Chemistry Test - 31

SiCl4 has 4 bond pairs and no lone pair, so it has a tetrahedral structure.

The following set of quantum numbers is possible for an electron in a 4f orbital:

n = 4

l = 3

m = -3, -2, -1, 0, 1, 2, 3

s = +1/2 or -1/2

Hence, option (4) is correct.

SiF₄ is tetrahedral as it contains 4 bond pairs and no lone pair.

SF₄ has a see-saw structure as it has 4 bond pairs and 1 lone pair.

Hence, SiF₄ and SF₄ are isostructural.

Number of moles of ammonia = 4.25/17 = 0.25 mol

Number of molecules in 0.25 mol of ammonia = 0.25 x 6.022 x 10²³

= 1.5 x 10²³

Total number of electrons in the molecule = Number of electrons of carbon atom + 2(number of electrons of oxygen atom)

= 6 + 2(8) = 22

The partial pressure of A in a mixture of A and other gases is the total pressure multiplied by the mole fraction of A.

In the present case,

Mole fraction of hydrogen =1/(1+(1/2)) = 2/3

The partial pressure of Hydrogen = 2/3 of total pressure

The first goes from 3^rd Bohr orbit to the 2^nd Bohr orbit, so the 3^rd line will be on the transition from 5^th Bohr orbit to the 2^nd Bohr orbit.

B.O. of O₂ = 1/2 [10 - 6] = 2; Paramagnetic

B.O. of O₂⁺= 1/2 [10 - 5] = 2.5; Paramagnetic

NH₄Cl is equivalent to NH₄⁺ and Cl^-

NH₄⁺ has 7 e^- of nitrogen and 3 e^- of hydrogen as 1 hydrogen is devoid of e^-.

Cl^- has 18 e^-

so in total = 7 + 3 + 18 = 28 e^-