Logical Reasoning & DI (LRDI) Test

Result

Logical Reasoning & DI (LRDI) Test - 19

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Weekly Quiz Competition

Question 1
3 / -1

Directions For Questions

Directions: Read the given information carefully and answer the question that follows.

Mr. Brown, a shopkeeper, purchased eight bundles of magazines (bundle 1 to bundle 8). Each bundle contained a different number of magazines and he purchased each bundle at a different cost. He sold the magazines from these eight bundles over a period of six weeks, from week 1 to week 6, such that he first sold all the magazines from bundle 1, after which he sold all the magazines from the next bundle, i.e. bundle 2 and so on, until bundle 8. All the magazines that he sold in any week were sold at the same price, which however, was different for each of the six weeks. Further, for each magazine that he sold, CP of that magazine was calculated as the cost of the bundle which that magazine is from, divided by the number of magazines in that bundle.

The table below provides the number of magazines in each bundle and the price (in $) at which he purchased each bundle and the second table provides the number of magazines that he sold on each of the six weeks and the price (in $) per magazine on each week.

...view full instructions

Key in the number of the week in which Mr. Brown made the third highest percent of profit.

A
3

B
4

C
5

D
6

Solution

Total CP of magazines of week 1 = 54 × 7.5 + 88 × 8 = 1,109

Total CP of magazines of week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879

Total CP of magazines of week 3 = 72 × 6.5 + 36 × 7.75 = 747

Total CP of magazines of week 4 = 84 × 7.75 + 30 × 6 = 831

Total CP of magazines of week 5 = 66 × 6 + 42 × 6.52 = 669

Total CP of magazines of week 6 = 22 × 6.52 + 82 × 8.50 = 840

In week 3, Mr. Brown made the third highest percent of profit.

Hence, answer = 3
Question 2
3 / -1

Directions For Questions

Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:

Moreover, it is also known that:

(A) Each group won at least one round.

(B) G₁ lost the round against K₅, while G₄ lost against K₁.

...view full instructions

Which of the following groups drew the maximum number of rounds?

A
K₅

B
K₃

C
K₁

D
K₄

Solution

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄ and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂ having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅ each has 2 wins and 3 losses.

The table below presents this information:

Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K₃drew the most number of rounds.

Hence, option B is correct.
Question 3
3 / -1

Directions For Questions

Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:

Moreover, it is also known that:

(A) Each group won at least one round.

(B) G₁ lost the round against K₅, while G₄ lost against K₁.

...view full instructions

K₂ lost a round against which of the following groups

A
G₁

B
G₂

C
G₃

D
None of these

Solution

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅each has 2 wins and 3 losses.

The table below presents this information:

Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K₂ lost the rounds against G₁ and G₄.

Hence option A is correct.
Question 4
3 / -1

Directions For Questions

Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:

Moreover, it is also known that:

(A) Each group won at least one round.

(B) G₁ lost the round against K₅, while G₄ lost against K₁.

...view full instructions

The group that scored the least number of points won against which of the following groups?

A
K₁

B
K₄

C
K₅

D
Either K₁ or K₅

Solution

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅each has 2 wins and 3 losses.

The table below presents this information:

Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

The group that scored the least number of points is G₅. G₅ could have won against either K₁ or K₅.

Hence, option D is correct.
Question 5
3 / -1

Directions For Questions

Directions: Study the given information and answer the following question.

In a quiz competition, two academies - Alex Academy and Zed Academy - with five groups each competed against each other such that each group of an academy competed against all the five groups of the other academy exactly once. In any round, the winner was given three points, and the loser was awarded no points. In case of a draw, the two groups were awarded one point each.

The table below provides partial information about the wins, draws and losses of each group:

Moreover, it is also known that:

(A) Each group won at least one round.

(B) G₁ lost the round against K₅, while G₄ lost against K₁.

...view full instructions

The total number of rounds that K₄ lost was _________.

A
3

B
4

C
5

D
6

Solution

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅each has 2 wins and 3 losses.

Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K₄ lost three rounds.

Hence answer = 3
Question 6
3 / -1

Directions For Questions

Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:

1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.

2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.

3) Bonnie was a part of the Fierce Werewolves.

4) At any point of time, exactly one player, of either team, took possession of the ball.

...view full instructions

Which among the following is a part of Fierce Werewolves?

A
Alex

B
William

C
Sean

D
Rjay

Solution

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.

Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.

If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.

Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.

Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.

The following table represents the team.
Question 7
3 / -1

Directions For Questions

Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:

1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.

2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.

3) Bonnie was a part of the Fierce Werewolves.

4) At any point of time, exactly one player, of either team, took possession of the ball.

...view full instructions

Who scored the highest number of goals in Deadly Sharks?

A
Sean

B
Casey

C
Bonnie

D
Either Sean or Casey

Solution

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.

Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.

If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.

Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.

Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
Question 8
3 / -1

Directions For Questions

Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:

1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.

2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.

3) Bonnie was a part of the Fierce Werewolves.

4) At any point of time, exactly one player, of either team, took possession of the ball.

...view full instructions

Which of the following pairs of players belongs to the same team?

A
Michael and Harry

B
William and Rjay

C
Rjay and Jamie

D
Charlie and Jamie

Solution

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.

Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.

If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.

Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.

Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.

The following table represents the team.
Question 9
3 / -1

Directions For Questions

Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:

1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.

2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.

3) Bonnie was a part of the Fierce Werewolves.

4) At any point of time, exactly one player, of either team, took possession of the ball.

...view full instructions

If the title 'Player of the Game' was awarded to the player from the winning team who scored at least two goals and possessed the ball for the highest duration, who was awarded the Player of the Game?

A
Casey

B
Sean

C
Alex

D
Bonnie

Solution

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.

Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.

If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.

Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.

Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
Question 10
3 / -1

Directions For Questions

Directions: Study the following information and answer the question that follows.

Ten friends played Polo by splitting themselves into two teams of 5 players each namely Fierce Werewolves and Deadly Sharks. They played one game, which was for 90 minutes. During this time, the ball was in possession of a player from either of the teams. The following table provides the number of goals scored by each player and the duration (in minutes) for which the ball was in possession of each player.

Further information is given below:

1) Fierce Werewolves won the match by scoring one goal more than Deadly Sharks.

2) The possession time for Deadly Sharks was 10 minutes more than for Fierce Werewolves.

3) Bonnie was a part of the Fierce Werewolves.

4) At any point of time, exactly one player, of either team, took possession of the ball.

...view full instructions

The second least possession time of a player in the winning team is more or less than the same for a player in the losing team by _______ minutes.

A
2

B
8

C
3

D
7

Solution

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.

Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.

If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.

Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.

Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.

The following table represents the team.

The second least possession time, i.e. 3 minutes, is that of Charlie in "Fierce Werewolves", the winning team.

The second least possession time is that of Rjay, i.e. 10 minutes, in "Deadly Sharks", the losing team.

Thus, the possession time of Charlie in the winning team is less by 7 minutes.