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Mathematics Test - 18

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Mathematics Test - 18
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Three numbers, the first number is two times the second and the second number is three times the third number. If the average of all three is 21, then find the largest number of three numbers?

    Solution

    Considered III number = x

    II number = 2x

    I number = 4 x x = 3 × 3 = 9x = 3 × 3 = 9

    Large number = 4 × 9 = 36

  • Question 2
    1 / -0

    Find the value of -

    \(\left|\begin{array}{ccc}w^{3} & w^{2} & w \\ w^{5} & 1 & w \\ w^{4} & w^{3} & w^{2}\end{array}\right|\)
    Solution

  • Question 3
    1 / -0

    Find out the value of n in the expansion (5+x/7)n,, where x10 and x11 are equal.

    Solution

  • Question 4
    1 / -0

    Among the following alternatives, which represents each bar is for a range of data?

    Solution

    Bar graph is used to represent the grouped data with rectangular bars that can be plotted vertically or horizontally.

    Histogram is also used to represent the grouped data graphically in bars. It is similar to Bar graph, but in a histogram each bar is for range of data.

    Pie chart is a circular representation of grouped data.

    Frequency polygons are the graphical representation of grouped data by understanding the shapes of distribution.

  • Question 5
    1 / -0

    The integral forcos2x+sin2xcos2xsin2xdxis.

    Solution

  • Question 6
    1 / -0

    Letfx=log1-x+x2-1x=?Then Domain

    Solution

    f(x) = g(x) + h(x)

    g(x) is defined only when 1 – x > 0

    When x < 1

    Dom (g) = [-∞, 1]

    h(x) is defined x² - 1 ≥ 0

    When x ≥ 1 or x ≤ -1

    Dom (h) = [-∞, -1] or [1, ∞]

    Dom (f) = Dom (g) U Dom (h)

    = [-∞, -1]

  • Question 7
    1 / -0

    A shopkeeper bought two articles for Rs.68250. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each article is same, then the difference between their cost prices is -

    Solution

    Let the cost price of first and the second article be Rs.x and y respectively.

  • Question 8
    1 / -0

    The 10th term in the expansion of (x² - 2x + 1)20 is:

    Solution

    To find the general term of the binomial expansion (1 - a)n, following formula is used:

    Tr + 1 = (-1)r nCr ar

    The given equation can be re - written as:

    x² - 2x + 1 = 1 - x(1 - x)

    Let x(1 - x) = y

    So, x² - 2x + 1 = 1 - y

    So, the 10th term of the expansion will be:

    T10 = 20C10y10

    Put the value of y as (x – x²)

    T10 = 20C10(x – x²)10

  • Question 9
    1 / -0

    The largest possible set of real numbers which can be the domain of
    fx=1-1xis

    Solution

  • Question 10
    1 / -0

    Solution

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