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Chemistry Test - 28

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Chemistry Test - 28
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following is the electron deficient molecule?

    Solution

    B2H6 is electron deficient molecule because boron atom has 3 half filled orbitals in excited state. In it 2 electrons of a B—H bond are involved in formation of 3 centre bond.

  • Question 2
    1 / -0

    Wood spirit is knowm as-:

    Solution

    Methanol, also known as methyl alcohol among others, is a chemical with the formula CH3OH (a methyl group linked to a hydroxyl group, often abbreviated MeOH). Methanol acquired the name wood alcohol because it was once produced chiefly by the destructive distillation of wood.

  • Question 3
    1 / -0

    In lab H2O2 is prepaired by-:

    Solution

    Ans-coldH2SO4+BaO2

    From barium peroxide-Laboratorymethod ofpreparation.Hydrogen peroxide is preparedfrom barium peroxide by the following methods: (a) By the action of dilute sulphuric acid. Apaste of hydrated barium peroxide (BaO2. 8H2O) isprepared inice – cold waterandthen added slowly to an ice-cold solution of 20% H2SO4.

  • Question 4
    1 / -0

    Amongst the following which one is not chiral?

    Solution

    3-Bromopentane is not chiral.

    Hence correct answer is option B

  • Question 5
    1 / -0

    Due to Frenkel defect,the density of ionic salts-

    Solution

    In Frenkel defect the density of ionic solids doesn't change and remains same.

  • Question 6
    1 / -0

    Iodoform test is not given by?

    Solution

    Ans 3- pentanone

    Iodoform test is notanswered by methanol CH3OH. Note: Compounds containing methyl keto (−CH3CO) group, or the compounds that can be easily oxidized to methyl ketones, give positiveiodoform test.

  • Question 7
    1 / -0

    Which type of crystals contain more than one Bravais lattice?

    Solution

    Monoclinic crystals have 2 Bravais lattices-simple and body central.

  • Question 8
    1 / -0

    The shape of O2F2 is similar to that of-:

    Solution

  • Question 9
    1 / -0

    The correct order of reactivity towards the electrophilic substitution of the compounds aniline(I),benzene(II) and nitrobenzene(III) is-

    Solution

    In aniline –NH2 group is attached with benzene ring. –NH2 group shows +M effect.So it activates the benzene ring.Hence rate of electrophilic substitution is increased due to increase in the electron density at o/p position.

    In case of nitrobenzene ,-NO2 deactivates the benzene ring , so in nitrobenzene rate of electrophilic substitution is lower than benzene.Hence order of SE reaction is-

    I > II > III .

  • Question 10
    1 / -0

    Phenelzine and Iproniazid are-:

    Solution

    both (a) and (b)

    Hence correct answer is option C

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