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Chemistry Test - 25

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Chemistry Test - 25
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  • Question 1
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    Solution

  • Question 2
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    Consider the following statement in respect of zero order reaction.
    I. The rate of the reaction is independent of reactant concentration.
    II. The rate of the reaction is independent of temperature.
    III. The rate constant of the reaction is independent of temperature.
    IV. The rate constant of reaction is independent of reactant concentration.
    Choose the correct statements/s

    Solution

    (i) Rate \(=\mathrm{K}[\mathrm{A}]^{o}\)

    (ii) Rate constant depends only on temperature

    For a zero order reaction rate and rate constant are independent of reactant concentration.

  • Question 3
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    The main oxides formed on combustion of Li, Na and K in excess of air are respectively:

    Solution

  • Question 4
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    Which of the following reactions can be used to change benzaldehyde to cinnamic acid?

    Solution

    When benzaldehyde is heated with acetic anhydride in the presence of sodium acetate, condensation product is obtained which on hydrolysis give α,β-unsaturated acid (such as cinnamic acid) and the reaction is known as Perkin's reaction.

    Knoevenagal condensation:-

    Reformatsky reaction condenses aldehydes & ketones with α halo esters using a metallic Zn to form aβ hydroxy-ester.

    Benzoin condensation: The benzoin condensation is a condensation reaction between two aldehydes. The reaction generally or glyoxals the reaction produces an acyloin.

  • Question 5
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    Which of the following is not a characteristic property of chemical equilibrium?

    Solution

    Based on theory ;ng=0

    no effect of catalyst

  • Question 6
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    How many optical isomer will the tartaric acid show?

    Solution

    Answer(A)

    3

  • Question 7
    1 / -0

    Solution

    The equations are said to be balanced when there are same number of atoms of every element on each side of the equation.

  • Question 8
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    A certain metal when irradiated by light r=3.2×1016 Hz emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light r=2.0×1016 Hz. Then of metal is

    Solution

    \((K E)_{1}=h v_{1}-h v_{0}\)

    \((K E)_{2}=h v_{2}-h v_{0}\)

    As, \((K E)_{1}=2 \times(K E)_{2}\)

    \(\therefore \quad h v_{1}-h v_{0}=2\left(h v_{2}-h v_{0}\right)\)

    Or, \(h v_{0}=2 h v_{2}-h v_{1}\)

    Or, \(v_{0}=2 v_{1}-v_{1}\)

    \(=2 \times\left(2 \times 10^{16}\right)-\left(3.2 \times 10^{16}\right)\)

    \(=0.8 \times 10^{16} H z=8 \times 10^{15} H z\)

  • Question 9
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    0.005 M acid solution has 5 pH. The percentage ionisation of acid is

    Solution

  • Question 10
    1 / -0

    When phenolic ether is heated with HI, it yields

    Solution

    When phenolic ether is heated with HI, it gives alkyl halide and phenol

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