Physics Test

Result

Physics Test - 9

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Two rods of the same length and diameter having thermal conductivities K₁and K₂are joined in parallel. The equivalent thermal conductivity of the combination is

A
K₁K₂/K₁+K₂

B
k₁ + k₂

C

D

Solution
Question 2
1 / -0

The number of turns of primary and secondary coils of a transformer is 5 and 10 respectively and mutual inductance of the transformer is 25 H. Now, the number of turns in primary and secondary are made 10 and 5 respectively. Mutual inductance of transformer will be

A
25 H

B
12.5 H

C
50 H

D
6.25 H

Solution
Question 3
1 / -0

A candle placed 25cm from a lens forms an image on a screen placed 75cm on the other side of the lens. The focal length and type of the lens should be

A
+ 18.75 cm and convex lens

B
- 18.75 cm and convex lens

C
+ 20.25 cm and convex lens

D
- 20.25 cm and convex lens

Solution
Question 4
1 / -0

A cell of emf E is connected across a resistance R. The potential difference between the terminals of the cell is found to be V. The internal resistance of the cell must be -

A

B

C

D

Solution
Question 5
1 / -0

Equivalent resistance between A and B is-

A

B

C

D

Solution
Question 6
1 / -0

A particle is moving in circular path clockwise as shown with decreasing speed. When it is at point A. the direction of its acceleration may be given as

A

B

C

D

Solution

Since its speed is decreasing so its tangential acceleration is opposite to v. When it is at A
Question 7
1 / -0

What would be the magnetic field produced due to a long straight wire carrying 3 A current at a point 1/2m away from it?

A
0.012 Gauss

B
0.22 Gauss

C
3.4 Tesla

D
0.12 Tesla

Solution

Magnetic field due to infinitely long wire is
\[
\begin{array}{l}
B=\frac{\mu_{0} I}{2 \pi r} \\
=\frac{4 \pi \times 10^{-7}}{2 \pi} \times \frac{3}{\frac{1}{2}} \\
\because 1 \mathrm{T}=10^{4} \text { gauss }(\mathrm{G}) \\
B=12 \times 10^{-7} \times 10^{4} \mathrm{G}=12 \times 10^{-3} \mathrm{G}=0.012 \mathrm{G}
\end{array}
\]
Question 8
1 / -0

For small areas of the orifice, the velocity of efflux of a liquid through an orifice in the bottom of the tank depend upon,

A
cross-sectional area of the container

B
Height of liquid

C
atmospheric pressure

D
Density of liquid

Solution
Question 9
1 / -0

In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is

A
5

B
2

C
0.5

D
0.2

Solution
Question 10
1 / -0

A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10 cm. What is the loss in energy?

A
25%

B
75%

C
50%

D
100%

Solution