Chemistry Test - 3

The order of reactivity of alcohols towards hydrogen halides depends on the stability of the corresponding carbonium ion. As the stability of carbonium follows the order 3^o > 2^o > 1o, hence the order of reactivity of alcohols is 3^o > 2^o > 1^o.

As we move from left to right across a period, ionisation enthalpy increases with increasing atomic number. So, the order of increasing ionisation enthalpy should be B < C < N < O.

But, N (1s² 2s² 2p³) has a stable half filled electron configuration. So, ionisation enthalpy of nitrogen is greater than oxygen. So, the correct order of increasing first ionisation enthalpy is B < C < O < N.

Hence, the order indicated in the option (2) is correct.

Silver reacts with dilute nitric acid to liberate nitric oxide (\(NO\)) gas.

\(3 \mathrm{Ag}+4 \mathrm{HNO}_{3} \text { (dil) } \rightarrow 3 \mathrm{AgNO}_{3}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{NO} \uparrow\)

Given: OH^- ion concentration is 10^-3 M.

We know, [H⁺][OH^-] = 10^-14

Similarly, the pH of HCI is 3 and the pH of NaCI is 7.

The orbital with highest value of (n + l) has the highest energy.

For set, 3, 2, 2, 1/2. 

Value of n + l is 3 + 2 = 5

It is the highest among given options, hence electron will have the highest energy for this set of quantum numbers.

As the particles are moving towards the anode, they carry negative charge. Hence, cation of electrolyte is useful for coagulation. Coagulating power of an ion increases with charge on it.

According to Faraday's Law of electrolysis, if the same amount of electricity is passed, the equivalents of Ag and O₂ deposited are equal.

Equivalent of Ag = Equivalent of O₂

Mond process is used for the refining of nickel. Nickel is heated with CO to form highly volatile nickel tetracarbonyl. It is then decomposed to pure nickel at high temperature.

 \(\mathrm{Ni}+4 \mathrm{CO} \stackrel{50^{\circ} \mathrm{C}}{\rightarrow} \mathrm{Ni}(\mathrm{CO})_{4} \stackrel{230^{\circ} \mathrm{C}}{\rightarrow} \mathrm{Ni}+4 \mathrm{CO}\)

Thus, \(\mathrm{T}_{1}\) and \(\mathrm{T}_{2}\) are \(50^{\circ} \mathrm{C}\) and \(230^{\circ} \mathrm{C}\) respectively.

The structures of P₄O₁₀ and P₄O₆ are as follows.

Hence, the number of P-O-P bridges is 6 in each.

Various enantiomers of 2,3-dichloropentane are represented as follows:

S or sinister (left) is used for counterclockwise configuration. R or rectus (right) is used for clockwise configuration.

But out of the various absolute configurations, only the configuration given in option (2) is correct.