Logical Ability Test

Result

Logical Ability Test - 11

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

Directions For Questions

6 friends Aman, Biju, Charu, Daniel, Eric, Farhan own cars of different colors viz. Red, Blue, White, Black, Silver & Gold. Each of the friends owns an Even or an Odd numbered car.

Further information is known about them:-

a. The sum of the number on cars that are white and red in color is an even number.

b. The difference of number on cars that are Red and Silver in color is an odd number.

c. Biju owns an even numbered car.

d. 4 of the cars are even numbered and 2 are odd numbered cars.

e. Daniel owns a Blue colored car and Eric owns an odd numbered car.

f. Charu owns a silver colored car.

g. Aman and Daniel own the same numbered car.

h. The white colored car is even in number.

i. Gold colored car is owned by Biju

...view full instructions

White colored car is owned by?

A
Aman

B
Eric

C
Farhan

D
Either Aman or Farhan

Solution

From statement (b), Red no. car + Silver no. car = odd number

So the possibilities are (Red, Silver) = (Odd, even) or (even, odd), because

|even-odd| = odd number

From statement (a), White no. car + Red no. Car = Even number

So the possibilities are (Red, White) = (Even, Even) or (Odd, odd)

But in statement (h), we are given white colored car is even in number so the 2nd possibility of white colored car being odd in number can be ruled out.

So, White colored car is even and so is red color car. This gives us Silver colored car being odd in number.

Now Aman and Daniel own same numbered car and Eric owns an odd numbered car. So Aman and Daniel must own an even numbered car, because there are only two odd numbered cars (from statement (d)).

Charu owns silver colored car. So it will be odd in number (already established above).

So Charu and Eric own odd numbered car and rest all own even numbered car.

Biju owns gold colored car. So Eric who owns an odd numbered car cannot own gold, silver, blue, red and white colored cars. So he owns a black colored car.

So, collating all the information above, we have,

White colored car is owned by either Aman or Farhan.
Question 2
4 / -1

Directions For Questions

6 friends Aman, Biju, Charu, Daniel, Eric, Farhan own cars of different colors viz. Red, Blue, White, Black, Silver & Gold. Each of the friends owns an Even or an Odd numbered car.

Further information is known about them:-

a. The sum of the number on cars that are white and red in color is an even number.

b. The difference of number on cars that are Red and Silver in color is an odd number.

c. Biju owns an even numbered car.

d. 4 of the cars are even numbered and 2 are odd numbered cars.

e. Daniel owns a Blue colored car and Eric owns an odd numbered car.

f. Charu owns a silver colored car.

g. Aman and Daniel own the same numbered car.

h. The white colored car is even in number.

i. Gold colored car is owned by Biju

...view full instructions

Red colored car is owned by?

A
Aman

B
Eric

C
Farhan

D
Either Aman or Farhan

Solution

From statement (b), Red no. car + Silver no. car = odd number

So the possibilities are (Red, Silver) = (Odd, even) or (even, odd), because

|even-odd| = odd number

From statement (a), White no. car + Red no. Car = Even number

So the possibilities are (Red, White) = (Even, Even) or (Odd, odd)

But in statement (h), we are given white colored car is even in number so the 2nd possibility of white colored car being odd in number can be ruled out.

So, White colored car is even and so is red color car. This gives us Silver colored car being odd in number.

Now Aman and Daniel own same numbered car and Eric owns an odd numbered car. So Aman and Daniel must own an even numbered car, because there are only two odd numbered cars (from statement (d)).

Charu owns silver colored car. So it will be odd in number (already established above).

So Charu and Eric own odd numbered car and rest all own even numbered car.

Biju owns gold colored car. So Eric who owns an odd numbered car cannot own gold, silver, blue, red and white colored cars. So he owns a black colored car.

So, collating all the information above, we have,

Red colored car is owned by either Aman or Farhan.
Question 3
4 / -1

Directions For Questions

6 friends Aman, Biju, Charu, Daniel, Eric, Farhan own cars of different colors viz. Red, Blue, White, Black, Silver & Gold. Each of the friends owns an Even or an Odd numbered car.

Further information is known about them:-

a. The sum of the number on cars that are white and red in color is an even number.

b. The difference of number on cars that are Red and Silver in color is an odd number.

c. Biju owns an even numbered car.

d. 4 of the cars are even numbered and 2 are odd numbered cars.

e. Daniel owns a Blue colored car and Eric owns an odd numbered car.

f. Charu owns a silver colored car.

g. Aman and Daniel own the same numbered car.

h. The white colored car is even in number.

i. Gold colored car is owned by Biju

...view full instructions

Which of the following is odd one out?

