Chemistry Test

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Chemistry Test - 30

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Weekly Quiz Competition

Question 1
3 / -1

Which of the following would be expected to have the largest entropy per mole?

A
SO₂Cl₂(s)

B
SO₂Cl₂(g)

C
SO₂(g)

D
SO₂Cl₂(l)

Solution

If ∆H/∆T is the same for in case of SO₂ (g) and SO₂Cl₂ (g), then change in entropy is related to the molar mass of a substance. Entropies generally increase with molecular weight. Thus, SO₂Cl₂(g) has greater entropy.
Question 2
3 / -1

The conductivity of $0 \cdot 20 M$ solution of KCl at $298 K$ is $0.0248 S c m^{- 1}$ . Calculate its molar conductivity.

A
$124 S m o l^{- 1} c m^{2}$

B
$62 S m o l^{- 1} c m^{2}$

C
$248 S m o l^{- 1} c m^{2}$

D
$186 S m o l^{- 1} c m^{2}$

Solution

Given-
Conductivity $k = 0.0248 S c m^{- 1}$
$k = 0.0248 o h m^{- 1} c m^{- 1}$
Molar concentration $C = 0.20 M$
$C = 0.20 m o l L^{- 1}$
$C = \frac{0.2 m o l}{1000 c m^{3}}$
$C = 2 \times 10^{- 4} m o l c m^{- 3}$
Molar conductivity $= \frac{k}{C}$
$= \frac{0.0248 o h m^{- 1} c m^{- 1}}{2 \times 10^{- 4} m o l c m^{- 3}}$
$= 124 S m o l^{- 1} c m^{2}$
Question 3
3 / -1

What is the number of atoms in 100 amu of He? (Atomic weight of He is 4 u)

A
25

B
100

C
50

D
125

Solution

Mass of 1 atom of helium = 4 amu
So, in 100 amu, the number of helium atoms = 100/4 = 25
Question 4
3 / -1

Which one of the following is not included in internal energy?

A
Vibrational energy

B
Energy arising out of coriolis force

C
Electronic energy

D
Energy arising out of gravitational pull

Solution

It is the energy needed to create the system, but excludes the energy to displace the system's surroundings, any energy associated with a move as a whole, or due to external force fields. So it does not include energy arising out of gravitational pull.
Question 5
3 / -1

Which of the following does not crystallise in the rock-salt structure?

A
NaCl

B
KCl

C
MgO

D
CsCl

Solution

CsCL has body-centred cubical packing.
Question 6
3 / -1

The density of a gaseous substance at 1 atm pressure and 773 K is 0.4 g/l. If the molecular weight of the substance is 30 g, the forces existing among gas molecules are

A
repulsive

B
attractive

C
neutral

D
amphoteric

Solution

PV = ZnRT
Here, n (number of moles)=mass(W) / molar mass(M)
Then, PM=( W/V )ZRT
PM = ZdRT (where, M is molecular mass and d is density) [W/V=d (density)]
Substituting the values,
(1)(30) = Z(0.4)(0.082)(773)
Z = 1.183 > 1
Thus, forces are repulsive.
Question 7
3 / -1

If C₆H₆(I) + 15/2 O₂(g)→3H₂O(I) + 6CO₂(g); ΔH= – 3264.6 kJ mol^–1, then the energy obtained by burning 3.9 g of benzene in the air is

A
163.23 kJ

B
326.4 kJ

C
32.64 kJ

D
16.32 kJ

Solution

78 g of C₆H₆ gives heat
= 3264.6 kJ
∴3.9 g of C₆H₆ will give heat
= (3264.6 / 78) x 3.9= 163.23 kJ
Question 8
3 / -1

Which gas has the highest partial pressure in atmosphere?

A
CO₂

B
H₂O

C
0₂

D
N₂

Solution

Nitrogen is present in largest amount in the atmosphere. So it has the highest partial pressure in the atmosphere.
Question 9
3 / -1

When the rate of the reaction is equal to the rate constant, the order of the reaction is-

A
0

B
1

C
2

D
3

Solution

When the rate of the reaction is equal to the rate constant, the order of the reaction is 0.
Zero-order reactions are typically found when a material that is required for the reaction to proceed such as a surface or a catalyst is saturated by the reactants.
Question 10
3 / -1

Which of the following aqueous solutions will have the lowest vapour pressure at room temperature?

A
0.1 M CaCl₂

B
0.1 M glucose

C
0.1 M urea

D
0.1 M NaCl

Solution

The change in the colligative properties depends on the number of particles of the non-volatile solute,
The 0.1 M solution of CaCl₂ will furnish 0.3 moles of ions (assuming α=1).
Since the particles of the non-volatile solute are maximum in CaCl₂ the change in the colligative properties will be maximum.
Therefore the solution of CaCl₂ will have the lowest vapour pressure.
0.1 mol of NaCl will furnish 0.2 moles (2 x 0.1) of ions. While urea and glucose non-ionisable. Therefore, i = 1, and both will gives 0.1 moles of ions.

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Chemistry Test - 30

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Chemistry Test - 30

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Question 1

SO2Cl2(s)

SO2Cl2(g)

SO2(g)

SO2Cl2(l)

Solution

Question 2

124Smol-1cm2

62Smol-1cm2

248Smol-1cm2

186Smol-1cm2

Solution

Question 3

25

100

50

125

Solution

Question 4

Vibrational energy

Energy arising out of coriolis force

Electronic energy

Energy arising out of gravitational pull

Solution

Question 5

NaCl

KCl

MgO

CsCl

Solution

Question 6

repulsive

attractive

neutral

amphoteric

Solution

Question 7

163.23 kJ

326.4 kJ

32.64 kJ

16.32 kJ

Solution

Question 8

CO2

H2O

02

N2

Solution

Question 9

0

1

2

3

Solution

Question 10

0.1 M CaCl2

0.1 M glucose

0.1 M urea

0.1 M NaCl

Solution

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SO₂Cl₂(s)

SO₂Cl₂(g)

SO₂(g)

SO₂Cl₂(l)

$124 S m o l^{- 1} c m^{2}$

$62 S m o l^{- 1} c m^{2}$

$248 S m o l^{- 1} c m^{2}$

$186 S m o l^{- 1} c m^{2}$

CO₂

H₂O

0₂

N₂

0.1 M CaCl₂