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Quantitative Ability Test - 8

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Quantitative Ability Test - 8
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Weekly Quiz Competition
  • Question 1
    4 / -1

    A man buys a certain number of oranges at 20 for Rs. 60 and an equal number at 30 for Rs. 60. He mixes them and sells them at 25 for Rs. 60. What is gain or loss percent?

    Solution

    Let the man buy 60 oranges (LCM of 20 and 30) of each kind. CP of the 60 oranges of the first find
    =60/20 x 60 =Rs.180.
    CP of oranges of second kind 60/30 x60 =Rs.120
    Total CP of 120 oranges
    =(180 +120) =Rs. 300
    Their SP =60/25 x120 =Rs 288
    Loss =Rs (300 -288) =Rs.12
    Loss percent =12/300 x100 =4%.

  • Question 2
    4 / -1
    If \(\tan ^{2} A \operatorname{cosec}^{2} B-1=\tan ^{2} A\) then which one is true:
    Solution
    \(\tan ^{2} A \operatorname{cosec}^{2} B-1=\tan ^{2} A\)
    \(\tan ^{2} A \operatorname{cosec}^{2} B=\sec ^{2} A\)
    \(\operatorname{cosec}^{2} B=\frac{1}{\cos ^{2} A \sin ^{2} A}\)
    \(\operatorname{cosec}^{2} B=\operatorname{cosec}^{2} A\)
    \(A=B\)
  • Question 3
    4 / -1

    Directions For Questions

    Direction : Read the following table carefully and Answer the Questions given below:

    The number of 5 different players from India and Australia

    ...view full instructions

    The ratio of total cricket players from both countries to the total football players from both countries is :

     

    Solution

    total cricket players = 50+65

    total football players = 40+50=90

    Ratio =115:90 = 23 : 18

  • Question 4
    4 / -1

    Directions For Questions

    Direction : Read the following table carefully and Answer the Questions given below:

    The number of 5 different players from India and Australia

    ...view full instructions

    The tennis player from Australia is how many percent of the total players from Australia.

    Solution

    Players from Australia=65+50+25+30+10=180

    % = 30/180*100 = 16 2/3%

  • Question 5
    4 / -1

    Directions For Questions

    Direction : Read the following table carefully and Answer the Questions given below:

    The number of 5 different players from India and Australia

    ...view full instructions

    The Volleyball players from India is how many percent more than the Chess players from Australia.

    Solution

    % = 45 -10 / 10 *100 = 350%

  • Question 6
    4 / -1

    Directions For Questions

    Direction : Read the following table carefully and Answer the Questions given below:

    The number of 5 different players from India and Australia

    ...view full instructions

    If the number of Cricket players from India is decreased by 20% then the difference of Cricket players from India to Tennis players from Australia is :

    Solution

    Cricket players from India after decrement

    = 50*80/100 =40

    Difference=40-30=10

  • Question 7
    4 / -1

    The height of an equilateral triangle is cm. 4√3 The ratio of the areas of its circumcircle and in circle is :

    Solution
    Height of triangle- \(\left.4 \sqrt{3} \cdot \frac{\sqrt{3}}{2} a \text { (a } \cdot \text { side of triangle }\right)\) Side of triangle(a)=8 in-radius of equilateral triangle(r)= \(\frac{a}{\sqrt{3}}\) circum-radius of equilateral triangle(R) \(=\frac{a}{2 \sqrt{3}}\) then area of circum-triangle and in-triangle \(\pi R^{2}: \pi r^{2}\)
    \(\Rightarrow 4: 1\)
  • Question 8
    4 / -1

    A, B and C has 40,x and y balls respectively. If B gives 20 balls to A then B has half the balls as C has. If they all had 60 balls more then average would have been 100. The ratio of x and y is:

    Solution
    \begin{equation}\begin{array}{lll}
    \mathrm{A} & \mathrm{B} & \mathrm{C} \\
    40 & \mathrm{x} & \mathrm{y} \\
    40+20 & \mathrm{x}-20 & -2(\mathrm{x}-20)
    \end{array}\end{equation}
    \(\frac{A+B+C+60}{3}=100\)
    \(\frac{60+x-20+2 x-40+60}{3}=100\)
    \(3 x=240 \Rightarrow x=80\)
    \(y=2(x-20) \Rightarrow 120\)
    \(x: y=80: 120 \Rightarrow x: y=2: 3\)
  • Question 9
    4 / -1

    Two pipes P and Q fill a tank in 3 min and 6 min respectively while the other pipe R can empty the full tank in 4 hr. All the pipes are opened together and after 2 min. Pipe R is closed, then the tank will in :

    Solution
    \begin{equation}\begin{array}{l}
    P-3 \uparrow \\
    Q-6 \uparrow \\
    R-4 \downarrow
    \end{array}|12| \begin{array}{l}
    4 \\
    2 \\
    3
    \end{array}\end{equation}
    \(2 \times(4+2-3)=2 \times 3=6\) Part filled
    Time to fill in remaining part \(=\frac{6}{6}=1\) min Total time \(=2+1=3\) min
  • Question 10
    4 / -1

    A can runs 25 km/hr faster than a bus in traveling a distance of 500 km. If bus takes 10 hr more than the car to travel this distance, then the speed of car and bus :

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