A
Aman

B
Biju

C
Daniel

D
Eric

Solution

From statement (b), Red no. car + Silver no. car = odd number

So the possibilities are (Red, Silver) = (Odd, even) or (even, odd), because

|even-odd| = odd number

From statement (a), White no. car + Red no. Car = Even number

So the possibilities are (Red, White) = (Even, Even) or (Odd, odd)

But in statement (h), we are given white colored car is even in number so the 2nd possibility of white colored car being odd in number can be ruled out.

So, White colored car is even and so is red color car. This gives us Silver colored car being odd in number.

Now Aman and Daniel own same numbered car and Eric owns an odd numbered car. So Aman and Daniel must own an even numbered car, because there are only two odd numbered cars (from statement (d)).

Charu owns silver colored car. So it will be odd in number (already established above).

So Charu and Eric own odd numbered car and rest all own even numbered car.

Biju owns gold colored car. So Eric who owns an odd numbered car cannot own gold, silver, blue, red and white colored cars. So he owns a black colored car.

So, collating all the information above, we have,

Odd one out is Eric. He owns an odd numbered car.
Question 4
4 / -1

Directions For Questions

6 friends Aman, Biju, Charu, Daniel, Eric, Farhan own cars of different colors viz. Red, Blue, White, Black, Silver & Gold. Each of the friends owns an Even or an Odd numbered car.

Further information is known about them:-

a. The sum of the number on cars that are white and red in color is an even number.

b. The difference of number on cars that are Red and Silver in color is an odd number.

c. Biju owns an even numbered car.

d. 4 of the cars are even numbered and 2 are odd numbered cars.

e. Daniel owns a Blue colored car and Eric owns an odd numbered car.

f. Charu owns a silver colored car.

g. Aman and Daniel own the same numbered car.

h. The white colored car is even in number.

i. Gold colored car is owned by Biju

...view full instructions

What of the following is odd one out ?

A
White colored car

B
Gold colored car

C
Blue colored car

D
Black colored car

Solution

From statement (b), Red no. car + Silver no. car = odd number

So the possibilities are (Red, Silver) = (Odd, even) or (even, odd), because

|even-odd| = odd number

From statement (a), White no. car + Red no. Car = Even number

So the possibilities are (Red, White) = (Even, Even) or (Odd, odd)

But in statement (h), we are given white colored car is even in number so the 2nd possibility of white colored car being odd in number can be ruled out.

So, White colored car is even and so is red color car. This gives us Silver colored car being odd in number.

Now Aman and Daniel own same numbered car and Eric owns an odd numbered car. So Aman and Daniel must own an even numbered car, because there are only two odd numbered cars (from statement (d)).

Charu owns silver colored car. So it will be odd in number (already established above).

So Charu and Eric own odd numbered car and rest all own even numbered car.

Biju owns gold colored car. So Eric who owns an odd numbered car cannot own gold, silver, blue, red and white colored cars. So he owns a black colored car.

So, collating all the information above, we have,

Odd one out is Black Colored car. It is an odd numbered car.
Question 5
4 / -1

Directions For Questions

6 friends Aman, Biju, Charu, Daniel, Eric, Farhan own cars of different colors viz. Red, Blue, White, Black, Silver & Gold. Each of the friends owns an Even or an Odd numbered car.

Further information is known about them:-

a. The sum of the number on cars that are white and red in color is an even number.

b. The difference of number on cars that are Red and Silver in color is an odd number.

c. Biju owns an even numbered car.

d. 4 of the cars are even numbered and 2 are odd numbered cars.

e. Daniel owns a Blue colored car and Eric owns an odd numbered car.

f. Charu owns a silver colored car.

g. Aman and Daniel own the same numbered car.

h. The white colored car is even in number.

i. Gold colored car is owned by Biju

...view full instructions

Which of the following pair of cars can have their sum as an even number

A
Black, white

B
Black, gold

C
Black, Red

D
Black, Silver

Solution

From statement (b), Red no. car + Silver no. car = odd number

So the possibilities are (Red, Silver) = (Odd, even) or (even, odd), because

|even-odd| = odd number

From statement (a), White no. car + Red no. Car = Even number

So the possibilities are (Red, White) = (Even, Even) or (Odd, odd)

But in statement (h), we are given white colored car is even in number so the 2nd possibility of white colored car being odd in number can be ruled out.

