 / -0
    A certain sum of money at certain rate of interest amounts to Rs. 5900 in 3 years and Rs. 7400 in 8 years, it will amount to Rs. 8000 at the same rate of interest in
    Solution
    Amount in 3 years = Rs.5900
    Amount in 8 years = Rs.7400
    Hence interest for 5 years = 7400 - 5900 = 1500
    Interest for 3 years =
    = 900
    Sum = 5900 - 900 = 5000
    Rate = = 6%
    Now amount = Rs.8000
    Interest = 8000 - 5000
    = 3000
    Time = = 10 years
  • Question 13
    1 / -0
    Sahil borrows Rs. 16550 from Rishab to be paid back with compound interest at the rate of 10% p.a. in 3 years, in 3 equal yearly instalments. Find the value of each instalment.
    Solution
    Let the value of each equal instalment be Rs. e.
    So, 16550(1 + 0.10)3 = e(1 + 0.10)2 + e(1 + 0.10) + e
    Or, 16550(1.331) = 1.21e + 1.1e + e = 3.31e
    Or, e = 6655
    Thus, the equal instalment is of Rs. 6655.
    Hence, answer option 4 is correct.
  • Question 14
    1 / -0
    A man borrows money at 6% per annum interest payable yearly and lends it immediately at 6% per annum compound interest payable half-yearly and thereby gains Rs. 45 at the end of the year. What is the sum borrowed?
    Solution
    Let the sum borrowed be Rs. x.
    Rate = 6%
    Time = 1 year
    Amount = x =
    He received interest payable half yearly.
    = x
    = x
    x = 45
    x = 45
    = 45
    x = = Rs. 50,000
  • Question 15
    1 / -0
    The compound interest on a certain sum for 3 years at the rate of 5% per annum is Rs. 2522. The simple interest on the same sum for double the time at half the rate percent per annum is:
    Solution
    Let sum = Rs. x
    2522 =
    2522 = x
    2522 = x
    x = 16,000
    x = 16,000
    R = %
    T = 6 years
    S.I. = = Rs. 2400
  • Question 16
    1 / -0
    There is 60% increase in an amount in 6 years at SI. What will be CI of Rs. 12000 after 3 years at the same rate?
    Solution
    Suppose, P = Rs. 100
    Time = 6 years
    Hence, interest = 160 - 100 = 60
    Rate = = 10%
    Now, P = Rs. 12000
    T = 3 years
    R = 10%
    Amount = 12000
    =
    = Rs. 15972
    Hence, CI = 15972 - 12000 = Rs. 3972
  • Question 17
    1 / -0
    A sum of money was borrowed and paid back in two annual equal installments of Rs. 882 each, paying 5% compound interest. The sum borrowed was
    Solution
    Let each instalment be Rs. x and principal for the first and the second years be P1 and P2, respectively.
    x = P1
    P1 =
    x = P2
    P2 =
    P1 + P2 = x
    P1 + P2 = x
    P = 882 = 2 20 41 = Rs. 1640
    Hence, the sum of money borrowed = Rs. 1640
  • Question 18
    1 / -0
    The least number of complete years in which a sum of money put at 25% C.I. will be more than treble is:
    Solution
    Let P = Rs.100
    Rate = 25%
    Time = 1 year
    Interest = = 25
    Amount after 1 year = 125
    Interest for 2nd year =
    = 31.25
    Amount after 2 years = 156.25
    Amount after 3 years = 200.31
    Amount after 4 years = 250.38
    Amount after 5 years = 312.98
    Hence after 5 years it will be treble
  • Question 19
    1 / -0
    The effective annual rate of interest corresponding to a nominal rate of 8% per annum payable quarterly is
    Solution
    Let P = Rs.100
    R = 8%
    T = 1 year (quarterly)
    Amount = 100
    =
    = 108.24
    Effective rate of interest = 108.24 - 100 = 8.24%
  • Question 20
    1 / -0
    A sum of money invested at compound interest amounts to Rs. 4624 in two years and Rs. 4913 in three years. The sum invested is
    Solution
    Amount in two years = Rs. 4624
    Amount in three years = Rs. 4913
    Hence, interest for one year on Rs. 4624 = Rs. 4913 - Rs. 4624 = Rs. 289

    Rate = = 6.25%

    Suppose the sum of money invested = Rs. P
    Then, according to the question:
    4624 =
    4624 = P
    P = = Rs. 4096
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