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Chemistry Test - 1

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Chemistry Test - 1
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  • Question 1
    1 / -0

    Which of the following statements is correct?

    Solution

    (1) Hydrogenation of an alkene is a heterogeneous process which occurs on the surface of a solid catalyst (PtO2 or Pd/C). The addition occurs with syn stereochemistry (both hydrogens add from the same side). For cis isomer, the product is a meso compound.

    (3) The addition of two hydroxyl groups involves syn addition (on the same side of a double bond). The result is same as that of hydrogenation. The cis isomer produces meso compound.

    (4) The addition of two hydroxyl groups involves syn addition (on the same side of a double bond). The result is same as that of hydrogenation. The trans isomer produces racemic mixture.

  • Question 2
    1 / -0

    Which of the following orders of amine in terms of basic nature in aqueous solution is correct?

    Solution

    Considering the inductive effect and the steric hindrance of alkyl groups, CH3NH2, (CH3)2NH and (CH3)3N can be arranged in the increasing order of their basic strengths as follows.

    (CH3)2NH > CH3NH2 > (CH3)3N

    In C6H5NH2, N is directly attached to the benzene ring. Thus, the lone pair of electrons on the N−atom is delocalised over the benzene ring. Again, due to −I effect of C6H5 group, the electron density on the N−atom in C6H5NH2 is lower than that on the N−atom in (CH3)3N. Therefore, (CH3)3N is more basic than C6H5NH2. Considering the inductive effect and the steric hindrance of alkyl groups, CH3NH2, (CH3)2NH, (CH3)3N and C6H5NH2 can be arranged in the increasing order of their basic strengths as

    (CH3)2NH > CH3NH2 > (CH3)3N > C6H5NH2 

    Note: This is the correct order in case of aqueous solutions.

    In the gas phase, the order would be (CH3)2NH > (CH3)3N > CH3NH2 > C6H5NH2

  • Question 3
    1 / -0

    Which of the following does not exist as a zwitter ion?

    Solution

    The lone pair of electrons on the -NH2 group is donated towards the benzene ring due to resonance effect. As a result, acidic character of -COOH group and basic character of -NH2 group decrease. Therefore, the weakly acidic -COOH group cannot transfer an H+ ion to the weakly basic -NH2 group. Thus, o- and p-aminobenzoic acids do not exist as zwitter ions.

  • Question 4
    1 / -0

    Which of the following is paramagnetic?

    Solution

    The paramagnetic substances are those which are freely magnetised when placed in a magnetic field. All the species which have unpaired electrons, are paramagnetic. When placed in a magnetic field, the domains of the unpaired electrons get aligned in the same direction. 

    KO2, the superoxide of potassium, is paramagnetic because it has unpaired electrons.

    SiO2, TiO2 and BaO2 are all diamagnetic, as they have paired electrons.

  • Question 5
    1 / -0

    Solution

  • Question 6
    1 / -0

    b-particle is emitted in radioactivity by

    Solution

    Since the nucleus does not contain b-particle, it is produced by the conversion of a neutron to a proton at the moment of emission.

  • Question 7
    1 / -0

    Which of the following molecules can act as an oxidising as well as a reducing agent?

    Solution

    Hydrogen peroxide (H2O2) can act as an oxidising as well as a reducing agent. 

    H2O2 as a reducing agent: 

    Ag2O + H2O2  2Ag + H2O + O2

    H2O2 as an oxidising agent:

    PbS + 4H2O2  PbSO4 + 4H2O

  • Question 8
    1 / -0

    The above reaction is known as:

    Solution

    The reaction is known as Sandmeyer reaction. The Sandmeyer reaction is a chemical reaction used to synthesise aryl halides from aryl diazonium salts. 

    Strecker reaction: The Strecker synthesis is a preparation of α-aminonitriles.

    For example:

    Wolff-Kishner reaction (Reduction): The Wolff-Kishner reduction is an organic reaction used to convert an aldehyde or ketone to an alkane using hydrazine, base, and thermal conditions.

    Stephen reduction reaction: The Stephen reaction is used to prepare aldehydes from nitriles or cyanides. 

  • Question 9
    1 / -0

    The dipole moment of  - X is 1.2 D. If the bond length of  - X is 2 , then calculate the percentage of ionic character in the bond.

    Solution

  • Question 10
    1 / -0

    1 L mixture of C3H8 and C5H12 is completely reacted with O2 to produce 3.5 L of CO2. Find the respective volumes of C3H8 and C5H12 in the mixture, when all the volumes are measured under similar conditions of temperature and pressure.

    Solution

    C3H8 + 5O2 3CO2 + 4H2O

    C5H12 + 8O2 5CO2 + 6H2O

    Let the volume of C3H8 be 'a' and that of C5H12 be 'b'.

    Now, 'a' L of C3H8 gives '3a' L of CO2 on combustion and 'b' L of C5H12 gives '5b' L of CO2.

    Under similar conditions of temperature and pressure, PV = nRT

    Or, V  n

    Therefore, a + b = 1 L and 3a + 5b = 3.5 L 

    On solving, we get 

    a = 0.75 L and b = 0.25 L

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