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Physics Test - 2

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Physics Test - 2
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  • Question 1
    1 / -0

    Directions: The following question has four choices, out of which ONE or MORE can be correct.

    A particle of mass m moves on the x-axis as follows:

    It starts from rest at t = 0 from the point x = 0, and comes to rest at t = 1 at the point x = 1. No other information is available about its motion at intermediate times (0 < t < 1). If α denotes the instantaneous acceleration of the particle, then

    Solution

  • Question 2
    1 / -0

    Positive point charges q1 and q2 are moving with velocities v1 and v2 as shown in the given figure. Mark the correct statements.

    Solution

  • Question 3
    1 / -0

    Directions: Study the following information and answer the question. 

    In YDSE, slits are separated by a distance of 2 mm and screen is placed 2 m from the plane of slits.

    The position of maxima is given in column I, the position of minima is given in column II and the fringe width/shifting of central maxima in given in column III.

    When the wavelength of 650 nm is used in the experiment, then the position of 3rd maxima, 5th minima and the fringe width is given by

    Solution

  • Question 4
    1 / -0

    Directions: Study the following information and answer the question. 

    In YDSE, slits are separated by a distance of 2 mm and screen is placed 2 m from the plane of slits.

    The position of maxima is given in column I, the position of minima is given in column II and the fringe width/shifting of central maxima in given in column III.

    If the slit S1 is covered with the slab of thickness 2 μm of the refractive index 1.5, then by how much distance does central maxima shift?

    Also find the position of the 3rd maxima above the central maxima and the position of 5th minima on the lower side from point O (shown in the figure). The wavelength of light used in the experiment is 650 nm.

    Solution

  • Question 5
    1 / -0

    Directions: Study the following information and answer the question. 

    In YDSE, slits are separated by a distance of 2 mm and screen is placed 2 m from the plane of slits.

    The position of maxima is given in column I, the position of minima is given in column II and the fringe width/shifting of central maxima in given in column III.

    If the whole apparatus is immersed in the liquid of the refractive index 1.5, find the positions of the 7th bright point and 8th dark point. Also, calculate the fringe width.

    Solution

  • Question 6
    1 / -0

    Two straight conducting rails form a right angle where their ends are joined. A conducting bar in contract with the rails starts at the vertex at t = 0 and moves with constant velocity v along them as shown. A magnetic field B is directed into page. The induced emf in the circuit at any time 't' is proportional to

    Solution

  • Question 7
    1 / -0

    A gas is undergoing a cyclic process as shown in the figure.

    For this cyclic process, mark the correct statement(s).

    Solution

    In the given V-P graph, cycle is anticlockwise. In corresponding P-V graph, cycle would be clockwise. Hence, work in done by the system against the surroundings using the first law of thermodynamics.

    dQ = dU + W

    For cyclic process, dU = 0

     dQ = W
    Hence, net heat is taken out of the system.

    Hence, the correct options are (A), (C).

  • Question 8
    1 / -0

    Directions: Read the following and answer the question.

    A simple harmonic motion is the oscillatory motion in which the restoring force, acting on the oscillatory particle, is directly proportional to the displacement i.e. F = -kx and for the angular oscillation τ = -kθ, where k is the spring constant. The total energy of the SHM remains constant and in mechanical oscillations, the kinetic energy of the particle is converted into potential energy and potential energy is converted into kinetic energy. The equivalent spring constant of the oscillating system is given in the column I, angular frequency of the oscillation is given in column II and kinetic energy of the oscillating system is given in column III. Assume the amplitude of the oscillation is A.

    A solid sphere of mass M and radius R is connected by the spring constant k. If the sphere rolls without slipping, then calculate the equivalent spring constant, angular frequency of oscillation and the kinetic energy, when the displacement is A/2.

    Solution


  • Question 9
    1 / -0

    Directions: Read the following and answer the question.

    A simple harmonic motion is the oscillatory motion in which the restoring force, acting on the oscillatory particle, is directly proportional to the displacement i.e. F = -kx and for the angular oscillation τ = -kθ, where k is the spring constant. The total energy of the SHM remains constant and in mechanical oscillations, the kinetic energy of the particle is converted into potential energy and potential energy is converted into kinetic energy. The equivalent spring constant of the oscillating system is given in the column I, angular frequency of the oscillation is given in column II and kinetic energy of the oscillating system is given in column III. Assume the amplitude of the oscillation is A.

    Calculate the equivalent spring constant, angular frequency of oscillation and the kinetic energy, when the displacement is A/2 for the figure pulley block as shown. 

    Solution


  • Question 10
    1 / -0

    Directions: Read the following and answer the question.

    A simple harmonic motion is the oscillatory motion in which the restoring force, acting on the oscillatory particle, is directly proportional to the displacement i.e. F = -kx and for the angular oscillation τ = -kθ, where k is the spring constant. The total energy of the SHM remains constant and in mechanical oscillations, the kinetic energy of the particle is converted into potential energy and potential energy is converted into kinetic energy. The equivalent spring constant of the oscillating system is given in the column I, angular frequency of the oscillation is given in column II and kinetic energy of the oscillating system is given in column III. Assume the amplitude of the oscillation is A.

    A hollow sphere of mass M and radius R is connected by the spring constant k. If the sphere rolls without slipping, then calculate the equivalent spring constant, angular frequency of oscillation and the kinetic energy at mean position.

    Solution


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