So, White colored car is even and so is red color car. This gives us Silver colored car being odd in number.

Now Aman and Daniel own same numbered car and Eric owns an odd numbered car. So Aman and Daniel must own an even numbered car, because there are only two odd numbered cars (from statement (d)).

Charu owns silver colored car. So it will be odd in number (already established above).

So Charu and Eric own odd numbered car and rest all own even numbered car.

Biju owns gold colored car. So Eric who owns an odd numbered car cannot own gold, silver, blue, red and white colored cars. So he owns a black colored car.

So, collating all the information above, we have,

Black is an odd numbered car and so is silver. Odd + odd makes an even number.
Question 6
4 / -1

Directions For Questions

6 friends Aman, Biju, Charu, Daniel, Eric, Farhan own cars of different colors viz. Red, Blue, White, Black, Silver & Gold. Each of the friends owns an Even or an Odd numbered car.

Further information is known about them:-

a. The sum of the number on cars that are white and red in color is an even number.

b. The difference of number on cars that are Red and Silver in color is an odd number.

c. Biju owns an even numbered car.

d. 4 of the cars are even numbered and 2 are odd numbered cars.

e. Daniel owns a Blue colored car and Eric owns an odd numbered car.

f. Charu owns a silver colored car.

g. Aman and Daniel own the same numbered car.

h. The white colored car is even in number.

i. Gold colored car is owned by Biju

...view full instructions

Which of the following pairs of cars can have their product as an odd number

A
Black, white

B
Black, gold

C
Black, Red

D
Black, Silver

Solution

From statement (b), Red no. car + Silver no. car = odd number

So the possibilities are (Red, Silver) = (Odd, even) or (even, odd), because

|even-odd| = odd number

From statement (a), White no. car + Red no. Car = Even number

So the possibilities are (Red, White) = (Even, Even) or (Odd, odd)

But in statement (h), we are given white colored car is even in number so the 2nd possibility of white colored car being odd in number can be ruled out.

So, White colored car is even and so is red color car. This gives us Silver colored car being odd in number.

Now Aman and Daniel own same numbered car and Eric owns an odd numbered car. So Aman and Daniel must own an even numbered car, because there are only two odd numbered cars (from statement (d)).

Charu owns silver colored car. So it will be odd in number (already established above).

So Charu and Eric own odd numbered car and rest all own even numbered car.

Biju owns gold colored car. So Eric who owns an odd numbered car cannot own gold, silver, blue, red and white colored cars. So he owns a black colored car.

So, collating all the information above, we have,

Black is an odd numbered car and so is silver. Only odd * odd can make an odd number.
Question 7
4 / -1

Directions For Questions

In a language,

School Study Books playground is coded as ac ad aa ab.

Tiffin Study subject teacher is coded as ae af ag ab.

Playground subject teacher student is coded as ag ah ad af.

School playground subject student is coded as ad aa ah af.

...view full instructions

What is the code for teacher?

A
ab

B
ac

C
ad

D
ag

Solution

The words and their respective codes are highlighted in a similar fashion.

School Study Books playground = ac ad aa ab.

Tiffin Study subject teacher = ae af ag ab.

Playground subject teacher student = ag ah ad af.

School playground subject student = ad aa ah af.

The code for teacher is ag
Question 8
4 / -1

Directions For Questions

In a language,

School Study Books playground is coded as ac ad aa ab.

Tiffin Study subject teacher is coded as ae af ag ab.

Playground subject teacher student is coded as ag ah ad af.

School playground subject student is coded as ad aa ah af.

...view full instructions

What is the code for student?

A
ab

B
aa

C
ad

D
ah

Solution

The words and their respective codes are highlighted in a similar fashion.

School Study Books playground = ac ad aa ab.

Tiffin Study subject teacher = ae af ag ab.

Playground subject teacher student = ag ah ad af.

School playground subject student = ad aa ah af.

The code for teacher is ah
Question 9
4 / -1

Directions For Questions

In a language,

School Study Books playground is coded as ac ad aa ab.

Tiffin Study subject teacher is coded as ae af ag ab.

Playground subject teacher student is coded as ag ah ad af.

School playground subject student is coded as ad aa ah af.

...view full instructions

What is the code for Books?

A
af

B
ac

C
ad

D
ag

Solution

The words and their respective codes are highlighted in a similar fashion.

School Study Books playground = ac ad aa ab.

Tiffin Study subject teacher = ae af ag ab.

Playground subject teacher student = ag ah ad af.

School playground subject student = ad aa ah af.

The code for teacher is ac