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Quantitative Skills Test-6

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Quantitative Skills Test-6
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  • Question 1
    1 / -0

    2M + 5W + 6C does a work in 72 hours while 4M + 10C can complete the same work in 90 hours and 3M + 5W can complete the same work in 120 hours, then find in how much time will 5M + 4C complete the work.

    Solution

    Given:

    2M + 5W + 6C = 72 hours

    4M + 10C = 90 hours

    3M + 5W = 120 hours

    Formula:

    Efficiency = total work/total days

    Calculation:

    Let total work be x

     

  • Question 2
    1 / -0

    Directions For Questions

    For a country, CO2  emission (million metric tons) from various sectors are given in the following table.

     COemissions   (million metric   tons)          
         Sector    Power    Industry    Commercial    Agriculture  Domestic
         2005      500      200        150           80     100
         2006       600      300        200           90    110
         2007       650      320        250          100    120
         2008       700      400        300          150    150
         2009      800      450        320          200    180

    ...view full instructions

    What is the average annual growth rate of power has increased from 2005 to 2009?

    Solution

     

  • Question 3
    1 / -0

    Directions For Questions

    For a country, CO2  emission (million metric tons) from various sectors are given in the following table.

     COemissions   (million metric   tons)          
         Sector    Power    Industry    Commercial    Agriculture  Domestic
         2005      500      200        150           80     100
         2006       600      300        200           90    110
         2007       650      320        250          100    120
         2008       700      400        300          150    150
         2009      800      450        320          200    180

    ...view full instructions

    Which sector has recorded maximum growth in CO2 emissions from 2005 to 2009?

    Solution

     

  • Question 4
    1 / -0

    Directions For Questions

    For a country, CO2  emission (million metric tons) from various sectors are given in the following table.

     COemissions   (million metric   tons)          
         Sector    Power    Industry    Commercial    Agriculture  Domestic
         2005      500      200        150           80     100
         2006       600      300        200           90    110
         2007       650      320        250          100    120
         2008       700      400        300          150    150
         2009      800      450        320          200    180

    ...view full instructions

    By what percentage (%), the total emissions of CO2 have increased from 2005 to 2009?

    Solution

     

  • Question 5
    1 / -0

    Directions For Questions

    For a country, CO2  emission (million metric tons) from various sectors are given in the following table.

     COemissions   (million metric   tons)          
         Sector    Power    Industry    Commercial    Agriculture  Domestic
         2005      500      200        150           80     100
         2006       600      300        200           90    110
         2007       650      320        250          100    120
         2008       700      400        300          150    150
         2009      800      450        320          200    180

    ...view full instructions

    What is the percentage (%) growth of CO2 emissions from the power sector from 2005 to 2009?

    Solution

    Growth of CO2 from power sector during 2005 to 2009 = 800 - 500 = 300 (Just take values of 2009 and 2005 and subtract them)

     

  • Question 6
    1 / -0

    A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is:

    Solution

    Please remember that Maximum portability is 1.

    So we can get the total probability of non-defective bulbs and subtract it from 1 to get the total probability of defective bulbs.

     

  • Question 7
    1 / -0

    The first term of an Arithmetic Progression is 22 and the last term is −11. If the sum is 66 , the number of terms in the sequence are:

    Solution

     

  • Question 8
    1 / -0

    10 persons begin to work together on a job, but after some days, 4 persons leave. As a result, the job, which could have been completed in 40 days, was completed in 50 days. How many days after commencement of the work did the four persons leave?

    Solution

    Given:

    Number of persons = 4

    Initial time to complete the work = 40 days

    Final time to complete the work = 50 days

    Total work done = Number of persons × Time taken

    Total work = 10 × 40 = 400 units

    Let 4 persons leave after x days

    So, remaining persons will complete the work in (50 − x) days

    Total work = (10 × x) + 6(50 − x)

    = 10x + 300 − 6x

    = 4x + 300

    Now, according to question,

    400 = 4x + 300

    ⇒ 4x = 100

    ⇒ x = 25

    ∴ The four persons will leave after 25 days

     

  • Question 9
    1 / -0

    The following question is accompanied by two statements (I) and (II). You have to determine which statements(s) is/are sufficient/necessary to answer the questions.

    What is the rate of simple interest?

    I. The amount was invested for 8 years.

    II. The simple interest is half the investment.

    Solution

    From statement I and II we can find the value of rate of interest.

    ∴ Both the statements I and II together are needed to answer the question

     

  • Question 10
    1 / -0

    The marked price of an article is Rs. 400. After allowing a discount of 20% on the marked price, a shopkeeper makes a loss of Rs. 48. His loss percentage is:

    Solution

     

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